Solve This Riddle

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Date: September 08, 2008, 12:49 PM
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Author Topic: Solve This Riddle  (Read 260 views)
SAM MILLA (m)
Solve This Riddle
« on: June 18, 2008, 10:12 PM »

3 on 3

Using the numbers 1-9 (you can only use each number ONE time) can you make 3 rows of 3 so that the sum total of all 3 digits in any direction (vertical and horizontal) is 15?


* * *
* * *
* * *
chidipupay (m)
Re: Solve This Riddle
« #1 on: June 18, 2008, 10:42 PM »

it is simple.

        8 6 1
        4 2 9
        3 7 5

am i right?
SAM MILLA (m)
Re: Solve This Riddle
« #2 on: June 21, 2008, 06:22 PM »

weldone.
you got it right.
worked it out this way too.


8 3 4
1 5 9
6 7 2
kola oloye (m)
Re: Solve This Riddle
« #3 on: June 24, 2008, 01:02 PM »

Quote from: SAM MILLA on June 18, 2008, 10:12 PM
3 on 3

Using the numbers 1-9 (you can only use each number ONE time) can you make 3 rows of 3 so that the sum total of all 3 digits in any direction (vertical and horizontal) is 15?


* * *
* * *
* * *

check this out

  9  5  1
  2  7  6
  4  3  8

give us something harder
jay bee (m)
Re: Solve This Riddle
« #4 on: June 24, 2008, 01:09 PM »

Can you add your name to the list? Work out the answer to unlock the spreadsheet.
This is a 5th Grade Math Problem. If you can’t stand word math problems, just delete now. If you can open
spreadsheet with the correct answer, you’ll see it’s a very small list of people who have got the correct answer. This is not a trick question. This is a real math problem so don’t say that a bus has no legs, and the bus driver is NOT part of the equation.

There are 7 girls in a bus.
Each girl has 7 backpacks.
In each backpack there are 7 big cats.
For every big cat there are 7 little cats.
Question: How many legs are on the bus?

The number of legs is the password to unlock the attached Excel sheet.
If you open it, add your name and send it on to see who else can unlock it.

Good luck! 

TheAnswer.xls
* TheAnswer.xls (148 KB - downloaded )
jay bee (m)
Re: Solve This Riddle
« #5 on: June 24, 2008, 07:32 PM »

no one managed to solve it?
Miketomi
Re: Solve This Riddle
« #6 on: June 24, 2008, 09:17 PM »

Quote from: chidipupay on June 18, 2008, 10:42 PM
it is simple.

 8 6 1
 4 2 9
 3 7 5

am i right?

Am afraid you are wrong despite SAM MILLA said you are right.

If you add along the left diagonal (1,2,3) you can't get 15.

The kernel of the solution is that  5 must occupied the central position as arranged by SAM MILLA.
There are other possible arrangement but 5 must be central.
SAM MILLA (m)
Re: Solve This Riddle
« #7 on: June 24, 2008, 11:10 PM »

Quote from: Miketomi on June 24, 2008, 09:17 PM
Am afraid you are wrong despite SAM MILLA said you are right.

If you add along the left diagonal (1,2,3) you can't get 15.

The kernel of the solution is that  5 must occupied the central position as arranged by SAM MILLA.
There are other possible arrangement but 5 must be central.


Yea, you are very right,
I just brushed my attention horizontally and vertically through his answer.
Meanwhile he is right partially7 because iforgot to add Diagonally on the question box.
tetmosol (m)
Re: Solve This Riddle
« #8 on: June 26, 2008, 01:05 PM »

 8  4  3
6  2  7
1  9  5

I think I am right!!
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