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Re: Nairaland Mathematics Clinic by saipn: 8:30am On Nov 21, 2015
Pls gurus in the house help me to solve this SET world problem
1)In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither?
2)In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics?
3)In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport?
Re: Nairaland Mathematics Clinic by dprinz99(m): 8:32am On Nov 21, 2015
I must comend u guys first for this grt work.
I'm new on this thread and I think God hs Brot me to d ryt plc.
my story goes dis way,

while in sec school,I thought I will study medical course as such wouldn't need much maths.i wasn't interested in math anymore.
I dropped futhermath in my ss2 even thou I was abv average.
as life changes,I now hv opportunity to go abroad for studies(which God hs done).and the course I want to pursue now requires excellent knowledge of maths(aerospace engr).
aldo I'm NT doom in math's,Bt I must confess DAT my math knowledge is not up to DAT.
I jus hav four month to d begin in of my course,I hv started self study.n I must admit DAT I hv already seen d changes,Bt I want to b more than a GURU in math's.

my question is,how can I become overgud in math's?
what r d steps?
what must I do?
thankx
Re: Nairaland Mathematics Clinic by petengine(m): 9:06am On Nov 21, 2015
dprinz99:
I must comend u guys first for this grt work.
I'm new on this thread and I think God hs Brot me to d ryt plc.
my story goes dis way,

while in sec school,I thought I will study medical course as such wouldn't need much maths.i wasn't interested in math anymore.
I dropped futhermath in my ss2 even thou I was abv average.
as life changes,I now hv opportunity to go abroad for studies(which God hs done).and the course I want to pursue now requires excellent knowledge of maths(aerospace engr).
aldo I'm NT doom in math's,Bt I must confess DAT my math knowledge is not up to DAT.
I jus hav four month to d begin in of my course,I hv started self study.n I must admit DAT I hv already seen d changes,Bt I want to b more than a GURU in math's.

my question is,how can I become overgud in math's?
what r d steps?
what must I do?
thankx
it requires constant practice. "practice makes perfect". first start with the known (simple ones) then advance to the unknown (difficult ones). don't feel discourage if u don't get the practice questions right at first. my favorite quote then I was "if u leave maths for one day, maths will leave u for 1 week" so keep on practicing till u become morn than a guru in maths.

cc: MathsChic, et al.
Re: Nairaland Mathematics Clinic by dprinz99(m): 9:21am On Nov 21, 2015
saipn:
Pls gurus in the house help me to solve this SET world problem
1)In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither?
2)In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics?
3)In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport?

. (1)
35:::19plus12plus x
35:::31plus x
x::::35-31
x::::4

therefore,4 student take neither
Re: Nairaland Mathematics Clinic by dprinz99(m): 9:24am On Nov 21, 2015
petengine:

it requires constant practice. "practice makes perfect". first start with the known (simple ones) then advance to the unknown (difficult ones). don't feel discourage if u don't get the practice questions right at first. my favorite quote then I was "if u leave maths for one day, maths will leave u for 1 week" so keep on practicing till u become morn than a guru in maths.

cc: MathsChic, et al.

I'm grateful bro
Re: Nairaland Mathematics Clinic by Mathemagician1(m): 9:40am On Nov 21, 2015
saipn:
Pls gurus in the house help me to solve this SET world problem
1)In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither?
2)In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics?
3)In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport?

(1) In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither?
‎
Solution:

Total students = 35
History student = 19
Economics students = 12
Students taking both courses = 5‎
‎
Economics = (12 - 5)= 7
History = (19 - 5) = 14‎
Neither = 35 - ( 14 + 7 + 5) = 9

(2) ‎In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics?

Solution:

Total students = 36
Mathematics students = 29
Chemistry students = 20
Neither = 5
‎
Both = ((29 - x) + (20 - x) + x + 5) - 36 = 18
Chemistry = 20 - 18 = 2

(3) In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport?

Solution:

‎Total students = 750‎
Total Sport student = 559‎
Girls population = 320
Boys population = (750 - 320) = 430‎
Non-sport activity girls = 101‎

Sports active girls = (320 - 101) = 219
Sports active boys = (559 - 219) = 340
Non-sport activity boys = (430 - 340) = 90‎
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 11:08am On Nov 21, 2015
saipn:
Pls gurus in the house help me to solve this SET world problem
1)In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither?
2)In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics?
3)In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport?
1)
35=(19-5)+(12-5)+5+x
35=14+7+5+x
35-26=x
X=9
2)
36=(29-x)+(20-x)+x+5
36=54-x
36-54=-x
-18=-x
X=18
thus chemistry only gives 20-18=2
3)solved already by mathemagician1
Re: Nairaland Mathematics Clinic by stlaibrowne(m): 2:26pm On Nov 21, 2015
Mathemagician1:

(1) In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither?
‎
Solution:
Total students = 35
History student = 19
Economics students = 12
Students taking both courses = 5‎
‎
Economics = (12 - 5)= 7
History = (19 - 5) = 14‎
Neither = 35 - ( 14 + 7 + 5) = 9
(2) ‎In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics?
Solution:
Total students = 36
Mathematics students = 29
Chemistry students = 20
Neither = 5
‎
Both = (29 + 20) - (36 - 5) = 8
Chemistry = 20 - 8 = 12
(3) In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport?
Solution:
‎Total students = 750‎
Total Sport student = 559‎
Girls population = 320
Boys population = (750 - 320) = 430‎
Non-sport activity girls = 101‎
Sports active girls = (320 - 101) = 219
Sports active boys = (559 - 219) = 340
Non-sport activity boys = (430 - 340) = 90‎
saipn:
Pls gurus in the house help me to solve this SET world problem
1)In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither?
2)In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics?
3)In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport?
The solutions of question 2 above is all wrong. The question is chemistry only

Re: Nairaland Mathematics Clinic by ladokuntlad(m): 3:32pm On Nov 21, 2015
stlaibrowne:
The solutions of question 2 above is all wrong. The question is chemistry only
i got mine naa
Re: Nairaland Mathematics Clinic by stlaibrowne(m): 4:28pm On Nov 21, 2015
ladokuntlad:

i got mine naa

Oh yes boss the other two foul foul foul
Re: Nairaland Mathematics Clinic by Mathemagician1(m): 5:15pm On Nov 21, 2015
stlaibrowne:


Oh yes boss the other two foul foul foul

grin my set is becoming rusty. Nice work ladokuntla and stlaibrowne
Re: Nairaland Mathematics Clinic by dprinz99(m): 6:16pm On Nov 21, 2015
1/3plus(5/7(9/10-1plus3/4))
its fraction.
I hv tried by stil no ryt anxa
plx help
Re: Nairaland Mathematics Clinic by Mathemagician1(m): 6:34pm On Nov 21, 2015
dprinz99:
1/3plus(5/7(9/10-1plus3/4))
its fraction.
I hv tried by stil no ryt anxa
plx help

1/3 + ( 5/7 ( 9/10 - 1 + 3/4 ))‎
Using BODMAS‎
1/3 + ( 5/7 ( 9/10 - 1/4 ))‎
1/3 + ( 5/7 ( 13/20 ))
1/3 + ( 13/28)
1/3 + 13/28
= 67/84‎
Re: Nairaland Mathematics Clinic by seuntosyn: 11:45pm On Nov 21, 2015
Help solve this (3/4 --2/5) - 1/3 of 3/10 all divided by 2 -- (1/1 3/7) moreso i want sir to teach me sets
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 12:46am On Nov 22, 2015
.
Re: Nairaland Mathematics Clinic by seuntosyn: 6:42am On Nov 22, 2015
[quote author=ladokuntlad post=40275175] is it like dis? NOPE
(3/4-(-2/5))-1/3 of 3/10 all dived by (2-(-1/(1 3/7)) ) i made a mistake when typing is like this (3/4 - 2/5) - 1/3 of 3/10 all divided by 2 - (1/1 3/7)
Re: Nairaland Mathematics Clinic by dprinz99(m): 6:46am On Nov 22, 2015
Mathemagician1:


1/3 + ( 5/7 ( 9/10 - 1 + 3/4 ))‎
Using BODMAS‎
1/3 + ( 5/7 ( 9/10 - 1/4 ))‎
1/3 + ( 5/7 ( 13/20 ))
1/3 + ( 13/28)
1/3 + 13/28
= 67/84‎
I got that Bt its NT the ryt ansa ooo
Re: Nairaland Mathematics Clinic by jackpot(f): 6:47am On Nov 22, 2015
Simplify as much as possible logca * logcb
Re: Nairaland Mathematics Clinic by Madmathecian(m): 7:31am On Nov 22, 2015
dprinz99:
I got that Bt its NT the ryt ansa ooo
67/27?
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 8:17am On Nov 22, 2015
jackpot:
Simplify as much as possible

logca * logcb
check ur question again.
because dis has already been simplified.
maybe dia ought to b a little modification in yaa log

except u looking for dis

logca * logcb= logc(a+b)
wich is very wrong
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 8:21am On Nov 22, 2015
seuntosyn:
i made a mistake when typing is like this (3/4 - 2/5) - 1/3 of 3/10 all divided by 2 - (1/1 3/7)

((3/4-(2/5))-(1/3x3/10))/(2-(1/(1 3/7)) )

((3/4-2/5)-(1/10))/(2-(1/(10/7)) )

(7/20-1/10)/(2-7/10)
(5/20)/(13/10)
=5/20 x 10/13
=5/26

According to ur new question
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 8:28am On Nov 22, 2015
dprinz99:

I got that Bt its NT the ryt ansa ooo
then d mistake is from the way u typed d question.
Try tak a snapshot of the question and upload it here
Re: Nairaland Mathematics Clinic by jackpot(f): 2:24pm On Nov 22, 2015
ladokuntlad:
check ur question again. because dis has already been simplified. maybe dia ought to b a little modification in yaa log
except u looking for dis logca * logcb= logc(a+b) wich is very wrong
okay.
What of the following:

Simplify as much as possible: (logc a) / (logcb)
Re: Nairaland Mathematics Clinic by stlaibrowne(m): 2:27pm On Nov 22, 2015
jackpot:
okay.

What of the following:


Simplify as much as possible: (logc a) / (logcb)

Logc(a-b)
Re: Nairaland Mathematics Clinic by thankyouJesus(m): 4:05pm On Nov 22, 2015
jackpot:
Simplify as much as possible

logca * logcb
[logalogb]/[logclogc]
jackpot:
okay.
What of the following:
Simplify as much as possible: (logc a) / (logcb)
loga base b
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 5:07pm On Nov 22, 2015
jackpot:
okay.

What of the following:


Simplify as much as possible: (logc a) / (logcb)

(logc a) / (logcb)
=(loga/logc)/(logb/logc)
=(loga/logc)*(logc/logb)
=(loga/logc)*(logc/logb)
=loga/logb
=logb a
QED
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 5:08pm On Nov 22, 2015
stlaibrowne:


Logc(a-b)
Wrong.
try insert a value and c for ursef.
no such rule exist
Re: Nairaland Mathematics Clinic by jackpot(f): 6:50pm On Nov 22, 2015
thankyouJesus:
[logalogb]/[logclogc]loga base b
kudos to you and ladokuntlad
Re: Nairaland Mathematics Clinic by saipn: 7:40pm On Nov 22, 2015
stlaibrowne:
The solutions of question 2 above is all wrong. The question is chemistry only
thanks bro
Re: Nairaland Mathematics Clinic by saipn: 7:42pm On Nov 22, 2015
ladokuntlad:
1) 35=(19-5)+(12-5)+5+x 35=14+7+5+x 35-26=x X=9 2) 36=(29-x)+(20-x)+x+5 36=54-x 36-54=-x -18=-x X=18 thus chemistry only gives 20-18=2 3)solved already by mathemagician1
thanks ladokuntlad
Re: Nairaland Mathematics Clinic by saipn: 7:42pm On Nov 22, 2015
ladokuntlad:
1) 35=(19-5)+(12-5)+5+x 35=14+7+5+x 35-26=x X=9 2) 36=(29-x)+(20-x)+x+5 36=54-x 36-54=-x -18=-x X=18 thus chemistry only gives 20-18=2 3)solved already by mathemagician1
thanks ladokuntlad
Re: Nairaland Mathematics Clinic by saipn: 7:44pm On Nov 22, 2015
Mathemagician1:


(1) In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither?
‎
Solution:

Total students = 35
History student = 19
Economics students = 12
Students taking both courses = 5‎
‎
Economics = (12 - 5)= 7
History = (19 - 5) = 14‎
Neither = 35 - ( 14 + 7 + 5) = 9

(2) ‎In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics?

Solution:

Total students = 36
Mathematics students = 29
Chemistry students = 20
Neither = 5
‎
Both = ((29 - x) + (20 - x) + x + 5) - 36 = 18
Chemistry = 20 - 18 = 2

(3) In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport?

Solution:

‎Total students = 750‎
Total Sport student = 559‎
Girls population = 320
Boys population = (750 - 320) = 430‎
Non-sport activity girls = 101‎

Sports active girls = (320 - 101) = 219
Sports active boys = (559 - 219) = 340
Non-sport activity boys = (430 - 340) = 90‎
thanks mathematicians

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