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Pls Solve If U Can. Thanks by shankeke: 5:37am On Mar 28, 2018
1) two men started from the same point and walked in opposite directions. each man walked for 50 minutes and turned left, walked for another 20 minutes and stopped. how far apart are they, if each man walked at the same rate of 6km/hr?
Re: Pls Solve If U Can. Thanks by dejt4u(m): 7:02am On Mar 28, 2018
shankeke:
1) two men started from the same point and walked in opposite directions. each man walked for 50 minutes and turned left, walked for another 20 minutes and stopped. how far apart are they, if each man walked at the same rate of 6km/hr?
10.77km
Re: Pls Solve If U Can. Thanks by shankeke: 9:04am On Mar 28, 2018
dejt4u:
10.77km
Pls can u show the working.. thanks
Re: Pls Solve If U Can. Thanks by Sugar97(f): 9:19am On Mar 28, 2018
Both are a total of 140 minutes apart. That's (50 ×2) + (20×2).

They have a common speed of 6km/h.

The problem is to find distance (in km) when Time is 140 mins ( or 2 hrs. 20 mins) and speed is 6km/h.

Distance = speed × time. Therefore, distance between them is 2 1/3 × 6, that's 7/3 × 6 = 14 km

smiley
Re: Pls Solve If U Can. Thanks by Nobody: 9:21am On Mar 28, 2018
Sugar97:
Both are a total of 140 minutes apart. That's (50 ×2) + (20×2).

They have a common speed of 6km/h.

The problem is to find distance (in km) when Time is 140 mins ( or 2 hrs. 20 mins) and speed is 6km/h.

Distance = speed × time. Therefore, distance between them is 2 1/3 × 6, that's 7/3 × 6 = 14 km

smiley

Hmnn.
Guru
Re: Pls Solve If U Can. Thanks by Sugar97(f): 9:25am On Mar 28, 2018
DanXplore:


Hmnn.
Guru

Good u're here. Oya confirm it smiley
Re: Pls Solve If U Can. Thanks by Omuneizzy6(m): 9:31am On Mar 28, 2018
The answer has been given so thread closed.
Re: Pls Solve If U Can. Thanks by Nobody: 10:05am On Mar 28, 2018
Sugar97:

Good u're here. Oya confirm it smiley
I don't think you will like my 'confirmation' oh grin
Re: Pls Solve If U Can. Thanks by Sugar97(f): 10:12am On Mar 28, 2018
DanXplore:


I don't think you will like my 'confirmation' oh grin

Lol. Well, if it's wrong, pls say it so I don't mislead someone
Re: Pls Solve If U Can. Thanks by Nobody: 10:13am On Mar 28, 2018
Sugar97:


Lol. Well, if it's wrong, pls say it so I don't mislead someone

lol. detj4u is more correct
Re: Pls Solve If U Can. Thanks by Sugar97(f): 10:16am On Mar 28, 2018
DanXplore:


lol. detj4u is more correct

Lol. What does "more correct" mean? I thought it should be either correct or wrong
Re: Pls Solve If U Can. Thanks by Nobody: 10:18am On Mar 28, 2018
Sugar97:


Lol. What does "more correct" mean? I thought it should be either correct or wrong

you will have two congruent right angled triangles in opposite direction but touching each other at the point of intersection of their respective hypothenus and adjacent (longest line). Their distance apart is twice the length of the hypothenus of one triangle grin

1 Like

Re: Pls Solve If U Can. Thanks by Sugar97(f): 10:30am On Mar 28, 2018
DanXplore:


you will have two congruent right angled triangles in opposite direction but touching each other at the point of intersection of their respective hypothenus and adjacent (longest line). Their distance apart is twice the length of the hypothenus of one triangle grin

I agree, I considered it as a possible solution. But then, the question doesn't ask for the shortest possible distance and that's why I ignored it
Re: Pls Solve If U Can. Thanks by Nobody: 10:33am On Mar 28, 2018
Sugar97:


I agree, I considered it as a possible solution. But then, the question doesn't ask for the shortest possible distance and that's why I ignored it


Lol. you think say u get sense abi? I agree with you 100% though grin
Re: Pls Solve If U Can. Thanks by Sugar97(f): 10:40am On Mar 28, 2018
DanXplore:



Lol. you think say u get sense abi? I agree with you 100% though grin

Seriously, I considered both. I'm not trying to use sense cry cry

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