Just new here. So what are the questions?

seno408: Just new here. So what are the questions?

Its not a contest o, Just capacity building...
Bring your.problems and pple will help u solve them...

echibuzor:


Its not a contest o, Just capacity building...
Bring your.problems and pple will help u solve them...

I know its not a competition.

Plz factorise x^6+8

plz help me with this:
if 2 bread and 4 butter cost 20naira.
If 3 bread and 6 butter cost 60naira.
Find the cost of 1 bread and 1 butter.

johnpaul1101: plz help me with this: if 2 bread and 4 butter cost 20naira. If 3 bread and 6 butter cost 60naira. Find the cost of 1 bread and 1 butter.

This is one very interesting application of mathematics, but check the question very well and ensure that you have provided us with the right values... i think the values are inconsistent.

Richiez: This is one very interesting application of mathematics, but check the question very well and ensure that you have provided us with the right values... i think the values are inconsistent.

tnx richiez, she says d question is ok(i.e there is no mistakes in it)
i tried solving it, but i got to point in which the variable i'm luking for canceled each other giving me 0. How can i find a variabke wen the variable itself is zero

Mbahchiboy: Plz factorise x^6+8

SOLUTION
x^6 + 8
this is same as; (x^2)^3 + 2^3
from our knowledge of addition of two cubes,
a^3 + b^3 = (a+b)(a^2 -ab + b^2) therefore
x^6 + 8
=(x^2)^3 + 2^3
=(x^2 + 2)(x^4 -2x^2+ 4)

johnpaul1101: tnx richiez, she says d question is ok(i.e there is no mistakes in it) i tried solving it, but i got to point in which the variable i'm luking for canceled each other giving me 0. How can i find a variabke wen the variable itself is zero

same problem here, if it is an assignment given to her, tell her to ask her friends for the correct values...

johnpaul1101:
tnx richiez, she says d question is ok(i.e there is no mistakes in it)
i tried solving it, but i got to point in which the variable i'm luking for canceled each other giving me 0. How can i find a variabke wen the variable itself is zero

The Question has a serious typo.... Someone should try plotting a graph for the equations, I am pretty sure there will be no intersection....

goodday every1, plz i would like someone to help me with these questions:
(1) a student is told to draw the graph of y=x^2+4x-6. He is then told to draw a linear graph on the same axis such that the intersection of the two graphs will give the solution to the equation x^2 + 4x - 7=0.what is the equation of the linear graph he needs to draw?
(2)find the product xy if x,3/2,6/7,y, are in a GP

I'm really impressed...like I said before "I'm following every equation solved"

Larrysamuel: Good day my maths guru, pls can u help me with this simultaneous equation (one quadratic and one linear) : x^2-y^2= 56....equation 1, xy=20....equation 2. 10x

u must b an oau student cos dats 1 of d assignment we were given last week in ssc105

johnpaul1101: goodday every1, plz i would like someone to help me with these questions: (1) a student is told to draw the graph of y=x^2+4x-6. He is then told to draw a linear graph on the same axis such that the intersection of the two graphs will give the solution to the equation x^2 + 4x - 7=0.what is the equation of the linear graph he needs to draw? (2)find the product xy if x,3/2,6/7,y, are in a GP

johnpaul, there is no tool to enable one plot a graph here...

johnpaul1101: goodday every1, plz i would like someone to help me with these questions:
(1) a student is told to draw the graph of y=x^2+4x-6. He is then told to draw a linear graph on the same axis such that the intersection of the two graphs will give the solution to the equation x^2 + 4x - 7=0.what is the equation of the linear graph he needs to draw?
(2)find the product xy if x,3/2,6/7,y, are in a GP

Richiez:
johnpaul, there is no tool to enable one plot a graph here...

@johnpaul..... Equate y=x^2+4x-6 and x^2 + 4x - 7=0 that should give you the Equation of the linear graph...After doin it myself, I got y = -1.. Dont know but i think that means the linear graph is parallel to the x-axis at y = -1... And for the Second one....

(3/2)/x = (6/7) / (3/2) = y/(6/7) (common ratio of the GP)

3/2x = 4/7 = 7y/6

Hence : 3/2x = 7y/6

14xy = 18

xy = 18/14...

echibuzor:


@johnpaul..... Equate y=x^2+4x-6 and x^2 + 4x - 7=0 that should give you the Equation of the linear graph...After doin it myself, I got y = -1.. Dont know but i think that means the linear graph is parallel to the x-axis at y = -1... And for the Second one....

(3/2)/x = (6/7) / (3/2) = y/(6/7) (common ratio of the GP)

3/2x = 4/7 = 7y/6

Hence : 3/2x = 7y/6

14xy = 18

xy = 18/14...

tnx chibuzor, i think i get it now

johnpaul1101:
tnx chibuzor, i think i get it now

My Pleasure...

I am new hear,can any one plz tell me how to reply someone's question

Dats right

A

This is it
solve for a
5loga(base 4) + 48log4(base a)= a/8.

echibuzor:

Good then.. My family is based in Ibadan although I am in Abuja at d moment... Thanks man....

I'm still awaiting your response to the email that I sent to you. Thanks

I hail all the gurus in the house. Nice works!

Much gratitude to the 'Gurus'.Nice job u all doing

Ayowumie:

I'm still awaiting your response to the email that I sent to you. Thanks

Replied.. Sorry I was out network coverage......

Adol16: This is it solve for a 5loga(base 4) + 48log4(base a)= a/8.

SOLUTION
loading....

LOVE U GUYS U ARE TOO MUCH BUT HOW I WISH I CAN SOME WHO CAN BROUGHT ME UP MORE THAN THIS HERE OOOOOOOOOOOO

Ibbaba: Hello nairaland mathematicians,am an undergraduate whose course deals with math(computer science),I wasn't that good in math while in secondary school as a result of my foundation and also my math secondary school teacher but I have so much fasion for math,I really would love to be tutoring others in math like I kinder see lovely student in my school do(they love calculations to anything else)
*have gone through my general math text and a furthermath text we used in secondary school then,now what I want is TO GET MYSELF TEXT BOOKS THAT WILL ADD VALUE AND ALSO HELP ME KNOW MUCH OF MATH,SO PLEASE RECOMEND ALEVEL TEXT BOOKS FOR ME,AND WHERE DO I GET THEM,I HEARD ABOUT OJU ELEGBA IN LAGOS,I'LL BE HEADING THERE TOMORROW.

go get engineering mathematics..after using that book, your "maths" life will never remain thesame again....
My sis gave hers to me as a gift some years back

Adol16: This is it solve for a 5loga(base 4) + 48log4(base a)= a/8.

SOLUTION
5log4 a + 48loga 4 = a/8
multiply thru by 8
40log4 a + 384loga 4 = a
next we convert log(base a) to log(base 4)

40log4 a + 384log4 4/log4 a = a

but log4 4 = 1
40log4 a + 384/log4 a = a

40(log4 a)² +384 =alog4 a
40(log4 a)² - alog4 a + 384 = 0
let log4 a = x...........(1)
40x² -ax + 384 =0 ............(2) solving simultaneously, x=4 and a=256
hence
a=256

Hey maths gurus wch of u guys lives in abeokuta, I wud like to get in contact wit you. Here is ma contact 08184135053

Ghettoguru: I hail all the gurus in the house. Nice works!

bro where av u been?