barackodam:



You like maths ni, I think say you hate am??

Xtarxhyne:
c his mouth


I like maths

2muchopoTBdope:

59/64 = 0.921875
0.921875 × 2 = 1.84375
forget the number before the decimal point in dis next step
0.84375 × 2 = 1.6875
forget the number before the decimal point as usual
0.6875 × 2 = 1.375
As usual,
0.375 × 2 = 0.75
As usual,
0.75 × 2 = 1.5
As usual, forget the number before the decimal point and continue
0.5 × 2 = 1.00
At this point,u dont go further cos the number after d decimal is zero. Now ur answer will come from those numbers u ignored(ie all the numbers before the decimal point. Therefore,from the first multiplication, the answer is .111011 base two. I hope u get it??

Xtarxhyne:
c his mouth


I like maths

bolaji3071:
pls help me wit dis.

Factorize completely Y^3-4XY+XY^3-4Y
&
Factorize 4a^2-12ab-c^2+9b2

tanx

bolaji3071:
pls help me wit dis.

Factorize completely Y^3-4XY+XY^3-4Y
&
Factorize 4a^2-12ab-c^2+9b2

tanx

raayah:


I'll do the first, since barack did the second.

Firstly separate y^3+xy^3-4y-4xy

Factorize y^3(1+x) -4y(1+x)

adding (y^3-4y) (1+x)

further factorization y(y^2-4)(1+x)

y^2-4= (y+2)(y-2)

overall y(y+2)(y-2)(1+x)

Same Example i did last time.

Martiyu:
pls, bikonu whenever anyone comes across any of the following jamb threads (Commerce, Account, Government and Economics) Pls just make do to quote me and share the link. Daalu, Nagode, Ime, Ese

goofyone:
guys, I'm sorry for not being around. My timezone at the moment is not very favourable.
Nevertheless, I'll go about espousing my little simple methods of solving JAMB questions here. Hopefully, someone will find it useful.
Since we are treating number bases, let me start with a few number bases examples.

Please take caution as you go through these solutions. You are supposed to learn from them, not to cram them.

First question:

What is the answer when 2434 base 6 is divided by 42 base 6?

A. 23 base 6
B. 35 base 6
C. 52 base 6
D. 55 base 6

To solve a question like this normally and fast, you'd have to first convert 2434 base 6 to base 10, then also convert 42 base 6 to base 10, divide your answers, and then convert back to base 6.

But there is a faster way to go around it, and I'll show you.

You see numbers in a base, say 6 for example, will not only have digits less than that number. Because of this, a number in a certain base is less than the same number in a higher base. In this case, 2434 base 6 is actually much less than 2434 to base 7, 8, 9 or 10. While 42 base 6 is also less than 42 in base 7, for example.

Since it is easy to work with base 10, we'll take this approach.

So 2434 base 6 is actually much less than 2434 to base 10 (and base 6 is very far from base 10). 42 to base 6 is also much less than 42 to base 10. Now, let's assume for a moment that we are actually dividing 2434 base 10 / 42 base 10. The answer will be about 57 or so. If you cannot quickly do this computation, a faster way is to immediately do 2436/42, instead of 2434/42, which divides cleanly to 58. You can also do 2400/40 should be very close to 2434/42.

Now, since you have that answer as 58 to base 10. You can then figure that if 2434 base 6 << 2434 base 10 and 42 base 6 << 42 base 10, then 2434 base 6 / 42 base 6 << 2434 base 10/42 base 10. This means that the options 52 base 6 & 55 base 6 can't be correct since they are so close to 58 base 10. This leaves you with 35 base 6 and 23 base 6. All of this you should have done in about 1 minutes or less.

Quickly convert both to base 10, 35 base 6 = 18 + 5 = 23 base 10 & 23 base 6 = 18 + 3 = 21 base 10. Then convert 2434 base 6 to 10 to give 598 base 10; also convert 42 base 6 to base 10 = 26 base 10. 598/26 = 23. Which means you answer is 35 base 6.

Alternatively, you could have converted everything in both question & answer to base 10 and then work directly in base 10.

What is the answer when 2434 base 6 is divided by 42 base 6?

A. 23 base 6
B. 35 base 6
C. 52 base 6
D. 55 base 6

This would mean converting all numbers to base 10 and treating the question like

What is the answer when 598 base 10 is divided by 26 base 10?

A. 23 base 6 = 18 + 3 = 21 base 10
B. 35 base 6 = 18 + 5 = 23 base 10
C. 52 base 6 = 30 + 2 = 32 base 10
D. 55 base 6 = 30 + 5 = 35 base 10

Using your usual knowledge of base 10 mathematics then, you can easily divide 598/26 which is 23 (B). If you can't immediately divide 598 by 26, then divide 600/25 = 24 ~ 23(B)

To solve this question, there is no point following the usual step first described: converting first to base 10, dividing your results and then converting your result to base 6. It'll waste your time.

I do hope you understand this procedure. If you have any questions, please don't fail to ask.

Martiyu:
cc: barackobam

Thumbs up to u

GeneralShepherd:
I am willing to teach any topic on mathematics here.

I don't mind taking out 30mins everyday from my busy schedule to coach the future engineers and scientists that will move Nigeria to where we need to be.

Quote anytime, with a question and I will reply.

Thanks.
GeneralShepherd. B.eng,M.sc

barackodam:





Which eng, EE or ME??

Martiyu:


23 base 6 ought to be 12 + 3 = 15 base 10...or is there anything I am missing?

barackodam:




Its actually, ODAM, not Obama, as you must have thought

Martiyu:


OH my bad. Pls forgive me for that oversight. I really did not take notice of it.

GeneralShepherd:



EE and Msc in offshore technology. Specialising in corrosion engineering

Martiyu:
pls, bikonu whenever anyone comes across any of the following jamb threads (Commerce, Account, Government and Economics) Pls just make do to quote me and share the link. Daalu, Nagode, Ime, Ese

barackodam:





Iono if this is correct sha, but this what I got.

4A^2-12AB-C^2+9B^2

Rearrange
4A^2-12AB+9B^2-C^2
4A^2-6AB-6AB+9B^2-C^2
(4A^2-6AB)-(6AB+9B^2)-C^2
4A(A-3/2B)-6B(A-3/2B)-C^2
(4A-6B) (A-3/2B)-C^2

WORKING ON THE FIRST

raayah:



I got a slightly different answer when working this

from your second step

(4a^2-6ab)-(6ab - 9b) - c^2

factorizing gives 2a(2a-3b)-3b(2a-3b)-c^2

this would be equal to (2a-3b)^2 -c^2

difference of two squares (2a-3b-c) (2a-3b+c)- completely factorized


CHECK: opening bracket

4a^2-6ab+2ac-6ab+9b^2-3bc-2ac+3bc-c^2

4a^2-6ab-6ab+2ac-2ac+9b^2-3bc+3bc-c^2

after cancelling out 2ac and 3bc, we are left with

4a^2-12ab+9b^2-c^2

barackodam:

Iono if this is correct sha, but this what I got.
4A^2-12AB-C^2+9B^2
Rearrange
4A^2-12AB+9B^2-C^2
4A^2-6AB-6AB+9B^2-C^2
(4A^2-6AB)-(6AB+9B^2)-C^2
4A(A-3/2B)-6B(A-3/2B)-C^2
(4A-6B) (A-3/2B)-C^2
WORKING ON THE FIRST

raayah:
With Factorization in Jamb, I highly suggest you work very closely with the given options.
Always expand the bracket to check if you are right.
There is a very high chance of mixing up signs, be extra careful