Geofavor:
GUYS, LESSON STARTS BY 1PM TODAY.
I SHALL START WITH THE FIRST TOPIC ON THE SYLLABUS - NUMBER BASE

SO GET YOURSELVES PREPARED.

CHEERS

Yes Boss!

OKAY, ARE WE READY?

Geofavor:
For jamb maths, students are expected to be familiar with number bases ranging from 2 to 10, and be able to carry out operations with each and every one of them.


BASE 10 NUMBERS (also known as decimal numbers); This is the most commonly used of all the bases. The numbers we use everyday are in base 10..

following

Francis95:
following

Still following? I thought no one was

Geofavor come n continue nah

Orezy5:
Geofavor come n continue nah

how far? How's preparations going?

All of you disappeared. plus i figured that i cant do number base additions and subtractions here, unless i solve in a sheet, capture it, and post. But some of you won't be able to view it.
So I can only explain. So, i implore everyone who doesnt already know the topic to go and read up on it.
Then post any question not understoood.

Geofavor:

how far? How's preparations going?

All of you disappeared. plus i figured that i cant do number base additions and subtractions here, unless i solve in a sheet, capture it, and post. But some of you won't be able to view it.
So I can only explain. So, i implore everyone who doesnt already know the topic to go and read up on it.
Then post any question not understoood.

ok

thankyouJesus:
Watching from sideline

Oga mi, you sef don reach here?

The problem with these kinds of online classes is that they hardly survive the test of time. It wanes off with time.


Observing though!

You guys had better come out from hibernation.

1. Each exterior angle of a regular polygon is 30°. Calculate the sum of the interior angles

2. The probability of an event P happening is 1/5 and that of event Q is 1/4. If the events are independent, what is the probability that neither of them happens?

3. Find the number of terms in the sequence 2, -9, -20, . . ., -141

4. The area of a sector of a circle of diameter 12cm is 66cm². If the sector is folded to form a cone, calculate the radius of the base of the cone.

5. A box contains 13 currency notes all of which are either #50 or #20 notes. The total value of the currency notes is #530. How many #50 notes are in the box?

If u need a comfortable study routine add me on whatsapp for an educational adventure with other jambites. 09098280645

Pls letz continue this thread pls

mathefaro:
You guys had better come out from hibernation.

1. Each exterior angle of a regular polygon is 30°. Calculate the sum of the interior angles

2. The probability of an event P happening is 1/5 and that of event Q is 1/4. If the events are independent, what is the probability that neither of them happens?

3. Find the number of terms in the sequence 2, -9, -20, . . ., -141

4. The area of a sector of a circle of diameter 12cm is 66cm². If the sector is folded to form a cone, calculate the radius of the base of the cone.

5. A box contains 13 currency notes all of which are either #50 or #20 notes. The total value of the currency notes is #530. How many #50 notes are in the box?

1) 1800¤

2) 11/20

3) 14

4) 3.5cm

5)

PQRS is a parallelogram. The distance between PS and QR is 14cm and PS = 25cm. If PQ = 17.5cm, find the distance between PQ and SR.

Mathfero pls help solve this.

Geofavor:

1) 1800¤
2) 11/20
3) 14
4) 3.5cm
5)

could you help by posting hw u got that number 2?

ayokunlei:


could you help by posting hw u got that number 2?

1 - (1/5 + 1/4)

mathefaro:


5. A box contains 13 currency notes all of which are either #50 or #20 notes. The total value of the currency notes is #530. How many #50 notes are in the box?

Total amt of money=#530
Let the number of #50 notes = x
Then the number of #20 notes will be equal to (13-x)
here is the equation;

50x + 20(13-x)= 530
50x + 260 -20x= 530
30x=270
x=9
•°• there nine(9) #50 notes in the box



and there are four(4) #20 notes in d box i.e (13-9)

Geofavor:

1 - (1/5 + 1/4)

I kinda disagree with this because if u look closely at d question,it says the events are independent meaning they can happen at the same time without interfering with each other....

It then would be:
1-(1/5 × 1/4)
1-(1/20)
= 19/20

u should not add them....

Hey I might b wrong though..

we are all here to learn
Cc: mathefaro

cee001:
I kinda disagree with this because if u look closely at d question,it says the events are independent meaning they can happen at the same time without interfering with each other....

It then would be:
1-(1/5 × 1/4)
1-(1/20)
= 19/20

u should not add them....


Hey I might b wrong though..

we are all here to learn
Cc: mathefaro

So why didn't you solve the questions and post your own answers?

Geofavor:

1 - (1/5 + 1/4)

for independent event under probability, it deals with multiplication. The answer should be :
not P=1-1/5 = 4/5. not Q =3/4. Then , 4/5 * 3/4 = 3/5.

This app is really cool for maths in Jamb too................https://play.google.com/store/apps/details?id=com.xdev.mbt

Wow! A lot has happened while I was away. Hmm! Where do I start from?

I don't want to say anybody is wrong but this is actually the solution to the question

mathefaro:

2. The probability of an event P happening is 1/5 and that of event Q is 1/4. If the events are independent, what is the probability that neither of them happens?

P = 1/5 therefore P' = 1 - 1/5 = 4/5
Q = 1/4 therefore Q' = 1 - 1/4 = 3/4
The probability that neither of the events happens = P' and Q' ( P doesn't happen and Q doesn't occur) and we all know that the word "and" in probability begets "multiplication" of the probability of the events involved.
Therefore,
p(neither events) = P' * Q'
= 4/5 * 3/4
= 3/5

ciao

ayokunlei:


for independent event under probability, it deals with multiplication. The answer should be :
not P=1-1/5 = 4/5. not Q =3/4. Then , 4/5 * 3/4 = 3/5.

Yaaaga

Geofavor:
PQRS is a parallelogram. The distance between PS and QS is 14cm and PS = 25cm. If PQ = 17.5cm, find the distance between PQ and SR.

Mathfero pls help solve this.

Actually, it's Mathefaro, I didn't get the mention. And back to the question, it's kinda vague. Since the diagram was not provided, information on the parallel sides should have been given...
My thoughts anyway. I'll see if I can get a way round it though during my leisure time tomorrow.
But at the mean time, let me invite some math generals to check it out.
Cc:thankyoujesus, polymath, princecee, agentofchange1

mathefaro:
Actually, it's Mathefaro, I didn't get the mention. And back to the question, it's kinda vague. Since the diagram was not provided, information on the parallel sides should have been given...
My thoughts anyway. I'll see if I can get a way round it though during my leisure time tomorrow.
But at the mean time, let me invite some math generals to check it out.
Cc:thankyoujesus, polymath, princecee, agentofchange1

Pythagora's theorem or similarity concept will suffice.

thankyouJesus:
Pythagora's theorem or similarity concept will suffice.

how?

mathefaro:
Actually, it's Mathefaro, I didn't get the mention. And back to the question, it's kinda vague. Since the diagram was not provided, information on the parallel sides should have been given...
My thoughts anyway. I'll see if I can get a way round it though during my leisure time tomorrow.
But at the mean time, let me invite some math generals to check it out.

btw, i have corrected a slight mistake the the question initially had. It's QR not QS

ayokunlei:


for independent event under probability, it deals with multiplication. The answer should be :
not P=1-1/5 = 4/5. not Q =3/4. Then , 4/5 * 3/4 = 3/5.

you knew it, yet you couldn't solve the question and post it all these while.

It's been long since i did the topics of the questions he posted(i'd have to revise to recall fully). I just had to rush and put something down, since you guys ignored the questions.