Microflux:
okay!. Thanks alot. Just make sure you invite your e-friends, both jambites and non-jambites. It promises to be fantastic. And i knw when the result z released all partakers will flood nl with testimonies. Thanks.

MizMyColi:
Following.

I will teach/shed more light on social science subjects.
This is also an avenue for me to learn.
Thanks Microflux.

Xcapizt
Airbornelacer
Logodwhiz

You might like this.

LogoDWhiz:


Thanks for this, Ma.
I really like this and i support this setup.

Will be gald to contribute my quota in the Science subjects, most expecially, Mathematics and Physics.

Microflux:
Waow! thanks. Noted.

MizMyColi:



I may not be a science geek.

But I have surrounded myself with them noni.

Thanks LogoDwhiz.

pickabeau1:
Over to you.. you have a core of resource persons now

get the ball rolling

Microflux:
ohkay! Please can u hep us to make a workable timetable for the tutorial or mayb u and mizmycoli?

pickabeau1:


that will be difficult considering my schedule and dare i presume her's

Thats why i said you should do this once or twice a day with all the difficult questions

we then comein, answer with explanations and move on

until it starts.. nothing will happen

Jennimma:
Following.

Microflux:
ohkay. Miss. NL

Jennimma:

I can handle govt...has anyone taken that?

goofyone:
I can support anyone interested in learning tricks to solving maths questions in little time. Very simple tricks that could reveal the answers quickly, which is often how JAMB wants the questions solved. No long solutions.

Microflux
Please follow him up.

He is genius!

goofyone:
I can support anyone interested in learning tricks to solving maths questions in little time. Very simple tricks that could reveal the answers quickly, which is often how JAMB wants the questions solved. No long solutions.

Jennimma:

I can handle govt...has anyone taken that?

We can both share that

And maybe i'll chip in some parts of literature

MizMyColi:


Microflux
Please follow him up.

He is genius!

MizMyColi:


Microflux
Please follow him up.

He is genius!

Microflux:
ohkay you are really of usefulnes to the growth of this tutorial how cn u b of hep?

goofyone:

Maths basically. Quick tricks to solving jamb maths. Just keep me informed by tagging me when you begin and people bring on their maths questions. I'll also gladly go through the steps with them, provided i can.

Let me give you a quick example.

Find the equation of a line parallel to y = -4χ + 2 passing through (2,3)

A. y - 4χ + 11 = 0
B. y + 4χ + 11 = 0
C. y - 4χ - 11 = 0
D. y + 4χ - 11 = 0

This is a jamb question i just copied from the internet. To answer this question the normal way, you have to go through long series of steps which involve determining the gradient of the line and then using some funny equation to calculate the gradient of the line and then the equation of the line.
To solve this faster, it's better to work from the answer. If the line must pass through (2,3) then the first part of the answer should cancel out 11 in the second part. The student immediately sees that y + 4x should sum to give 11. Immediately you realize that only D has y + 4x=11 so that (2,3) actually passes through. So D is the answer. No need to go through the hassles of following solution steps. You get me?

Mbanu
Maths just got real in here

Nelsizzy:
I will teach commerce....

naijaboiy:

We can both share that

And maybe i'll chip in some parts of literature

naijaboiy:

We can both share that

And maybe i'll chip in some parts of literature

jimmy101231:
I can handle Economics. government or Yoruba

Fabdedon:
i wish Technical drawing is being offered here...i would have offered my best..i help in maths too

goofyone:

Maths basically. Quick tricks to solving jamb maths. Just keep me informed by tagging me when you begin and people bring on their maths questions. I'll also gladly go through the steps with them, provided i can.

Let me give you a quick example.

Find the equation of a line parallel to y = -4χ + 2 passing through (2,3)

A. y - 4χ + 11 = 0
B. y + 4χ + 11 = 0
C. y - 4χ - 11 = 0
D. y + 4χ - 11 = 0

This is a jamb question i just copied from the internet. To answer this question the normal way, you have to go through long series of steps which involve determining the gradient of the line and then using some funny equation to calculate the gradient of the line and then the equation of the line.
To solve this faster, it's better to work from the answer. If the line must pass through (2,3) then the first part of the answer should cancel out 11 in the second part. The student immediately sees that y + 4x should sum to give 11. Immediately you realize that only D has y + 4x=11 so that (2,3) actually passes through. So D is the answer. No need to go through the hassles of following solution steps. You get me?