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Note countdown is 1hour
Don't answer twice
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First to get it wins the ransom

3+4+4x10 = 110

might also be 47

15 plus 15 plus 15 = 45.
.
.
4 plus 4 plus 15 = 23
.
.
4 plus 3 plus 3 = 10
.
.
2 plus 3 plus 3 times 10 = 35.
.
.
.
Please note :
one bunch of banana has 4 piece and the other 3 piece.
One wall clock was at 3 and another at 2.
The first shape had two inner shapes,the last shape is short of one,making it 10 instead of 15

2+3+3*11 = 88

or

2+3+(3*11) = 38

From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38.

the polygons sides represent 1unit, one plantain is 1unit and 3'oclock means 3units.

solving eventually leads to

2+3+3x11

obeying BODMAs,, it becomes

2+3+33 =38

the correct answer is 225

answer is 255

Lol, see as people dey modify answer... issorait.

.

.
.
2 plus 3 plus 3 times 11 = 38.
Using bodmas (3×11+2+3)
.
.
.
Please note :
one bunch of banana has 4 piece and the last in d eqn has 3 piece.
One wall clock was at 3 and another at 2 (making the last clock 3-1hour=2)
The first shape had 3 shapes wother each side making a total of 15, removing the square of d last shape u have 11 sides)

For the sake of fairness

Ronaldinnioh:
Win data or credit of your choice if you get this quiz

Note countdown is 1hour
Don't answer twice
Show your working
First to get it wins the ransom

Centyakam:
3+4+4x10 = 110

might also be 47

boluwafunmike:
15 plus 15 plus 15 = 45.
.
.
4 plus 4 plus 15 = 23
.
.
4 plus 3 plus 3 = 10
.
.
2 plus 3 plus 3 times 10 = 35.
.
.
.
Please note :
one bunch of banana has 4 piece and the other 3 piece.
One wall clock was at 3 and another at 2.
The first shape had two inner shapes,the last shape is short of one,making it 10 instead of 15

ellagabs:
2+3+3*11 = 88

or

2+3+(3*11) = 38

Tittusstar22:
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38.

ayodijex:
the polygons sides represent 1unit, one plantain is 1unit and 3'oclock means 3units.

solving eventually leads to

2+3+3x11

obeying BODMAs,, it becomes

2+3+33 =38

xlextj:
the correct answer is 225

xlextj:
answer is 255

ayodijex:
Lol, see as people dey modify answer... issorait.

15+15+15=45

4+4+15= 23

4+3+3=10

3+4+4 * 10 = 47

Using bodmas and considering the missing square the answer is 47.... but using bodmas and without considering the missing square the answer is 67...

So oga what if it's a mistake from the drawing..