doubleDx:

Solution

-12a² x /-8a² b²

=> This is easy seeing as -4a² is a factor of the numerator and denomitor, cancelling out & reducing the expression to =>

For the numerator => -12a²/-4a² = 3x
For the denomitor => -8a² b²/-4a² = 2b²

Putting the simplified numerator and denomitor together yields =>

=> 3x/2b²

Thanks

Ortarico, doubledx and calculus all i can say is WoW! To me, you guies are an incentive to learning mathematics.

Omosivie,:
Guys pls help me multiply 34 and 5 in base 5

It's all the same steps as if it were in base 10, you just have to keep things all in base 5 the whole way through:

. . . .3 4
x. . . . 5₅

The first thing you do is 4 x 5 which is 20 in base 10, but in base 5 it's 40 (4*5= 20, 0*1= 0, 20 + 0= 20)

So drop the 0 from the ones down and carry the 4 from fives:

. . . . .4
. . . . .3 4
x. . . . 5₅
. . . . . . 0 . . .

Now do 5 x 3 which is 15 in base 10, but in base 5, it's 30. But add 4 to that since it's carried over from the last product and you get 19 in base 10 or 34 in base 5. So now we have:

. . . . .3
. . . . .3 4
x. . . . . .5₅
. . . . . . . . . . . .
. . . . .3 4 0. . .

And your answer is 340₅. . . . Hope this helped?

Ortarico:

It's all the same steps as if it were in base 10, you just have to keep things all in base 5 the whole way through:

. . . .3 4
x. . . . 5₅

The first thing you do is 4 x 5 which is 20 in base 10, but in base 5 it's 40 (4*5= 20, 0*1= 0, 20 + 0= 20)

So drop the 0 from the ones down and carry the 4 from fives:

. . . . .4
. . . . .3 4
x. . . . 5₅
. . . . . . 0 . . .

Now do 5 x 3 which is 15 in base 10, but in base 5, it's 30. But add 4 to that since it's carried over from the last product and you get 19 in base 10 or 34 in base 5. So now we have:

. . . . .3
. . . . .3 4
x. . . . . .5₅
. . . . . . . . . . . .
. . . . .3 4 0. . .

And your answer is 340₅. . . . Hope this helped?

Thanks, it helped. The question is actually : A housewife bought 5yams at W34 per yam and 3 oranges at W5 each where W is the currency reckoned in base six. The total amount spent by the house wife is
A W225(base six)
B W252(base six)
C W315(base six)
D W352(base six).

Omosivie,:
Thanks, it helped. The question is actually : A housewife bought 5yams at W34 per yam and 3 oranges at W5 each where W is the currency reckoned in base six. The total amount spent by the house wife is
A W225(base six)
B W252(base six)
C W315(base six)
D W352(base six).

All right, here we go:
NB: We're bound to do all in base 6

Now, we're multiplying W34₆ by 5 and W3₆ by 5 and thereafter adding the the amount of both to arrive at the total amount paid.

Multiplying 5 yams at W34₆ each:
following the steps I gave you, you'll arrive at W302₆.

Multiplying 5 oranges by W3₆ you'll arrive at W23₆

:. Adding both amount in base 6 carefully
Tot amount= W302₆ + W23₆
Tot amount= W325₆. . . .Answer
I can't find that in the options, maybe you made a typo error, please check it well especially option D

Ortarico:

All right, here we go:
NB: We're bound to do all in base 6

Now, we're multiplying W34₆ by 5 and W3₆ by 5 and thereafter adding the the amount of both to arrive at the total amount paid.

Multiplying 5 yams at W34₆ each:
following the steps I gave you, you'll arrive at W302₆.

Multiplying 5 oranges by W3₆ you'll arrive at W23₆

:. Adding both amount in base 6 carefully
Tot amount= W302₆ + W23₆
Tot amount= W325₆. . . .Answer
I can't find that in the options, maybe you made a typo error, please check it well especially option D

Nope, there's no typographical error. That's how it's written in my textbook. Thanks

Omosivie,:
Nope, there's no typographical error. That's how it's written in my textbook. Thanks

Well that's the solution I can provide on that. what's the answer in your textbook?

Ortarico:

Well that's the solution I can provide on that. what's the answer in your textbook?

315(base six). According to the textbook: 34(base six) X 5(base six) is 252(base six). I don't know how they came about the 252(base six).

Omosivie,:
315(base six). According to the textbook: 34(base six) X 5(base six) is 252(base six). I don't know how they came about the 252(base six).

All right sis. May I know the textbook?

Ortarico:

All right sis. May I know the textbook?

Lamlad Maths text book

Omosivie,:
Lamlad Maths text book

Hmmn. . .i've heard of the book before but haven't seen it. I doubt it's authenticity, maybe another person here should try helping.

.

Ortarico:

Hmmn. . .i've heard of the book before but haven't seen it. I doubt it's authenticity, maybe another person here should try helping.

Oh!!!!!! Someone told me that it's d best, that's why i bought it sha. Pls i'm having a little problem with mensuration, circles, bearing and lines. Can u help me out with them cos i don't understand them @ all. Are u on 2go?

Omosivie,:
Oh!!!!!! Someone told me that it's d best, that's why i bought it sha. Pls i'm having a little problem with mensuration, circles, bearing and lines. Can u help me out with them cos i don't understand them @ all. Are u on 2go?

...well lamlad is a good textbook...but it won't treat the topic at all...he will just write formulae and go to questions...but i love his questions and the way it's being solved...

Omosivie,:
Oh!!!!!! Someone told me that it's d best, that's why i bought it sha. Pls i'm having a little problem with mensuration, circles, bearing and lines. Can u help me out with them cos i don't understand them @ all. Are u on 2go?

Yes I am. You can add me with 'oketunde2' and/or my boss; calculusf(x) with 'mathemagician'.

Calculusf(x):
...well lamlad is a good textbook...but it won't treat the topic at all...he will just write formulae and go to questions...but i love his questions and the way it's being solved...

I've seen Comprehensive maths, Basic Mathematics for social management sciences(University book), New general maths and Lamlad maths. Up till now, i still don't know maths. My case is a pathetic one.

Ortarico:

Yes I am. You can add me with 'oketunde2' and/or my boss; calculusf(x) with 'mathemagician'.

Thanks, i'll add u both now

Lamlad z a gud textbook...i use it nd it has helped me alot,their questions r very technical,if u cnt think u wouldnt be able 2 solve it...ur case z nt pathetic @ omosive..all u have 2 do z practise....@calculux,otarico nd double(dx) u guys r gifted

koliks: Lamlad z a gud textbook...i use it nd it has helped me alot,their questions r very technical,if u cnt think u wouldnt be able 2 solve it...ur case z nt pathetic @ omosive..all u have 2 do z practise....@calculux,otarico nd double(dx) u guys r gifted

Thanks but i can be very very lazy when it comes to thinking mathematically but i'll keep on practising

Omosivie,:
Thanks but i can be very very lazy when it comes to thinking mathematically but i'll keep on practising

owk....maths z d simplest subject ever.....u just have 2 knw d principles behind every topic nd knw ur formulae d@s all u need....take it 4rm me,i was 1ce in ur shoes

Please who can integrate these derivatives:
integrate tanxdx

integrate 1/_/(x - 2)^2 + 25dx
i hope it is comprehensible.

Zico0: Please who can integrate these derivatives:
integrate tanxdx

integrate 1/_/(x - 2)^2 + 25dx
i hope it is comprehensible.

1. NB: $ denotes integral
$ tanx dx= $ sinx/cosx dx
u= cosx then we find du= -sinx dx
substitute du= -sinx, u= cosx.
$ sinx/cosx dx= - $ (-1) sinx dx/cosx
=> - $ du/u
solve the integral:
=> -In|u| + c
substitute back:
u= cosx
=> -In|cosx| + c
OR
$ tanx dx= -In|cosx| + c
=> In|(cosx)^-1| + c
=> In|secx| + c
Therefore:
$ tanx dx= -In|cosx| + c
=> In|secx| + c

2. Loading. . .

Zico0: Please who can integrate these derivatives:
integrate tanxdx

integrate 1/_/(x - 2)^2 + 25dx
i hope it is comprehensible.

...kudos to my oga at the top(ortarico) for number one...2...integral dx/sqrt(x-2)^2 +25...using the principle of hyperbolic functions...{1/sqrt x^2-a^2 will attract cosh,1/sqrtx^2+a^2 will attract sinh,1/sqrta^2-x^2 will attract sin}...so from those standard integral...sinh fits,then back to the question...integral dx/sqrt(x-2)^2+25...let 5sinh@ be x-2...therefore the equation becomes integral dx/sqrt(5sinh@)^2+25...integral dx/sqrt25sinh^2@+25...NB...don't forget x-2=5sinh@...so,integral dx/5sqrtsinh^2@+1...(pause)...using the principle of hyperbolic functions cosh^2@-sinh^2@=1...cosh^2@=1+sinh^2@...substitute that to where we stopped...integral dx/5sqrtcosh^2@...integral dx/5cosh@(pause)...from the beginning...x-2=5sinh@...dx/d@=5cosh@...dx=5cosh@d@...back to where we stopped integral dx/5cosh@...substitute dx=5cosh@d@...then it becomes integral 5cosh@d@/5cosh@...which is equal to integral d@...which is equal to {@}...from the top x-2=5sinh@...(x-2)/5=sinh@...therefore @=arcsinh(x-2)/5 +c...

i knw I'll locate u guys, #shaking heads# ehn ehn, so dis is hw life b abi? Hweva, u guys re doing gr8 here. I'm nw here with u guys 2 learn, 2 solve n 2 help. @ omosive, my mentor always tell me d@ nothin is impossible nt until i found myself knwing basic maths n 4rm there I tank God, so u cn do it, a question may take u 5 days 2 tink, buh if u give it 2 another person 2 solve, d@ shows u dnt wnt 2 disturb ur brain. @ Ortarico, calculux, More PALMOIL 2 ur elbows. Lols. Letz drive mathematics pls

Calculusf(x):
...kudos to my oga at the top(ortarico) for number one...2...integral dx/sqrt(x-2)^2 +25...using the principle of hyperbolic functions...{1/sqrt x^2-a^2 will attract cosh,1/sqrtx^2+a^2 will attract sinh,1/sqrta^2-x^2 will attract sin}...so from those standard integral...sinh fits,then back to the question...integral dx/sqrt(x-2)^2+25...let 5sinh@ be x-2...therefore the equation becomes integral dx/sqrt(5sinh@)^2+25...integral dx/sqrt25sinh^2@+25...NB...don't forget x-2=5sinh@...so,integral dx/5sqrtsinh^2@+1...(pause)...using the principle of hyperbolic functions cosh^2@-sinh^2@=1...cosh^2@=1+sinh^2@...substitute that to where we stopped...integral dx/5sqrtcosh^2@...integral dx/5cosh@(pause)...from the beginning...x-2=5sinh@...dx/d@=5cosh@...dx=5cosh@d@...back to where we stopped integral dx/5cosh@...substitute dx=5cosh@d@...then it becomes integral 5cosh@d@/5cosh@...which is equal to integral d@...which is equal to {@}...from the top x-2=5sinh@...(x-2)/5=sinh@...therefore @=arcsinh(x-2)/5 +c...

That's my boss. . . .always reliable, me hail oooo

rashywire: i knw I'll locate u guys, #shaking heads# ehn ehn, so dis is hw life b abi? Hweva, u guys re doing gr8 here. I'm nw here with u guys 2 learn, 2 solve n 2 help. @ omosive, my mentor always tell me d@ nothin is impossible nt until i found myself knwing basic maths n 4rm there I tank God, so u cn do it, a question may take u 5 days 2 tink, buh if u give it 2 another person 2 solve, d@ shows u dnt wnt 2 disturb ur brain. @ Ortarico, calculux, More PALMOIL 2 ur elbows. Lols. Letz drive mathematics pls

hmmmmmm. . . .thanks.

I think we have new mad people coming here....

Hmm...greatinz @ortarico,calculus,omosivie,general dx and odas...i can feel d heat hear

Mr Calculus: Hmm...greatinz @ortarico,calculus,omosivie,general dx and odas...i can feel d heat hear

Thank goodness, one of my bosses finally locates here. . . .welcome Mr. Calculus

.

Calculusf(x):
Pls,my people...how can you calculate these without using calculator...and faster than those using calculator...1.52^2
2.47^2
3.458*111
4.978^2
5.93^2
6.45*135
7.425^2

1 52 x 52= 2744
2 47 x 47 = 2209
3 Too long to calculate
4 Too long to calculate
5 93 x 93 = 8649
6 Too long to calculate.