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Re: Nairaland Mathematics Clinic by Nobody: 9:23pm On Jul 19, 2014 |
doubleDx: Yes boss am good. I dey see ur hand work here o. Keep it up. Respect 1 Like |
Re: Nairaland Mathematics Clinic by efficiencie(m): 6:30pm On Jul 20, 2014 |
masperano: Stennon how are you? and Jackpot why did u Thanks! I read Economics!! |
Re: Nairaland Mathematics Clinic by Nobody: 7:58pm On Jul 20, 2014 |
efficiencie: Economics!! That is stunning!! I am in awe. |
Re: Nairaland Mathematics Clinic by itunde(m): 3:04pm On Jul 21, 2014 |
Pls pals, help me with this questionn it is very urgent pls.................. If a,b,c,d>=0, show that (abcd)^1/4 <= (a+b+c+d)/4................ God bless us all and I salute evEryone here..................... |
Re: Nairaland Mathematics Clinic by efficiencie(m): 10:56pm On Jul 22, 2014 |
itunde: Pls pals, help me with this questionn it is very urgent pls.................. loading... |
Re: Nairaland Mathematics Clinic by efficiencie(m): 10:56pm On Jul 22, 2014 |
itunde: Pls pals, help me with this questionn it is very urgent pls.................. If a ≥0 ,b ≥0 ,c ≥0 ,d≥0, show that: (abcd)^(1/4) ≤ (a+b+c+d)/4 If a ≥0 ,b ≥0 ,c ≥0 ,d≥0 Then (√a - √b)^2 ≥ 0 a + b ≥ 2√ab (a + b)/2 ≥ (ab)^(1/2) ...1 similarly it can be argued that: (c + d)/2 ≥ (cd)^(1/2) ...2 And using d rule if x,y,u,v are non negative and x≥y and u≥v then xu≥yv Hence from 1 and 2 usin d abov rule: (a+b)(c+d)/4 ≥ (abcd)^(1/2) Apply d rule: If u≥v and u,v are non negativ then u^x≥v^x wen x≥0 Hence √((a+b)(c+d))/2 ≥ (abcd)^(1/4) (abcd)^(1/4) ≤ √((a+b)(c+d))/2 ...3 Using d rule: 2√uv ≤ u+v whr u,v are non negative and hence d RHS of inequality 3 is given as: √((a+b)(c+d))/2≤(a+b+c+d)/4 ...4 On apply d law of transitivity If u≤v and v≤w then u≤w Hence on combinin d results frm 3 n 4: (abcd)^(1/4) ≤ (a+b+c+d)/4 Quod Erat Demonstrandum 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 8:11pm On Jul 23, 2014 |
nice works generals . @ efficiencie i cn see your hand work... kudos bro.... |
Re: Nairaland Mathematics Clinic by Nobody: 8:36pm On Jul 23, 2014 |
jackpot: Sir, is that not a referrence to the centroid? not really . |
Re: Nairaland Mathematics Clinic by Nobody: 11:52pm On Jul 23, 2014 |
A ball when dropped from any given height loses 20 per cent of its previous height at each rebound. If it is dropped from a height of 40m, find how often it will rise to a height of over 8m. How far does the ball travel before coming to rest? try asap.. 1 Like |
Re: Nairaland Mathematics Clinic by dejt4u(m): 5:40am On Jul 24, 2014 |
benbuks: A ball when dropped fromthis is a series(GP) in this form: 40, 32, 25.6, . . .ar(1-n) Tn = ar(1-n), 1st term a = 40m, common ratio r = 0.8m, when Tn = 8, |
Re: Nairaland Mathematics Clinic by dejt4u(m): 5:57am On Jul 24, 2014 |
benbuks: find how often it will rise to a height of over 8m.7 approximate value benbuks: How far does the ball travel before coming to rest?the ball will bounce in 67times by my calculation b4 comin to rest, therefore, sum of the 67terms = approx. 200m |
Re: Nairaland Mathematics Clinic by sundaylinus: 3:18pm On Jul 24, 2014 |
help me with this once again. Sove By quadratic equation. If α and β are the roots of equation 3x²+5x-8=0. Find the value of α^4-ß^4 |
Re: Nairaland Mathematics Clinic by itunde(m): 5:03pm On Jul 24, 2014 |
efficiencie: @Lord efficiencie, Long live thee.......I do really appreciate U, though I still ve few other questions that requires solution, permitt me to send it................Maths is really fun |
Re: Nairaland Mathematics Clinic by Preasty: 5:19pm On Jul 24, 2014 |
2^x =8x.......solve this @ all abeg |
Re: Nairaland Mathematics Clinic by Nobody: 8:03pm On Jul 24, 2014 |
sundaylinus: help me with this once again. Sove By quadratic equation. If α and β are the roots of equation 3x²+5x-8=0. Find the value of α^4-ß^4 you should have used the idea they gave you earlier.. anyway leme use A & B as my alpha & beta respectively A^4 - B^4 =(A^2)^2 - (B^2)^2 ………………(N) => (A^ 2 -B^2) (A^2 +B^2 ) ............( E).....(Difference of two squares ) Now lets do some little derivation (A+B)^2 = A^2 +B^2 +2AB....................(W) => A^2 + B^2 = (A+B)^2 - 2AB ..............(T) & (A-B)^2 =A^2 +B^2 -2AB.................(O) =>A-B=√[(A+B)^2 -4AB ] ………… (M)..........( putting (T) .) thus A^4 - B ^4 = [ (A+B)^2 -2AB ] [(A+B) ] [√[(A+B)^2 -4AB ] ] NOW, GIVEN f(x) =3x^2 +5x -8 =0 sum , A+B= -5/3 product , AB = -8/3 => [(-5/3)] [√(121/9) ] [73/9] hence we -4015/81 . |
Re: Nairaland Mathematics Clinic by Kendzyma(m): 11:10pm On Jul 24, 2014 |
Kudos 2 u all..@ all my ogas..keep d fire burning.really learning frm u guys |
Re: Nairaland Mathematics Clinic by Nobody: 6:07pm On Jul 25, 2014 |
dejt4u: nice... |
Re: Nairaland Mathematics Clinic by Nobody: 7:21pm On Jul 26, 2014 |
Integrate:: Arctan([1-x]/[1+x]) |
Re: Nairaland Mathematics Clinic by Allenkee: 6:04pm On Jul 27, 2014 |
Please help me on this On an air Indian flight, there are 9 boys, 5 Indian children, 9 men, 7 Foreign boys, 14 Indian, 6 Indian males and 7 foreign females what is the number of people in the Plane? Please help. |
Re: Nairaland Mathematics Clinic by efficiencie(m): 11:10pm On Jul 27, 2014 |
benbuks: Integrate:: ∫arctan([1-x]/[1+x])dx = ∫arctan([tan(π(4n+1)/4)-tan(arctanx)]/[1+tan(π(4n+1)/4)tan(arctanx)])dx Where 'n' is any non-negative integer Hence = ∫arctan([tan(π(4n+1)/4)-tan(arctanx)]/[1+tan(π(4n+1)/4)tan(arctanx)])dx = ∫arctan(tan[π(4n+1)/4-arctanx])dx = ∫[π(4n+1)/4-arctanx])dx = π(4n+1)x/4-1/(1+x^2)+c |
Re: Nairaland Mathematics Clinic by Nobody: 11:53am On Jul 28, 2014 |
efficiencie: is that your final answer . .?? |
Re: Nairaland Mathematics Clinic by Nobody: 12:00pm On Jul 28, 2014 |
Allenkee: Please help me on this logical . brb.. |
Re: Nairaland Mathematics Clinic by efficiencie(m): 12:36pm On Jul 28, 2014 |
benbuks: or are u suggestin i try d audience, 50-50 or call a friend...infact let me phone JACKPOT!!! JACKPOT, hon, come to my aid o! |
Re: Nairaland Mathematics Clinic by Nobody: 12:58pm On Jul 28, 2014 |
efficiencie: hahaha......or u wanna walk away ..? well , the choice is yours ... an alternative solution could help . |
Re: Nairaland Mathematics Clinic by efficiencie(m): 2:03pm On Jul 28, 2014 |
Allenkee: n(b)=9 n(i n (b u g))=5 n(m)=9 n(i' n b)=7 n(i)=14 n(i n (b u m))=6 n(i' n b' n m')=7 By implicatn from d above we have d@: n(i n b)=2 n(i n m)=4 n(i n g)=3 n(i')-n(i' n (b u m))=n(i' n b' n m')=7 n(i')-n(i' n (b u m)=7 n(i')-n(i' n b)-n(i' n m)=7 n(i')-n(b)+n(i n b)-n(m)+n(i n m)=7 hence using d above info: n(i')=19 the total number persns on the plane equals n(i')+n(i)=19+14=33 |
Re: Nairaland Mathematics Clinic by PatEinstEin(m): 2:19pm On Jul 28, 2014 |
Allenkee: Please help me on this2 Indian boys + 4 Indian men + 7 foreign boys + 7 foreign females + 3 Indian girls + 5 Indian women + 5 foreign men = 33 people Total number of people in the plane is 33 To verify: the question says... 9 boys; which are: 2 Indian boys + 7 foreign boys 5 Indian children; which are: 2 Indian boys + 3 Indian girls 9 men; which are: 4 Indian men + 5 foreign men 7 Foreign boys; 14 Indian; which are: 2 Indian boys + 4 Indian men + 3 Indian girls + 5 Indian women 6 Indian males; which are: 2 Indian boys + 4 Indian men 7 foreign females Computer scientists or anyone that can help, pls help with this assignment: write a program in visual basic to calculate the compound interest payable in a premium for any number of years using a maximum of five tools or objects. Thanks. I'm a biochemistry student - 200 level, but computer science is compulsory for me Also, I would appreciate tutorials on Visual Basic Programming |
Re: Nairaland Mathematics Clinic by Nobody: 4:19pm On Jul 28, 2014 |
PatEinstEin: hnmm see boss abeg nice1 bro well, think i can assist . you nid d coding only or..? |
Re: Nairaland Mathematics Clinic by PatEinstEin(m): 4:45pm On Jul 28, 2014 |
benbuks:All of the above; I don't even know which is which |
Re: Nairaland Mathematics Clinic by Nobody: 5:40pm On Jul 28, 2014 |
PatEinstEin:ok bro.. but wait oo . how is the form of submission .? is it that you guys will present it using a p.c or how .? BTW: to get quick / expert's assistance on this , i suggest you forward to this to the programming section . |
Re: Nairaland Mathematics Clinic by PatEinstEin(m): 5:55pm On Jul 28, 2014 |
benbuks: ok bro..We are to write in pen and paper. I think it's d code...thanks... |
Re: Nairaland Mathematics Clinic by jackpot(f): 5:59pm On Jul 28, 2014 |
efficiencie:Sir, you called? Try differentiating your result, lets see will that pi go away eventually, to give us back the integrand? |
Re: Nairaland Mathematics Clinic by Nobody: 6:02pm On Jul 28, 2014 |
PatEinstEin:..ok. now ur talking ... will get bk.to u much later .. |
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