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If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) - Education - Nairaland

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If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by Mrshape: 12:14pm On May 05
Maths tutors/lecturers or professors have to be patient with does who are willing to learn,
You are their teacher because you learnt it first not because you are more intelligent.
Let's try this out I will bring solution tomorrow.
Hmmm
Everywhere Green.

Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by Mrshape: 12:21pm On May 05
Show workings
Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by Mrshape: 1:36pm On May 05
Anyone?
Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by femi4: 10:09pm On May 05
EA = AD = x

Diagonal = semicircle diameter = √(x²+x²) = x√2

Radius of semicircle = x√2/2

Now AF² = x² -(x√2/2)²

AF² = x² - 2x²/4 = x²/2

AF = x/√2

But AF + FG = 14√2
x/√2 + x√2/2 = 14√2
2x +2x = 4*14
x = 14
R of semi circle = x√2/2 = 7√2
r of the circle = 7√2/2

Area of the green region = Area of the semicircle - Area of the circle

π (7√2)²/2 - π (7√2/2)²

π(98/2 - 98/4) = π 98/4 = 22/7 * 98/4 = 77 units²
Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by Martinez39: 10:54pm On May 05
femi4:
EA = AD = x

Diagonal = semicircle diameter = √(x²+x²) = x√2

Radius of semicircle = x√2/2

Now AF² = x² -(x√2/2)²

AF² = x² - 2x²/4 = x²/2

AF = x/√2

But AF + FG = 14√2
x/√2 + x√2/2 = 14√2
2x +2x = 4*14
x = 14
R of semi circle = x√2/2 = 7√2
r of the circle = 7√2/2

Area of the green region = Area of the semicircle - Area of the circle

π (7√2)²/2 - π (7√2/2)²

π(98/2 - 98/4) = π 98/4 = 22/7 * 98/4 = 77 units²
You are correct. I got the same thing too.
Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by Mrshape: 6:36pm On May 06
femi4:
EA = AD = x

Diagonal = semicircle diameter = √(x²+x²) = x√2

Radius of semicircle = x√2/2

Now AF² = x² -(x√2/2)²

AF² = x² - 2x²/4 = x²/2


AF = x/√2

But AF + FG = 14√2
x/√2 + x√2/2 = 14√2
2x +2x = 4*14
x = 14
R of semi circle = x√2/2 = 7√2
r of the circle = 7√2/2

Area of the green region = Area of the semicircle - Area of the circle

π (7√2)²/2 - π (7√2/2)²

π(98/2 - 98/4) = π 98/4 = 22/7 * 98/4 = 77 units²
Good one sir √√√√√√√√√√√(11/10)
Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by naturalwaves: 5:27pm On Jun 12
Mrshape:

Good one sir √√√√√√√√√√√(11/10)
I bet you did not realise that there are a lot of badazz mathematicians on Nairaland. cheesy cheesy cheesy
Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by Mrshape: 5:30pm On Jun 12
naturalwaves:

I bet you did not realise that there are a lot of badazz mathematicians on Nairaland. cheesy cheesy cheesy
I have been fetching them out lately with my post sir,
It gives me joy to see like minds sir.
Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by naturalwaves: 5:33pm On Jun 12
Mrshape:

I have been fetching them out lately with my post sir,
It gives me joy to see like minds sir.
Lolz.
They are much o. I do not know the names you have on your list already. Perhaps I could add more.
Re: If You Can't Solve This As A Math Teacher, Hope You Wil Learn A Lesson(mr Shape) by Mrshape: 5:43pm On Jun 12
naturalwaves:

Lolz.
They are much o. I do not know the names you have on your list already. Perhaps I could add more.
Also check ifada123 thats my main account, go through my post you will see more of them.
I have a lot of them following me.

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