Aybalance:
It is a GMAT test past question.15 minutes....Lol that's almost the time for the whole test....seems the only green flag is to have crossed the question before.
I also noticed in your solution that y:z=9:8 is z:y=9:8 and z-y=1 as there is a discount

I said y-z=1 and not z-y
If you want to get discount
You will do the mafjed price (z) - selling price (y)
That's the discounted amount.

Talking about the question. I spent about 15 minutes looking for the best approach that will make anyone understand. The question can be solved under 2 minutes.

In Gmats, you can spend 3 minutes on some questions and 15 seconds on others. You have to know how to work smart. So, if for example, you have 60 minutes for 60 questions, 1 question can take you 4 minutes and some other questions can take you 15 seconds. Questions have varying levels of complexities. You must be able to decipher well.

Aybalance:
It is a GMAT test past question.15 minutes....Lol that's almost the time for the whole test....seems the only green flag is to have crossed the question before.
I also noticed in your solution that y:z=9:8 is z:y=9:8 and z-y=1 as there is a discount

I meant, discount value is 1/9 of the selling price not marked price.

Talking about the question. I spent about 15 minutes looking for the best approach that will make anyone understand. The question can be solved under 2 minutes.

In Gmats, you can spend 3 minutes on some questions and 15 seconds on others. You have to know how to work smart. So, if for example, you have 60 minutes for 60 questions, 1 question can take you 4 minutes and some other questions can take you 15 seconds. Questions have varying levels of complexities. You must be able to decipher well.

Solve this simple Math equation and get #600 recharge card

Click here-- https://www.talkpalsforum.com/index.php?topic=34.msg69#msg69

naturalwaves:

I meant, discount value is 1/9 of the selling price not marked price.

Talking about the question. I spent about 15 minutes looking for the best approach that will make anyone understand. The question can be solved under 2 minutes.

In Gmats, you can spend 3 minutes on some questions and 15 seconds on others. You have to know how to work smart. So, if for example, you have 60 minutes for 60 questions, 1 question can take you 4 minutes and some other questions can take you 15 seconds. Questions have varying levels of complexities. You must be able to decipher well.

Thank you so much

Pls I need help with this
A person travels from P to Q at a speed of 40kmph and returns by increasing his speed by 50%.What is his average speed for both trips in kmph
A. 36
B. 45
C. 48
D. 50

Aybalance:
Pls I need help with this
A person travels from P to Q at a speed of 40kmph and returns by increasing his speed by 50%.What is his average speed for both trips in kmph
A. 36
B. 45
C. 48
D. 50

D. 50kmph

naturalwaves:

My solution

Data

pack 1...4 RED and 3 YELLOW cards
pack 2.....3 RED and 4 yellow cards

1) Probability of picking a red card at the end of the experiment implies
R,R or Y,R = [4/7 x 4/8] + [3/7 x 3/8]
= 2/7 + 9/56
= 25/56

2) Probability of picking a yellow card at the end of the experiment implies
Y,Y or R,Y = [3/7 x 5/8] + [4/7 x 4/8]
=15/56 + 2/7
=31/56

nice one.

Martinez39s:
SOLUTION
A pair of choices must be made to produce an outcome in this experiment.
(A) If we pick the 1st red ball in the 1st bag, there are 4 possible outcomes of a red ball, and 4 possible outcomes of a yellow ball. This is also true if we pick the 2nd, 3rd, or 4th red ball in the first bag.

(B) If we pick the 1st yellow ball in the 1st bag, there are 3 possible outcomes of a red ball, and there are 5 possible outcomes of a yellow ball. This is also true if we start with the 2nd or 3rd yellow ball in the first bag.

(C) From (A) & (B),
--- it is clear that the number of the pairs of choices leading to an outcome a red ball is O_RR + O_YR = 16 + 9 = 25.
--- It is also clear that the number of the pairs of choices leading to an outcome of a yellow ball is O_RY + O_YY = 16 + 15 = 31.
--- it then follows that the number of the pairs of choices resulting into an outcome of the experiment is
O_RR + O_YR + O_RR + O_YR = 56

The probability of picking a red ball is 25/56.
The probability of picking a yellow ball is 31/56.

nice one

1) a room is covers with tiles meaduring by 8cm by 5cm . If 1000 tiles are used , find the area of the room in square matters

2) the sum of two numbers is twice a third number .if the two numbers are 11 and 17 , find the third number

3) a boy runs 90meters in 10seconds .What is his speed in km per hour?
someone should help me solve it

arena07:
1) a room is covers with tiles meaduring by 8cm by 5cm . If 1000 tiles are used , find the area of the room in square matters

2) the sum of two numbers is twice a third number .if the two numbers are 11 and 17 , find the third number

3) a boy runs 90meters in 10seconds .What is his speed in km per hour?
someone should help me solve it

with workings

arena07:
1) a room is covers with tiles meaduring by 8cm by 5cm . If 1000 tiles are used , find the area of the room in square matters

2) the sum of two numbers is twice a third number .if the two numbers are 11 and 17 , find the third number

3) a boy runs 90meters in 10seconds .What is his speed in km per hour?
someone should help me solve it

1. The area of 1 tile is 8*5 = 40cm² = 0.004m². Therefore if a thousand of these are used to cover the room, then the area of the room = 1000*0.004 = 4 m²

2. Let the 3 numbers be x, y & z. According to the question,
x + y = 2z.
Therefore if x and y are 11 and 17 respectively, we have that
11 + 17 = 2z
2z = 28
z = 14.
Hence the third number is 14

3. 90m = 90/1000 = 9/100km and
10secs = 10/ 60*60 = 1/360 hrs.
Now if
9/100km = 1/360 hrs
x = 1hr
By cross multiplication, we have that
x = 9/100 ÷ 1/360 = 3240/100 = 32.4km/hr.

Ciao

mathefaro:

1. The area of 1 tile is 8*5 = 40cm² = 0.004m². Therefore if a thousand of these are used to cover the room, then the area of the room = 1000*0.004 = 4 m²

2. Let the 3 numbers be x, y & z. According to the question,
x + y = 2z.
Therefore if x and y are 11 and 17 respectively, we have that
11 + 17 = 2z
2z = 28
z = 14.
Hence the third number is 14

3. 90m = 90/1000 = 9/100km and
10secs = 10/ 60 = 1/6 hrs.
Now if
9/100km = 1/6 hrs
x = 1hr
By cross multiplication, we have that
x = 9/100 ÷ 1/6 = 54/100 = 0.54km/hr.

Ciao

thanks bro

mathefaro:

1. The area of 1 tile is 8*5 = 40cm² = 0.004m². Therefore if a thousand of these are used to cover the room, then the area of the room = 1000*0.004 = 4 m²

2. Let the 3 numbers be x, y & z. According to the question,
x + y = 2z.
Therefore if x and y are 11 and 17 respectively, we have that
11 + 17 = 2z
2z = 28
z = 14.
Hence the third number is 14

3. 90m = 90/1000 = 9/100km and
10secs = 10/ 60 = 1/6 hrs.
Now if
9/100km = 1/6 hrs
x = 1hr
By cross multiplication, we have that
x = 9/100 ÷ 1/6 = 54/100 = 0.54km/hr.

Ciao

pls I think the number 3 suppose to be converted to hour which (10/3600)hrs

arena07:
pls I think the number 3 suppose to be converted to hour which (10/3600)hrs

yeah, you're very correct. I've edited it

What is probability of someone living in Lagos contracting Coro virus given what we have been told about it's transmission.
a) within the next 6months
b) within next 5years
c) within the next 20years

2. what would be the answer a,b and c for somebody living any where in Nigeria.

Assume the following :
First ceas detected 80days ago
Today there are 6000 casrs..
million.
A .illion peopld iz added to the poulTion every yeat.
Poopulatiooc the country is 200

mathefaro:
yeah, you're very correct. I've edited it

ok boss

Pls I need solutions to question 12

tolulopevoice:
Pls I need solutions to question 12

Calculate the area of the quadrant to start with because you will still need it.
Area of a quadrant is (1/4) pi x R ²
Area of quadrant = (1/4)X(22/7)X14 X 14
=154cm²

To get the radius of the small circle, check the attached image and see how it was drawn
OC= (14-r)
(14-r)²= r² + r² from PYTHAGORAS THEOREM
(14-r)² =2r²
14-r=r x sqrt(2)
rx sqrt(2)+ r = 14
r(sqrt of 2 +1)=14
r=14/ [sqrt(2) +1]
r= 5.799cm

Thus,area of small circle = 22/7x 5.799 x5.799 = 105.689cm²

Area of the shaded part = Area of quadrant - Area of small circle
= 154 cm² - 105.689cm²
= 48.3cm²

naturalwaves:

Calculate the area of the quadrant to start with because you will still need it.
Area of a quadrant is (1/4) pi x R ²
Area of quadrant = (1/4)X(22/7)X14 X 14
=154cm²

To get the radius of the small circle, check the attached image and see how it was drawn
OC= (14-r)
(14-r)²= r² + r² from PYTHAGORAS THEOREM
(14-r)² =2r²
14-r=r x sqrt(2)
rx sqrt(2)+ r = 14
r(sqrt of 2 +1)=14
r=14/ [sqrt(2) +1]
r= 5.799cm²

Thus,area of small circle = 22/7x 5.799 x5.799 = 105.689cm²

Area of the shaded part = Area of quadrant - Area of small circle
= 154 cm² - 105.689cm²
= 48.3cm²

thank you God bless you, but why is OC = 14 - r

Please
In number 1 to 49 .Mr A took 6 numbers and mr B took 4 numbers what is the probability the 4 number of Mr B is not among the 6 numbers of mr A

tolulopevoice:
thank you God bless you, but why is OC = 14 - r

Reemeber that it is a quadrant and O is at the Centre of a circle. Any straight line drawn from the Centre of the circle to any part gives the radius. If a straight line goes from O to any edge, it is same as the Radius of the circle. Thus, that line from O to the front of that arrow is is also the Radius. We know the Radius should be 14 in all but there is a small r which covers part of the length. So, OC will be 14 - r. Do you understand??

coolqayy:
Please
In number 1 to 49 .Mr A took 6 numbers and mr B took 4 numbers what is the probability the 4 number of Mr B is not among the 6 numbers of mr A

Are they taking it randomly or Mr A will pick all his own first before Mr. B??

naturalwaves:

Are they taking it randomly or Mr A will pick all his own first before Mr. B??

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The take randomly

coolqayy:
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The take randomly

Are you sure? Can you take a snapshot of the question? If they are taking it randomly, there won't be need for Mr. A and Mr. B then. The question will just read that... What's the probability of selecting 10 numbers that aren't same from 49 numbers. Please take a snapshot of the original question. A lot of info is not clear.

I need workings to these objectives question.. thanks
Cc.naturalwaves,Mr shape etc

saipn:
I need workings to these objectives question.. thanks
Cc.naturalwaves,Mr shape etc

Everything on the left when added together must be equal to everything on the right when added together.
E.g
In the first sample,
LEFT COLUMN..3+2+7= 12
RIGHT COLUMN..1+6+5= 12
So, everything is just addition and subtraction.
Use this knowledge to solve others.
I hope this helps!

naturalwaves:

Everything on the left when added together must be equal to everything on the right when added together.
E.g
In the first sample,
LEFT COLUMN..3+2+7= 12
RIGHT COLUMN..1+6+5= 12
So, everything is just addition and subtraction.
Use this knowledge to solve others.
I hope this helps!

Thank you

arena07:
Thank you

You're welcome!

naturalwaves:

Everything on the left when added together must be equal to everything on the right when added together.
E.g
In the first sample,
LEFT COLUMN..3+2+7= 12
RIGHT COLUMN..1+6+5= 12
So, everything is just addition and subtraction.
Use this knowledge to solve others.
I hope this helps!

this is very helpful thanks

saipn:
this is very helpful thanks

You're welcome!

solve this differential equation using frobenius method

Smiles

Elders in the house help me look into this questions