Collections.reverse(list);

TheLordIsGr8:
Is the list you will provide already sorted?

Will there be need to sort the list if it is not already sorted?

In python it's as easy as calling

input_list = sorted(input_list, reverse=False/True)

FrankLampard:
In Java

Collections.reverse(list);

Jenifa123:
Php

$preserved = array_reverse($input, true);

 
 1. Loli = ["Sweet", "Is"]
 2. newList = []
 3. for i in range(len(Loli)-1):
       newList += Loli.pop()
 4. print(newList)
 

badthinds:
logicalhumour is winning in Python group


4 lines

badthinds:


No no no.
1. No need to sort anything.
2. Do not use inbuilt methods

Just create a list and maybe, use a loop or however to reverse it.

TheLordIsGr8:
# Using python 3 list comprehensions
# you can just copy this post as is into jupyter notebook or any IDE and run it to verify

from random import randint # import random integer generator

ints = [randint(x, 10*x) for x in range(10)] # create a random list of integers

# Two lines for better understanding

k = len(ints)
rev_ints = [ints[k-1-i] for i in range(k)]
print(rev_ints)




# here the same code is as a one-liner. just substitute the value of k directly in the list comprehension

rev_ints = [ints[len(ints)-1-i] for i in range(len(ints))]



# Here it is using a list of strings

animals = ['goat', 'dog', 'cat', 'mouse']
rev_animals = [animals[len(animals)-1-i] for i in range(len(animals))]
print(rev_animals)

# If you need to change the original list all you need to do is to reassign the original list to the value of the reversed list like so

ints = rev_ints
animals = rev_animals

TheLordIsGr8:
# Using a recursive algorithm in 4 lines to reverse a string

1. def reverse_string(a_str):
2.     if a_str == '':
3.         return a_str
4.     return a_str[-1] + reverse_string(a_str[:-1])
5. print(reverse_string('nairaland'))

badthinds:


Please. Decide on one solution. Thanks

TheLordIsGr8:


Is this a kind of competition or something?

I have a one-liner. But I spread it on two lines for ease of understanding for some beginners who may be here.
Also I posted another solution which is not a solution to the problem at all, but for reversing a string, which could be viewed as a subset of a list.

Ok. here is my final solution in one line using python

Given a list, x, the list could be reversed in one line like so

x = [x[len(x)-1-i] for i in range(len(x))]

print(x)

badthinds:


Its a quiz...just for fun.

Great. Your new code is in two lines...but you didn't declare the list in it.

badthinds:
bjboss is first in Python group



3 lines

1. dic = {"lst": [1,2,3], "rev": dic["lst"][::-1] }
2. print dic["rev"]

def rev(*args):
	     return args[::-1] 

TheLordIsGr8:


I don't think you understand python very well.

Python doesn't do all this list declaration thing as in java, c++, fortran.
My code is still in one line which is

print([x[len(x)-1-i] for i in range(len(x))])

I am only spreading it out for ease of understanding.

Also, you won't really consider a print statement part of a code because it does nothing other than show you the result of all that has been done by the main code.
Either way, my code is a one-liner. I can break it down and explain if you'd like to see.

TheLordIsGr8:


I don't think you understand python very well.

Python doesn't do all this list declaration thing as in java, c++, fortran.
My code is still in one line which is

print([x[len(x)-1-i] for i in range(len(x))])

I am only spreading it out for ease of understanding.

Also, you won't really consider a print statement part of a code because it does nothing other than show you the result of all that has been done by the main code.
Either way, my code is a one-liner. I can break it down and explain if you'd like to see.

// 2 Lines

 1. let list = [1, 2, 3];
 2. for (var d=0, rev=[];d<list.length;d++)
    rev[rev.length] = list[list.length - d - 1];

  console.log(rev); 

  --------------------- 

 // 1 Line 

 1. var list=[1, 2, 3],
      rev = list.reduce((x, y, i)=>x.concat(list[list.length - i - 1]), []);

  console.log(rev); 

Kodejuice:
JavaScript

// 2 Lines

 1. let list = [1, 2, 3];
 2. for (var d=0, rev=[];d<list.length;d++)
    rev[rev.length] = list[list.length - d - 1];

  console.log(rev); 

  --------------------- 

 // 1 Line 

 1. var list=[1, 2, 3],
      rev = list.reduce((x, y, i)=>x.concat(list[list.length - i - 1]), []);

  console.log(rev); 

badthinds:
Many languages and nethods can be used.

The aim of this quiz is to write a program that reverses a list eg [1, 2, 3] ==> [3,2,1] with minimal lines of code.

The programmer with the minimal is the winner.
In whatever language you choose, your code shall be compared to those who choose same with you.

NOTE: On reaching a semicolon ( ; ), if no line break, it is considered as line++. (if not, I know guys will use one line. ))

Start Now. JUST FOR FUN!.

Edit:

Note:
1. Your code should show the declaration of the list
2. Method used in reversing the list.
3. Last line should print the list for confirmation.

Current List


Python Group

1. TheLordIsGr8 - 1 line (endeavour to add the missing piece)
2. kayoph - 2 lines
2. logicalhumour - 2 lines (edit)
3. bjboss - 3 lines
4. logicalhumour - 4 lines
5. TheLordIsGr8 - 5 lines

JavaScript

1. Kodejuice - 2 lines
2. Kodejuice - 3 lines

Java Group

Where are you guys?