jackpot:
please, kindly show full workings.

ur own na 2 just dey post problems n tag people but u scarcely help others in solving dias

i could av post solutions to some of ur problems even if i av limited ideas cud av done all possible .

but feels lazy/discouraged to do so

Concerning that probability issue,
.
Three digit numbers will have unit's, ten's and hundred's place.

Out of 5 given digits any one can take the unit's place.

This can be done in 5 ways ------- (i)
After filling the unit's place, any of the four remaining digits can take the ten's place.
This can be done in 4 ways ------- (ii)
After filling in ten's place, hundred's place can be filled from any of the three remaining digits.
This can be done in 3 ways ------- (iii)
=> By counting principle, the number of 3 digit numbers =5×4×3= 60

when I did mine, I got 24/60. which is 2/5.

when I did mine, I got 24/60. which is 2/5.

chezholy:
when I did mine, I got 24/60.
which is 2/5.

Did you consider both multiple of 5, odd number and the formula for independent events?

Seamione:
Did you consider both multiple of 5, odd number and the formula for independent events?

I did.

chezholy:

I did.

Cool, that's what I also did

Seamione:
Cool, that's what I also did

Ya. That is it. *thumbs up*

personal59:


2) The function f is known to have a second derivative with the property that /f"(x)/ < 12
For x between 2 and 3. Using the error bound giving earlier in this section determine how many sub intervals are required so that the composite trapezieum rule used to approximate integral 5-2 f(x)dx


4) The function f is known to have a forth derivative with the property that f^(iv) (x)<6
For x between -1 and 5. Determine how many sub intervals are required so that the composite trapezium rule use to approximate integral 5 - (-2) f(x)dx incurs an error that is less than 0.001.

There is no error bound in question 2.

Question 4 looks... strange.
Usually the fourth derivative is used to calculate the error bound using Simpson's Rule, but it is required here to use the Trapezoid Rule.
Should I go ahead and use the formula for Simpson's Rule here?
Or is there something I'm missing.
AgentOfChange1, Can you help out?

jackpot:
please, kindly show full workings.

x^2/a^2+y^2/b^2 = 1
(assuming semimajor axis length a, semiminor axis length b, center (0, 0), and rotation angle 0°)

The center h, is given by:
(cd-bf)/(b^2 - ac )
The center k is given by:
(af -bd )/(b^2 -ac)

where d, f are gotten from the quadratic curve

a^2 -b^2 = c^2 where c is the focus on either side.

Sleepy....

Karmanaut:

There is no error bound in question 2.

Question 4 looks... strange.
Usually the fourth derivative is used to calculate the error bound using Simpson's Rule, but it is required here to use the Trapezoid Rule.
Should I go ahead and use the formula for Simpson's Rule here?
Or is there something I'm missing.
AgentOfChange1, Can you help out?

Ok pls can we assume error bound for question 2 so that wen I see one with error bound I will b able to solve it the exam is tomorrow thanks bro and also the question 4 is correct that's what the question state

agentofchange1:


ur own na 2 just dey post problems n tag people but u scarcely help others in solving dias

i could av post solutions to some of ur problems even if i av limited ideas cud av done all possible .

but feels lazy/discouraged to do so

ok. Thank God you said scarcely, not completely. My time here is somehow irregular. Most of the times, I come to see new questions and solutions. If I see an unsolved one that is not too trivial and interests me, then I'll go for it. Questions like Perm and Combination, simultaneous solution of 4^x+6^y=100 and x+y=5 do not interest me.

Some of the questions that I post is for others to learn. Under normal circumstances, elementary university maths treat conic sections at the surface level. That question requires knowledge of rotation of axes. You'll agree with me that sometimes we do have an unnecessarily long solution. In other words, i'm looking for shorter solutions, that is why I seek for other people's POV.

Don't feel that you're doing me a favour by solving the question. It is not about me. Other peoples are learning too. Gracias.

Karmanaut:


x^2/a^2+y^2/b^2 = 1
(assuming semimajor axis length a, semiminor axis length b, center (0, 0), and rotation angle 0°)

The center h, is given by:
(cd-bf)/(b^2 - ac )
The center k is given by:
(af -bd )/(b^2 -ac)

where d, f are gotten from the quadratic curve

a^2 -b^2 = c^2 where c is the focus on either side.

Sleepy....

ok, it is after 8 already.

Brother, wake up wake up wake up

jackpot:
ok. Thank God you said scarcely, not completely. My time here is somehow irregular. Most of the times, I come to see new questions and solutions. If I see an unsolved one that is not too trivial and interests me, then I'll go for it. Questions like Perm and Combination, simultaneous solution of 4^x+6^y=100 and x+y=5 do not interest me.

Some of the questions that I post is for others to learn. Under normal circumstances, elementary university maths treat conic sections at the surface level. That question requires knowledge of rotation of axes. You'll agree with me that sometimes we do have an unnecessarily long solution. In other words, i'm looking for shorter solutions, that is why I seek for other people's POV.

Don't feel that you're doing me a favour by solving the question. It is not about me. Other people are learning too. Gracias.

Aright dear i get your point,


BTW: look into that probability question i solved in the previous page , your honest mathematical input is required. tnx.

agentofchange1:


Aright dear i get your point,


BTW: look into that probability question i solved in the previous page , your honest mathematical input is required. tnx.

Pls bro can u help out on the question I post a page before this karmanaut he said he his aving problem with question 4 and call on u to help out he also include question two but I ask him to assume the error bound value so that I will b able to sove it wen eventually given in d exam thanks in anticipation

personal59:



Ok pls can we assume error bound for question 2 so that wen I see one with error bound I will b able to solve it the exam is tomorrow thanks bro and also the question 4 is correct that's what the question state

That's the General formula for error bound using trapezoid rule.

personal59:



Pls bro can u help out on the question I post a page before this karmanaut he said he his aving problem with question 4 and call on u to help out he also include question two but I ask him to assume the error bound value so that I will b able to sove it wen eventually given in d exam thanks in anticipation

guess he has done it already.

boss karmanaut , great works sir
kindly look into that probability question on the previous page
good day.

agentofchange1:


guess he has done it already.

He did 1 and 3 But he said he doesnot understand question 4 especially how to go about solving it and he said question 2 does not have error bound so I said he should assume an error bound so that I will be able to solve if eventually given in exam with error bound too


So pls can u help me sove question 2 using an assumed error bound and also question 4.

Thanks

agentofchange1:
boss karmanaut , great works sir
kindly look into that probability question on the previous page
good day.

I can't be of help, sir. Combinatorics and Probability are not my forte.

agentofchange1:


Aright dear i get your point,


BTW: look into that probability question i solved in the previous page , your honest mathematical input is required. tnx.

that question is the same as ''probability that it is an odd number.'' probability= event occurence/sample space.


We have three boxes to be filled with the figures 1,2,4,5,6 without replacement. The last box only has 2 choices 1 and 5.
So, if the last box is 1, then we feed the other two boxes with 4 figures. No of ways this can be done is 4P2=12
Occurence= 4P2*2=24.
Sample space is 5P3=60

probability = 24/60=2/5.

Hmmmmmmmm. Someone should correct me, please.

personal59:



He did 1 and 3 But he said he doesnot understand question 4 especially how to go about solving it and he said question 2 does not have error bound so I said he should assume an error bound so that I will be able to solve if eventually given in exam with error bound too


So pls can u help me sove question 2 using an assumed error bound and also question 4.

Thanks

ok sir

we gat basically two types of errors when using trapezoidal rule

local error ,

e = -1/12 *h^3 f' ' '(α) : x₁<α<x₂

&
Global error ,

e= -1/12 * n f' ' ' (α) : x₁<α<x_n


guess this helps





brb leme recheck the question behind.

agentofchange1:


ok sir

we gat basically two types of errors when using trapezoidal rule

local error ,

e = -1/12 *h^3 f' ' '(α) : x₁<α<x₂

&
Global error ,

e= -1/12 * n f' ' ' (α) : x₁<α<x_n


guess this helps

You used the third derivative?
Isn't it the second derivative for the trapezoid rule and the fourth derivative for Simpson's rule?

Karmanaut:


You used the third derivative?
Isn't it the second derivative for the trapezoid rule and the fourth derivative for Simpson's rule?

no bro,

that's it, wanna see the proof. ?

agentofchange1:


ok sir

we gat basically two types of errors when using trapezoidal rule

local error ,

e = -1/12 *h^3 f' ' '(α) : x₁<α<x₂

&
Global error ,

e= -1/12 * n f' ' ' (α) : x₁<α<x_n


guess this helps





brb leme recheck the question behind.

Thanks bros I need explanation and solution because I don't know it at all the man just drop the question at the last class of d semester saying we can't treat the topic cos we ran out of time saying go and solve this with. The topic we af treated atleast this will do

agentofchange1:


ok sir

we gat basically two types of errors when using trapezoidal rule

local error ,

e = -1/12 *h^3 f' ' '(α) : x₁<α<x₂

&
Global error ,

e= -1/12 * n f' ' ' (α) : x₁<α<x_n


guess this helps





brb leme recheck the question behind.

Thanks bros I need explanation and solution because I don't know it at all the man just drop the question at the last class of d semester saying we can't treat the topic cos we ran out of time saying go and solve this with. The topic we af treated atleast this will do


I possible bro u can help me write it and snap like dividing in 4places and post so I will b able to read

@personal59

www.google.com.ng/search?q=numerical+integration&client=ms-opera-mini-android&channel=new&gws_rd=cr&ei=HEXfVYzPJoX7aN_XmcgM

click on the site above n download d e copy, it really helps, u could understand well enough questions related to yours, seeing d exams is 2maro.


i don't wanna bring new formulas dat cud cause confusion,

leme advice u to just study ur notes carefully n all tests /assignments. u can't get all solutions from us here, at least my boss has done justice to some of ur problem.

this is how i could help on this


hope u get my gist..

agentofchange1:
@personal59

www.google.com.ng/search?q=numerical+integration&client=ms-opera-mini-android&channel=new&gws_rd=cr&ei=HEXfVYzPJoX7aN_XmcgM

click on the site above n download d e copy, it really helps, u could understand well enough questions related to yours, seeing d exams is 2maro.


i don't wanna bring new formulas dat cud cause confusion,

leme advice u to just study ur notes carefully n all tests /assignments. u can't get all solutions from us here, at least my boss has done justice to some of ur problem.

this is how i could help on this


hope u get my gist..

Thanks bro I do but it can't compound it cos I know other topics very well they are variable seperable, homogeneous, exact, all ODE so I know those ones very well so I just want to solve this four, know it and do it all who know what his compulsory question would be so I need to play safe too. But for other topics I av no problem with them

Just help me to solve the question I would b able to comprehend it

jackpot:
that question is the same as ''probability that it is an odd number.'' probability= event occurence/sample space.


We have three boxes to be filled with the figures 1,2,4,5,6 without replacement. The last box only has 2 choices 1 and 5.
So, if the last box is 1, then we feed the other two boxes with 4 figures. No of ways this can be done is 4P2=12
Occurence= 4P2*2=24.
Sample space is 5P3=60

probability = 24/60=2/5.

Hmmmmmmmm. Someone should correct me, please.

You're absolutely correct and on point madam

personal59:

Thanks bro I do but it can't compound it cos I know other topics very well they are variable seperable, homogeneous, exact, all ODE so I know those ones very well so I just want to solve this four, know it and do it all who know what his compulsory question would be so I need to play safe too. But for other topics I av no problem with them
Just help me to solve the question I would b able to comprehend it

my left mind is wishing the guy drops Laplace Transform as the compulsory question

Seamione:
You're absolutely correct and on point madam

wow. I'm not always sure of this topic.

Seriously, na just brain I dey use answer Permutation and Combination problems. I dislike questions that I gaze for like 10 mins before attempting the solution. I prefer to start putting something down the first minute I look at the question, even if it will take me 30mins to solve. I call it Solution Assured.

agentofchange1:


c'mmon bro, the question says no repetition

5C3 means total number of ways we could form the 3-digit number without repetition

421 (124) ,521(125) , 621( 126) already exist in the sample space.

Let me follow your argument to see if it holds water:
you gave your sample space as
S={(124),(125),(126),(245),(246),(145),
(156),(645),(641),(265)}.

Following your logic,
S={(124),(512),(126),(524),(246),(514),(156),(564),(164),(526)} because, for instance, 125 and 512 are the same numbers without repetition (whatever that means).

So, probability = 0/10=0.

Contradiction!

Class dismiss. Everybody go home.