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## Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help - Education - Nairaland

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 Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by cole01: 3:12pm On Jun 12 Good afternoon people, am really in need of solutions to some questions and I'll be glad if my thread is being moved to FPLalasticlala, Mynd44, thanks Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 5:36pm On Jun 12 @cole01 This exercise requires a good knowledge of calculus. Here are the answers. 1) The domain is the interval (0, 1].2) The limit does not exist. 3) The gradient at (a, ρ) is -b²/aρ4) F'(x) = 245) The slope is undefined. Either it has a vertical tangent line of none at all. I will investigate the behaviour of the function later to conclude which is it.Edit: the tangent line doesn't exist. 6) a = 17) ½x³e2x - ¾x²e2x + ¾xe2x - ⅜e2x + C8} a = e and b = 1, e is the Euler's constant ie. the base of the natural logarithmic function.9) f(x) = x, a = 3 & b = -110) n = 1 Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by cole01: 6:00am On Jun 13 Regiomontanus:@cole01 This exercise requires a good knowledge of calculus. Here are the answers. 1) The domain is the interval (0, 1].2) The limit does not exist. 3) The gradient at (a, ρ) is -b²/aρ4) F'(x) = 245) The slope is undefined. Either it has a vertical tangent line of none at all. I will investigate the behaviour of the function later to conclude which is it.Edit: the tangent line doesn't exist. 6) a = 17) ½x³e2x - ¾x²e2x + ¾xe2x - ⅜e2x + C8} a = e and b = 1, e is the Euler's constant ie. the base of the natural logarithmic function.9) f(x) = x, a = 3 & b = -110) n = 1 RegiomontanusThank you very much sir, plz can I just get the picture of the solvings, I remain grateful Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by cole01: 9:29pm On Jun 13 [quote author=Regiomontanus post=79267919]@cole01 This exercise requires a good knowledge of calculus. Here are the answer please I've been waiting Sir, really need it urgently Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 9:45pm On Jun 13 cole01: please I've been waiting Sir, really need it urgently I have been busy. I will send them very soon. I need to eat first. Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by cole01: 10:10pm On Jun 13 Regiomontanus: I have been busy. I will send them very soon. I need to eat first. ok sir, thanks for ur reply Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by cole01: 8:23am On Jun 14 Regiomontanus: I have been busy. I will send them very soon. I need to eat first. Sir I've been waiting, submitting by 10am Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 9:12am On Jun 14 cole01:Sir I've been waiting, submitting by 10am Sorry, my day has been tight.1) if f(x) = g(x)h(x), then the domain of f(x) is the intersection of the domains of g(x) and h(x). The domain of g(x) = (1 - x)½ is (-∞, 1] and the domain of h(x) = ln x is the set of all positive numbers ie. the interval (0, ∞). Therefore the domain of f(x) = g(x)h(x) = (1 - x)½ ln x is (0, 1].Typing... cole01 Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 9:20am On Jun 14 2) the limit doesn't exist because on both sides of 0, the function approaches two different numbers (-1 from the left and 1 from the right).3) Find dy/dx for b²x² + a²y² = b²a² using implicit differentiation. We have 2b²x + 2a²y(dy/dx) = 0. Hence, dy/dx = -b²x/a²y. @ (a, p), dy/dx = -b²/apTyping... cole01 Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 9:30am On Jun 14 4) if F(x) = f(g(x)) then by the chain rule of differentiation, F'(x) = f'(g(x))g'(x). So F'(5) = f'(g(5))g'(5) if g(5) = -2 then f'(g(5)) = f'(-2) = 4 and g'(5) = 6. Therefore, F'(5) = (4)(6) = 24typing ...cole01 Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 9:44am On Jun 14 5) Using implicit differentiation to find dy/dx for cos x + sin y = 1 leads to -sin x + cos y (dy/dx) = 0 Therefore dy/dx = sin x / cos y , at (π/2, π/2) dy/dx = 1/0 = udf The tangent line is nonexistent.6) The points of intersection of both graphs are x = 0 and x = 1 and on the interval [0, 1], y1 = x2 - x + 3 is greater than or equal to y2 = x3 - x + 3. So integrate y1 - y2 = x2 - x3 from 0 to 1 and you will get 1/12. therefore a = 1typing...cole01 Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Brunicekid(m): 9:47am On Jun 14 Mathematics, the father of all subjects... Argue with your keypads.Meanwhile, i will try and solve the questions. 1 Like 1 Share Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 9:56am On Jun 14 7) You will have to use integration by parts repeatedly to get the answer. I can,t write them as I am on a bus. 8} An antiderivative of the integrand f(x) = (cos x)esin x is F(x) = esin x because F'(x) = f(x). Using the first fundamental theorem of calculus, the definite integral is esin π/2 - esin 0 = e1 - e0 = e - 1.Therefore a = e and b = 1 typing...cole01 Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 10:11am On Jun 14 sorry that this is coming too late,9) using long division (x3[sup]+x[sup]2+7)/(x2+x-2) can be written as x + [(2x+7)/(x2+x-2)] Apply the method of partial fraction to the proper rational expression ,(2x+7)/(x2+x-2) = (2x+7)/[(x-1)(x+2)] = A/(x-1) + B/(x+2) Multiply both sides with (x-1)(x+2), 2x+7 = A(x+2) + B(x-1). If x = 1 , A = 3 and if x = -2, B = -1. So (x3+x2+7)/(x2+x-2) = x + 3/(x-1) + -1/(x+2).therefore f(x) = x , A = 3 and B = -1typing... Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 10:13am On Jun 14 cole01, I am sorry for not sending the solutions on time. I was busy and exhausted. Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 10:18am On Jun 14 10) nx2 + 2x = 4 + 2x at x = 2 to ensure continuity. 4n + 4 = 8. therefore n = 1 the end. cole01 1 Like Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by cole01: 9:53pm On Jun 14 Regiomontanus:10) nx2 + 2x = 4 + 2x at x = 2 to ensure continuity. 4n + 4 = 8. therefore n = 1 the end. cole01Thanks Sir, am so so grateful for every thing,thanks Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 7:09am On Jun 15 cole01:Thanks Sir, am so so grateful for every thing,thanks Were you able to copy them and support? In case you have any maths questions, mention me. If I can solve them, I will and I will send the workings and answers as fast as possible. 1 Like Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by cole01: 12:29pm On Jun 29 Regiomontanus: Were you able to copy them and support? In case you have any maths questions, mention me. If I can solve them, I will and I will send the workings and answers as fast as possible. 1.The total area under the normal distribution curve equals?? Regiomontanus Thanks once again Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Regiomontanus(m): 9:15pm On Jun 29 cole01:1.The total area under the normal distribution curve equals?? Regiomontanus Thanks once again These questions are beyond my limit. I am not informed in probability and statistics. Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by cole01: 8:29pm On Jul 01 Regiomontanus: These questions are beyond my limit. I am not informed in probability and statistics. Ok brother,Thank you sir for helping, I appreciate Re: Plz Help!!urgent Need Of Solutions To Some Maths Problems,thanks As U Help by Cmanforall: 10:38pm On Jul 01 Regiomontanus: Were you able to copy them and support? In case you have any maths questions, mention me. If I can solve them, I will and I will send the workings and answers as fast as possible. This guy go dey exam hall, snap picture send you. You solve within a particular time frame.My advice: He should attend classes. Practice exercises. When faced with challenging questions, he can then bring them here. You can solve questions for him, don't get me wrong. But that time limit for showing your calculations should not be encouraged.#IStandAgainstExamMalpractice

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