Next question pls

A BLOCK OF MASS 10KG REST ON A HORIZONTAL FLOOR,(COEFFICIENT OF FRICTION 0.4). (a) what Force Is Required Just To Make The Block Move when (i) Pulling Horizontally, (ii) Pulling At An Angle Of 60 Degree To The Horizontal? (b) If The Block Is Pulled With A Horizontal Force Of 50N, With What Acceleration Does It Move? (g=9.8m/s)

Polymath56:


Total payable Interest for d 36mnts = N9786
Total cost of loan payment= N59786

Monthly Loan repayments = 59786/36 = N1661

Pls, how did u arrive at '#9786' as total interest payments?. I don rack my brain tire. Abeg explain

afo7219:

Pls, how did u arrive at '#9786' as total interest payments?. I don rack my brain tire. Abeg explain

Lol...d method is quite intricate n arduous. You can use the usual method below

M = P [i(1+i)^n/(1+i)^n - 1]
Where M = monthly Loan repayments
i = r/12 = 0.12/12 = 0.01
n = 36 mnts

M = 50000[0.01(1.01^36)/1.01^36 - 1]
M = 50000[0.0143077/0.43077]
M = 50000[0.033214]
M = N1660.71

Polymath56:


Lol...d method is quite intricate n arduous. You can use the usual method below

M = P [i(1+i)^n/(1+i)^n - 1]
Where M = monthly Loan repayments
i = r/12 = 0.12/12 = 0.01
n = 36 mnts

M = 50000[0.01(1.01^36)/1.01^36 - 1]
M = 50000[0.0143077/0.43077]
M = 50000[0.033214]
M = N1660.71

Pls,educate me,how did u arrive at d formular? The one I'm used to is fv = p(1+r)^n

afo7219:

Pls,educate me,how did u arrive at d formular? The one I'm used to is fv = p(1+r)^n

It's actually the same formula for Annuity of future value.
A = r(FV)/[(1+r)ⁿ - 1]

Where FV = P(1+r)ⁿ

You could check up the formula for Annuity of future value for corroboratn.
Can I c how u solved urs?

afo7219:

Pls,educate me,how did u arrive at d formular? The one I'm used to is fv = p(1+r)^n

It's actually the same formula as Annuity from Future value;
A = r(FV)/[(1+r)ⁿ - 1]

Where FV = P(1+r)ⁿ

You could check up the formula of Annuity from FV for corroboratn n easy 'pray tell' on how dey derived the 4mula.

Next question pls

x"2 - 6root3 + 24=0

the sequence are a,ar,ar^2,ar^3.....
square of the sequence a^2,a^2r^2,a^2r^4......
Cube of the sequence a^3,a^3r^3,a^3r^6.....
Sum to infinity=a/r-1
S=a/r-1----------(1)
2S=a^2/r^2-1----------(2)
(64/13)S=a^3/r^3-1------(3)
Frm equation 2.
2S=a^2/(r-1)(r+1)
2S=(a/r-1)(a/r+1)
a/r-1=S:-
2S=S(a/r+1)--------(4)
From equation 3
(64/13)S=a^3/r^3-1
(64/13)S=a^3/(r-1)(r^2+r+1)
(64/13)S=(a/(r-1))(a^2/r^2+r+1)
(64/13)S=S(a^2/r^2+r+1)------4
By solving these simultaneously
We will get S=4
And d first three term.
8/3,8/9,8/27