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RichyBlacK (m)
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A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ? A. 16%B. 32%C. 48%D. 84%E. 92%
The explanation for this is much easier with a diagram. Let G(z) = P(x is less than z). Since the distribution is symmetric about the mean m, then G(m) = P(x < m) = 50%. The statement "68 percent of the distribution lies within one standard deviation d of the mean" means that: G(m+d) - G(m-d) = 68% = P(m-d<x<m+d) So, we are looking for G(m+d) which is also equal to P(x < m+d)But P(x < m+d) = P(x < m) + P(m < x < m+d) = P(x < m) + 0.5*[P(m-d < x < m+d)] due to symmetric nature of distribution about the mean m = G(m) + 0.5*(G(m+d) - G(m-d)) just substituting = 50% + 0.5(68%) = 50% + 34% = 84% (Answer = D) NOTE: there are several other ways of doing this.
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LiquidMind (m)
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Nice maths tread
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ADint (m)
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He must sell it for :
0.11*170270 + 0.055*170270 + 170270 = $198 364.55 ( $198 365--to the nearest $)
( Assuming they are making the gains on the cost price).
Eyohimself, The agent must sell for $199,395(nearest $). Only Ann's gain is made on the initial cost price. To the Agent the current cost price is 170270 + (0.11*170270) = $188,999.70 So, selling price is 188,999.70 + (0.055*188,99.70) = $199,394.68 ($199,395)
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Eyohimself
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Eyohimself,
The agent must sell for $199,395(nearest $). Only Ann's gain is made on the initial cost price. To the Agent the current cost price is 170270 + (0.11*170270) = $188,999.70 So, selling price is 188,999.70 + (0.055*188,99.70) = $199,394.68 ($199,395)
Thanks for noting that. I made my calculations based on the assumption that they both had gains on the initial cost price which I think is quite possible. Your contribution is welcomed. You based your solution on the assumption that the Agent made the gain on Ann's selling price which from common logic, is more probable. Thanks for the insight. I thought the other way round.
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edusegzy (m)
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hi every one,
i'm happy to see o much going on on this thread.boy i ' have a lot of catching up to do. eyohimself how is your prep.i'm sure you are in top shape. i'm brewing some stuff. Richyblacky you are such a blessing on this thread.
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edusegzy (m)
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integrating sec x
sec x=
sec x (sec x +tan x)/(sec x +tan x)=sec2 x+sec x tan x/(sec x +tan x)
integerate:
ln(sec x +tan x)
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jay bee (m)
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There are 2 rooms. One has 3 light switches and the second one has three light bulbs. U can only enter the one with the light bulbs once. How do u deteremine which of the three light switches corresponds to three of the light bulbs in the second room
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RichyBlacK (m)
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There are 2 rooms. One has 3 light switches and the second one has three light bulbs. You can only enter the one with the light bulbs once. How do u deteremine which of the three light switches corresponds to three of the light bulbs in the second room
1. Go into room with switches 2. Do the following: i. Put the first switch ON, and leave it ON ii. Put the second switch ON, leave it ON for a while, and then switch it OFF iii. Ignore the third switch 3. Go into room with bulbs: i. The bulb that is ON is controlled by the first switch ii. The one that is OFF, but WARM is controlled by the second switch iii. The one that is OFF, but COLD is controlled by the third switch. NB: Some rather obvious assumptions were made.
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RichyBlacK (m)
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Eyohimself,
Howz life? How did the GRE go?
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opi-ororo (m)
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I love these guys.I which i also could be a mathematics guru as these guys up here.It's Cooooooooooooool! 
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