|
FOD (m)
|
Solve the following equations: 2x + 1 ------- = 3 x 22x + 1 = 3x 2Rearranging, 3x 2 - 2x - 1 =0 (3x+1) (x-1) = 0 x= -1/3 or 1 3/(x 2 +2) = 4 - 1 3/(x 2 + 2) = 3 Cube both sides, ( 3/x 2 + 2) 3 = 3 3x 2 + 2 = 27 x 2 = 27 - 2 x 2 = 25 x = +5 or -5 |
|
|
|
|
|
Builder
|
Jeeeze, this thread is kindda depressin, reminds me of how them crazy teachers whoop ma arse, i hate maths!!!
|
|
|
|
|
|
J UNIT (m)
|
find themaximum proft given the following equation.
c(x) = 5x^2 - 7x +6
and
r(x)= 12x-3x^2+4.
|
|
|
|
|
|
huxley
|
Let us assume that there are five houses of different colors next to each other on the same road. In each house lives a man of a different nationality. Every man has his favorite drink, his favorite brand of cigarettes, and keeps pets of a particular kind.
1. The Englishman lives in the red house.
2. The Swede keeps dogs.
3. The Dane drinks tea.
4. The green house is just to the left of the white one.
5. The owner of the green house drinks coffee.
6. The Pall Mall smoker keeps birds.
7. The owner of the yellow house smokes Dunhills.
8. The man in the center house drinks milk.
9. The Norwegian lives in the first house.
10. The Blend smoker has a neighbor who keeps cats.
11. The man who smokes Blue Masters drinks bier.
12. The man who keeps horses lives next to the Dunhill smoker.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The Blend smoker has a neighbor who drinks water.
The question to be answered is: Who keeps fish?
|
|
|
|
|
|
bawomolo (m)
|
find themaximum proft given the following equation.
c(x) = 5x^2 - 7x +6
and
r(x)= 12x-3x^2+4.
what kind of question is this, what do c(x) and r(x) signify. |
|
|
|
|
|
4 Him (m)
|
Solve the following equations: Cross multiply both sides: x^2 + x = 3x x^2 - 2x = 0 make x subject of the formulae: x(x - 2) = 0 Therefore x = 0 or x = 2. |
|
|
|
|
|
bawomolo (m)
|
Solve the following equations:  ln (x2 - 9) = 2 |
|
|
|
|
|
nwando
|
chei.
Mr fadeinde tried so much to inculcate these math skills
I just crammed them and vomitted them for WAEC
|
|
|
|
|
|
Olumide7 (m)
|
5 x=2 x.2 divide both sides by 2 x5 x/2 x=2 (5/2) x=2 ln both sides ln(5/2) x=ln 2 x ln (5/2) = ln 2 x= ln2/ln(5/2)  ln(x 2-9)=2 x 2-9=e 2x 2=16.4 x=+-4 approx. |
|
|
|
|
|
bawomolo (m)
|
Mixtures) The radiator in an automobile holds 14 quarts. How much pure anti-freeze should be mixed with a 20% anti-freeze solution to obtain a 40% mixture that will fill the tank?
Find the values of a & b so that f(x) = and f(2) = 3 and f(-1) = 4.
|
|
|
|
|
|
4 Him (m)
|
Mixtures) The radiator in an automobile holds 14 quarts. How much pure anti-freeze should be mixed with a 20% anti-freeze solution to obtain a 40% mixture that will fill the tank?
this is a little tough but i'll give it a try (with a little bit of help though):  From the table above create 2 equations: Eqn 1 - x + y = 14 Eqn 2 - x + 0.2y = 5.6 Since we need to find x, make y the subject of eqn 1. y = 14 - x Substitute for y in eqn 2: x + 0.2(14-x) = 5.6 0.8x = 2.8 x = 3.5 qz |
|
|
|
|
|
4 Him (m)
|
any method, there's more if u want to try your hands.
x + y + z = 9 - 1
x + 2y + 3z = 23 - 2
x + 5y - 3z = -7 - 3
it's more comfortable solving it with linear algebra by the way. I think Pataki's calculation was wrong, RichyBlack got it right but i prefer using simple algebra to solve. First i label all 3 equations to make it easier to locate: x + y + z = 9 - 1 x + 2y + 3z = 23 - 2 x + 5y - 3z = -7 - 3Subtracting equations 1 from 2 gives us: y + 2z = 14 - 4make y subject of the formular: y = 14 - 2z Subtracting equation 3 from equation 2 gives us: -3y + 6z = 30 - 5substitute for y into equation 5: -3(14 - 2z) + 6z = 30 solving: 12z = 72 z = 6Substitute for z in equation 4: y + 2(6) = 14 solving: y = 2Substitute for y and z in equation 1: x + 2 + 6 = 9 Solving: x = 1 |
|
|
|
|
|
bawomolo (m)
|
Solve for x in the interval [ 0, 2pi ):  |
|
|
|
|
|
Olumide7 (m)
|
sin2x-sin x - 2=0
(sin x - 2)(sin x +1) = 0
sin x - 2 =0 ; sin x + 1=0
sin x = 2 invalid
sin x = -1
Is there any value of x in the given interval that satisfies the equation ?
after sloving the equation x = -pi/2 which is not in the given interval.
|
|
|
|
|
|
J UNIT (m)
|
Solve the following equations: ln (x2 - 9) = 2 what exactly are we solving for. |
|
|
|
|
|
J UNIT (m)
|
people understand the quesion, don't just bring it from a text book when you are not sure yourself about the question, is tis how you are asked questons in exams.
|
|
|
|
|
|
bawomolo (m)
|
sin2x-sin x - 2=0
(sin x - 2)(sin x +1) = 0
sin x - 2 =0 ; sin x + 1=0
sin x = 2 invalid
sin x = -1
Is there any value of x in the given interval that satisfies the equation ?
after sloving the equation x = -pi/2 which is not in the given interval.
-pi/2 is the same as 3pi/2 |
|
|
|
|
|
bawomolo (m)
|
people understand the quesion, don't just bring it from a text book when you are not sure yourself about the question, is tis how you are asked questons in exams.
nope, it's obvious the only variable that should be solved for is x. i think u should explain your C(x) and R(x) before talking shit. solve for x in the interval(0 Pi) c. 2 + cosine2x = 3cosinex |
|
|
|
|
|
donchichi
|
Solve the following equations: let me try if u log both sides, it gives; log 5 x = log 2 x+1xlog 5 = x+1log 2 x/x+1 = log 2 / log 5 x/x+1 = 0.431 x = 0.431x + 0.431 x - 0.431x = 0.431 0.569x = 0.431 x = 0.76Bawomolo, is the question above 2 + cosine2x = 3cosinex or 2 + cosine(2x) = 3cosinex |
|
|
|
|
|
J UNIT (m)
|
i gave you c anr r functions and asked you to profit and you asking what you solving for. dum head
|
|
|
|
|
|
bawomolo (m)
|
s the question above 2 + cosine2x = 3cosinex or 2 + cosine(2x) = 3cosinex it's 2+ cosine(2x) i gave you c anr r functions and asked you to profit and you asking what you solving for. dum head
yeah because we all know c and r functions are for. (Geometry) A rancher's pasture is rectangular and has an area of 84 square miles. The length is 5 miles more than the width. How much will it cost to enclose the pasture with a fence if fencing materials cost an average of #1.80 per linear foot? (5280 ft = 1 mile) |
|
|
|
|
|
4 Him (m)
|
(Geometry) A rancher's pasture is rectangular and has an area of 84 square miles. The length is 5 miles more than the width. How much will it cost to enclose the pasture with a fence if fencing materials cost an average of #1.80 per linear foot? (5280 ft = 1 mile) length = l miles Breadth/width = l-5 miles Area of rectangle = length * Breadth = l(l-5) = 84. l^2 - 5l = 84 l^2 - 5l - 84 = 0 (solve quadratic equation) l = 12 miles breadth = 7 miles. Total length of fence = perimeter = 2(length + breadth) = 2(12+7) = 38 miles. 1 miles = 5280ft 38 miles = 200640ft if 1 ft costs #1.80
therefore 200640ft will cost = #361,152. |
|
|
|
|
|
holamiday (m)
|
@ engineered, what you said has a little sense in it but you messed it up with callijg the users fools. you shouldn't have said that. learn to be polite.
|
|
|
|
|
|
dason4life (m)
|
please help me with this:
If two planes leave the same airport at 1:00 PM, how many miles apart will they be at 3:00 PM if one travels directly north at 150 mph and the other travels directly west at 200 mph?
|
|
|
|
|
|
4 Him (m)
|
please help me with this:
If two planes leave the same airport at 1:00 PM, how many miles apart will they be at 3:00 PM if one travels directly north at 150 mph and the other travels directly west at 200 mph?
Clearly both planes travel for 2hrs (1PM - 3PM) therefore Plane b traveling north at 150mph travels exactly 300miles Plane c traveling west at 200mph travels exactly 400miles. This gives you a right angle triangle which can then be solved by pythagoras theorem Distance between both planes a^2 = b^2 + c^2 a^2 = 300^2 + 400^2 a^2 = 2500 a = 500 miles |
|
|
|
|
|
bawomolo (m)
|
If because x = 1/3 and csc x < 0 find sin x. Solve for x in the interval [ 0,2pi ): a. sin 2x = cosine x Solve the following inequalities:  |
|
|
|
|
|
gbeborun (m)
|
Though this aint algebra, but just solve it anyways:
1/3 of the people in a club are men. The number in the club is n.
a) write down and expression in terms of n for the number of people in the club.
b) two of the people in the club are chosen at random, the probability that both these people are men is 1/10. Calculate the number of people in the club.
|
|
|
|
|
|
Ibime (m)
|
@ Huxley, Na Einstein puzzle wey you want use kill person? @ gbeborun, your question (a.) is ill posed. Anyway, make I help you whichever way I fit. My probability is sketchy. 1/3 of the people in a club are men. The number in the club is n.
a) write down and expression in terms of n for the number of people in the club.
b) two of the people in the club are chosen at random, the probability that both these people are men is 1/10. Calculate the number of people in the club.
(a. ) n (b.) Let m be the no of men in the club. Therefore we have that n=3m or m=n/3 Taking probabilities without replacement, we have that m/n((m-1)/n) = 1/10 Hence 1/3((m-1)/n) = 1/10 (m-1)/n = 3/10 Hence m-1 = 3n/10 Solving simultaneously: m - 1 = 3n/10 m = n/3 -1 = 3n/10 - n/3 -1 = (9n-10n)/30 -1 = -n/30 n/30 = 1 n = 30 Hence, there are 30 people in the club. Check: 10/30 x 9/30 = 90/900 = 1/10. QED |
|
|
|
|
|
4 Him (m)
|
Solve the following inequalities: The equation is equal to zero when: x = -2 x = 3 Therefore equation is > 0 when x is between (-infinity, -2) and (-2, 3) |
|
|
|
|
|
gbeborun (m)
|
Hence, there are 30 people in the club.
Check:
10/30 x 9/30 = 90/900 = 1/10. QED
WRONG!!!!!!!!!!!!!!!!
using your answer and remembering there's no replacement
10/30 x 9/29 = 90/870 (which is obviously not 1/10)Answers pleaseeee! |
|
|
|
|
|
Ibime (m)
|
^^^ Sorry, let me do that again. That was a minor oversight.
(b.) Let m be the no of men in the club. Therefore we have that n=3m or m=n/3
Taking probabilities without replacement, we have that m/n((m-1)/n-1) = 1/10
Hence 1/3((m-1)/(n-1)) = 1/10
(m-1)/(n-1) = 3/10
Hence m-1 = (3n-3)/10
Solving simultaneously:
m - 1 = (3n/10) - (3/10)
m = n/3
-1 = 3n/10 - n/3 - 3/10
-1 = (9n-10n -9)/30
-1 = (-n-9)/30
(n+9)/30 = 1
n/30 + 3/10 = 1
n/30 = 7/10
n = 210/10
n = 21
Hence, there are 21 people in the club.
Check:
7/21 x 6/20 = 1/10 QED
|
|
|
|
|
|
gbeborun (m)
|
@Ibime,
nice one!
|
|
|
|
|
|
![Nairaland [Nigerian Forum] Home](http://www.nairaland.com/Themes/default/images/english/home.gif)
Author
