Thank you very much Prodgalson for given me your precious time,
I want to display only one image starting from the first when I click Next and the previous image when I click prev button but it is not done in the order in which the images are placed in the array.
This is the code i used to select the images.
<body>
<table border="0" align="center">
<?php
$im0 = "<img src = './pic/car.gif' width = '150' height = '150'>";
$im1 = "<img src = './pic/fl.jpg' width = '150' height = '150'>";
$im2 ="<img src = './pic/house.jpg' width = '150' height = '150'>";
$im3 = "<img src = './pic/phone.gif' width = '150' height = '150'>";
$im4 = "<img src = './pic/pope.jpg' width = '150' height = '150'>";
$image = array($im0, $im1, $im2, $im3, $im4);
shuffle($image);
echo next($image);
?>
</td></tr></table>
<table align="center" border="0">
<form action="<?php $_SERVER['PHP_SELF'] ?>" method="post">
<input type ="submit" value ="Previous" name="prv">
<input type="submit" value="Next" name="nxt" />
</form>
</td></tr></table>
</body>
I appreciate any suggestion on how best to do it.
Cnn
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