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C2H5OH (m)
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A bus made the trip to the city in 6 hours while traveling at an ave speed of 50 kph. Had the speed been 45 kph, how many minutes more would it have taken to make the trip to the city?
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TOPE2000! (f)
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Tope is not cheating! She hasn't forgotten the concept of Mechanical Advantage in elementary physics  . A has an MA of 2, while B has an MA of 1. Lol . . . . @david u have to divided the weight by the number of ropes supporting it  Thats how i got A  |
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davidylan (m)
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A bus made the trip to the city in 6 hours while traveling at an ave speed of 50 kph. Had the speed been 45 kph, how many minutes more would it have taken to make the trip to the city?
40 more minutes? |
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jay bee (m)
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@ Tope  What's the total resistance, current passing through the above circuit? |
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ladysex (f)
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1. A side of a rhombus is 10cm, and one of its
angle is 30°. Whatis its area? lo *vo * ^^03
A. 25 cm1
B 50 cm1
C100 cm1
D 150 cm'
E 175 cm2
2. In the figure, ABCD is a parallelogram. AB is
produced to M such that BM = -j AB. Find the
ratio Area of triangle AMD : Area of parallelogram
ABCD.
A. 2:3
B. 1:3
C. 1:2
D. 3:4
E. 3:2
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RichyBlacK (m)
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I am beginning to suspect Tope.
Everyone must now show their workings. . . . .no more A, B or Q
----------------------------------------------------------------------------------------------------
Find the remainder when the polynomial x4 - 3x2 + 7x - 10 is divided by x - 2
(1) 8
(2) -20
(3) 18
(4) 0
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~Sauron~
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A bus made the trip to the city in 6 hours while traveling at an ave speed of 50 kph. Had the speed been 45 kph, how many minutes more would it have taken to make the trip to the city?
(6.667-6) hrs = 2/3 X 60 mins = 40 mins. ---------------------------------------------------- RichyBlack, show your workings!!! |
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C2H5OH (m)
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40 more minutes?
yep 40 more minutes |
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~Sauron~
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@ Tope What's the total resistance, current passing through the above circuit? Total R = 2.73 ohms and Total Current = 4 Amps. |
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RichyBlacK (m)
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@ Tope What's the total resistance, current passing through the above circuit? Equivalent resistance = 30/11 Ohms Current = 44 A (given) |
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~Sauron~
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I nor fit o. . . . .small boy like me. |
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ow11 (m)
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Mehn. . . .see questions!! people never answer some. Abeg make somebody tackle that Kirchoff's rule question! |
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~Sauron~
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What is the value of (1-CosA) / (1+CosA) given that tan A = 3/4 ?
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jay bee (m)
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Equivalent resistance = 30/11 Ohms
Current = 44 A (given)
Total R = 2.73 ohms and Total Current = 4 Amps. R T is correct i am guessing u simply forgot to type the first 4 as I T=V T/R T = 44A |
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chiogo (f)
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--------------------------------- x-2 \l x^4 + 0 - 3x^2 + 7x - 10 -x^4 +2x^3 ---------------- 2x^3 - 3x^2 -2x^3 + 4x^2 ------------------ x^2 + 7x -x^2 +2x ---------------- 9x - 10 -9x +18 ----------- 8 ----------------------------------------------------------------------------------------------------
Find the remainder when the polynomial x4 - 3x2 + 7x - 10 is divided by x - 2
(1) 8
(2) -20
(3) 18
(4) 0
No more showing of work, please. |
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RichyBlacK (m)
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---------------------------------
x-2 \l x^4 + 0 - 3x^2 + 7x - 10
-x^4 +2x^3
----------------
2x^3 - 3x^2
-2x^3 + 4x^2
------------------
x^2 + 7x
-x^2 +2x
----------------
9x - 10
-9x +18
-----------
8
No more showing of work, please.
Chiogo, you're strong o! Thanks for showing Sauron the steps. |
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stamma (m)
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1. A side of a rhombus is 10cm, and one of its
angle is 30°. Whatis its area? lo *vo * ^^03
A. 25 cm1
B 50 cm1
C100 cm1
D 150 cm'
E 175 cm2
2. In the figure, ABCD is a parallelogram. AB is
produced to M such that BM = -j AB. Find the
ratio Area of triangle AMD : Area of parallelogram
ABCD.
A. 2:3
B. 1:3
C. 1:2
D. 3:4
E. 3:2
No 2. D 3:4 |
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ow11 (m)
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What is the value of (1-CosA) / (1+CosA) given that tan A = 3/4 ?
A= tan -1 0.75 therefore (1-Cos A)/(1+ Cos A) = 1/9 |
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~Sauron~
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@ Chiogo,
Thats the longest way of going about it.
Just set the denominator, x-2=0 then x=2
Then substitute x for 2,
f(2) = 24 - 3(2)2 + 7(2) - 10
= 16 - 12 + 14 -10
= 8
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TOPE2000! (f)
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What is the value of (1-CosA) / (1+CosA) given that tan A = 3/4 ?
I hate trigonometric, so imma pass |
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RichyBlacK (m)
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What is the value of (1-CosA) / (1+CosA) given that tan A = 3/4 ?
(1-4/50/(1+4/5) = 1/9. |
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chiogo (f)
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Chiogo, you're strong o! Thanks for showing Sauron the steps. 'Twas the only question I could answer here. Y'all are killing me with the trig, physics, calculus, and whatnot. @ Chiogo,
Thats the longest way of going about it.
Just set the denominator, x-2=0 then x=2
Then substitute x for 2,
f(2) = 24 - 3(2)2 + 7(2) - 10
= 16 - 12 + 14 -10
= 8
Oh cool, didn't know that. The synthetic division method is easy too. Just didn't feel like using that. |
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jay bee (m)
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Split 5(x + 2)/ (x + 1)(x + 6) into partial fractions.
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~Sauron~
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A= tan-1 0.75 therefore (1-Cos A)/(1+ Cos A) = 1/9
(1-4/5/(1+4/5) = 1/9.
Correct!!! ---------------------------------------------------------------------------------------------------- What is the probability of getting at least one six in a single throw of three unbiased dice? |
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~Sauron~
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Split 5(x + 2)/ (x + 1)(x + 6) into partial fractions.
A=1, B=4. 5(x + 2) = 1/(x+1) + 4/(x+6) (x+1)(x+6) |
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TOPE2000! (f)
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Correct!!!
----------------------------------------------------------------------------------------------------
What is the probability of getting at least one six in a single throw of three unbiased dice?
91 / 216 working Since we need at least one six, let us calculate the negation of this…I mean calculate the probability of not getting a six on any of these three dice. The probability of not getting a six on a die is 5/6 Since the three events here are independent events, the probability of not getting six on any of these three dice is 5/6×5/6×5/6 = 125/216. Hence the probability of getting at least one six is 1-125/216 = 91/216. |
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~Sauron~
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91 / 216 I am getting u a job with Microsoft.  |
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TOPE2000! (f)
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n showed my workings |
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