Are
You
A
Genius
Prove
That
20/10=10
Lets Know How Good Your IQ is!

Well I was TAUGHT 20\10 is 2. THAINX.

dont lie in the head of your teacher.

postulate321: Are
You
A
Genius
Prove
That
20/10=10
Lets Know How Good Your IQ is!

Make i try!!!!
Since 20/10=10 [equation 1]
Then 20=10*10 .... 20=100
since 20 is equal to 100, we substitute for 20 in [equation 1]
100/10=10....
All ye math gurus,make una no crucify me..Na my own one kobo be dat ohhh..

Oh Mathematics, full of manipulations! cries the mortal soul.

See lie@kslip... Your manipulation is not mathematical atall!

See Lie@kslip. Your manipulation is not mathematical atal

nke001: Oh Mathematics, full of manipulations! cries the mortal soul.

postulate321: See Lie@kslip. Your manipulation is not mathematical atal

nke001: Oh Mathematics, full of manipulations! cries the mortal soul.

Lmao!! Make una no blame me nah.. Nah my fault say i no sabi maths.. Oya make i try another method...

ok lets see the other method of yours

20/10 = 10. I doubt that this has a solution, so I'll do something crazy.

Left hand side = LHS, Right hand side = RHS.

case 1:
assume that numerator on the LHS in in decimal, denominator on the LHS is in binary (2 in decimal is 10 in binary). Finally the RHS is in decimal. Here's you answer, converting the denominator from binary to decimal, 20(decimal)/10(binary) = 10(decimal)
=> 20(decimal)/2(decimal) = 10(decimal).

case 2:
assume that the numerator on the LHS is in decimal, denominator on the LHS is in decimal, and the right hand side is in binary.
20(decimal)/10(decimal) = 2(decimal) => 20(decimal)/10(decimal) = 10(binary).

20/10=10
@op u no wise at all
using d roman numerals:
20=XX, while 10=X
using the above derivatives
XX/X= X

X=10,

I'M VERY SURE, THAT I'M RIGHT!!
@op, Prove me wrong

u are very correct man@jovie kudos to u

postulate321: u are very correct man@jovie kudos to u

thankz man, i learnt dat trick back then in SS 1. ......

postulate321: Are
You
A
Genius
Prove
That
20/10=10
Lets Know How Good Your IQ is!

better idea!
20/10=10

only when 10(denumerator)=2,

To prove dat 10=2;
let a=5 and b=5,
a+b=10.........(eqn1)
a-b = 0..........(eqn2),

from eqn2,
a-b=0,
add a-b to both sides,
(a-b)+(a-b)=0+(a-b),
2(a-b)=a-b
2=(a-b)/(a-b)
2=1.......(eqn3)*,

Also,
multiply eqn1 by eqn2,
(a+b)(a-b)=10*0=0,
since (a+b)(a-b)=0 which is equivalent to eqn2,
since eqn2=0 i.e a-b=0
therefore; (a+b)(a-b)= (a-b),
divide both sides by (a-b),
((a+b)(a-b))/(a-b) = (a-b)/(a-b),
a+b=1,

also frm eqn 3, 2=1
therefore,a+b is equal to 2, a+b=2,
now subtitution for a and b,
a=5, b=5 remember,
a+b=2,
5+5=2,
10=2.

Back to d question;
20/10=20/2=10(since 10=2).

QED