@mathefaro why not solve the number two please, wanna see the correction. . . .thanks

mathefaro:
Wrong, check ur substitution, u made a slight error. d ans is 105

You are right, though it's confusing too. . . .

a= 3/2, r= 3 and d= -9/2

substituting into the sum of the 5th term (a+4d+ar4) gives:

3/2 + 4(-9/2) + 3/2(3)^4

: 3/2 + 4 * -9/2 + 3/2 * 81

: 3/2 - 18/1 + 243/2

: 3/2 + 243/2 - 18/1

: 3 + 243 - 36 all over the LCM 2= 210/2 = 105 the most correct answer

mathefaro:
Wrong, check ur substitution, u made a slight error. d ans is 105

Yeah, I fixed the error; I substituted r for d. I did it in a rush! No offense Chief, but try to correct folks with your workings next time. This is not an exams hall, we are only here to help...

Check out this thread sometime and contribute

doubleDx:

Yeah, I have fixed the error; I substituted r for d. I did it in a rush! No offense Chief, but try to correct folks with your workings next time. This is not an exams hall, we are only here to help...

Check out this thread sometime and contribute

noted

Ortarico: @mathefaro why not solve the number two please, wanna see the correction. . . .thanks

You are right, though it's confusing too. . . .

a= 3/2, r= 3 and d= -9/2

substituting into the sum of the 5th term (a+4d+ar4) gives:

3/2 + 4(-9/2) + 3/2(3)^4

: 3/2 + 4 * -9/2 + 3/2 * 81

: 3/2 - 18/1 + 243/2

: 3/2 + 243/2 - 18/1

: 3 + 243 - 36 all over the LCM 2= 210/2 = 105 the most correct answer

let d cost of one article be = y
c.p of 20 articles = 20y
s.p = 20y + (16% of 20y)
s.p = 23.2y
c.p for 10 articles = 10y
s.p = 10y - (4% of 10)
s.p = 9.6y
total s.p = 9.6y + 23.2y
total s.p = 32.8y
total c.p=20y + 10y = 30y
total gain = 32.8 y - 30y
total gain = 2.8y
% gain =(2.8y x 100)/30y
%gain = 9.33%
This is the solution to the number two.
Sorry, I didn't see your message earlier, I only saw the one quoted under my reply.

mathefaro:
let d cost of one article be = y
c.p of 20 articles = 20y
s.p = 20y + (16% of 20y)
s.p = 23.2y
c.p for 10 articles = 10y
s.p = 10y - (4% of 10)
s.p = 9.6y
total s.p = 9.6y + 23.2y
total s.p = 32.8y
total c.p=20y + 10y = 30y
total gain = 32.8 y - 30y
total gain = 2.8y
% gain =(2.8y x 100)/30y
%gain = 9.33%
This is the solution to the number two.
Sorry, I didn't see your message earlier, I only saw the one quoted under my reply.

thanks my oga @mathefaro. By your real name "maths pharaoh", you too much. . .

Ortarico:

thanks my oga @mathefaro. By your real name "maths pharaoh", you too much. . .

lolz, not yet an oga....

mathefaro:
lolz, not yet an oga....

my oga why u kan fall my hænd na after announcing it?

Ortarico:

my oga why u kan fall my hænd na after announcing it?

My brother, he that thinks he's the best and an oga will fall indefinitely. Just because I have a knowledge of the subject, I must not think I'm the best or see my self as an oga because I'm very sure there are lots of people out there weep are far better than I am

mathefaro:
My brother, he that thinks he's the best and an oga will fall indefinitely

true talk jare no abasement for the humble

me sef gan wan solve.
throw me one

Show that:
sin^4@ - cos^4@= sin^2@ - cos^2@.
Let @ be teta.Pls wit d workings.

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