Mayemavins:
1.Expand (2a+3b) *4 using pascal triangle
2: find the coefficient of (A+B) *5 and (A+B) *6

qwertyboss:

.........1
.......1 1
......1 2 1
.....1 3 3 1
....1 4 6 4 1
..1 5 10 10 5 1
.1 6 15 20 15 6 1
Above is the Pascal's triangle.
So we are going to use the row 1 4 6 4 1 as our coefficient for the expansion. Since it's power four in (2a+3b)⁴
Hence: (2a +3b)⁴ = 1*(2a)⁴ + 4*(2a)³(3b) + 6*(2a)²(3b)² + 4*(2a)(3b)³ + 1*(3b)⁴
=16a⁴ + 96a³b + 432a²b² + 216ab³ + 81b⁴

The coefficients of (A + B)**5 are 1 5 10 10 5 1
The coefficients of (A+ B)**6 are 1 6 15 20 15 6 1


Oyya bless my azza WEMA Bank:7811737820

qwertyboss:

.........1
.......1 1
......1 2 1
.....1 3 3 1
....1 4 6 4 1
..1 5 10 10 5 1
.1 6 15 20 15 6 1
Above is the Pascal's triangle.
So we are going to use the row 1 4 6 4 1 as our coefficient for the expansion. Since it's power four in (2a+3b)⁴
Hence: (2a +3b)⁴ = 1*(2a)⁴ + 4*(2a)³(3b) + 6*(2a)²(3b)² + 4*(2a)(3b)³ + 1*(3b)⁴
=16a⁴ + 96a³b + 432a²b² + 216ab³ + 81b⁴

The coefficients of (A + B)**5 are 1 5 10 10 5 1
The coefficients of (A+ B)**6 are 1 6 15 20 15 6 1


Oyya bless my azza WEMA Bank:7811737820
Bro I think this is what you are supposed to expand with 1 3 3 4 that's the fourth one

Mayemavins:

Seen
But Abeg make my lecturer Mark am first if e correct I go credit u inshallah on Monday

Mayemavins:

Seen
But Abeg make my lecturer Mark am first if e correct I go credit u inshallah on Monday

qwertyboss:

.........1
.......1 1
......1 2 1
.....1 3 3 1
....1 4 6 4 1
..1 5 10 10 5 1
.1 6 15 20 15 6 1
Above is the Pascal's triangle.
So we are going to use the row 1 4 6 4 1 as our coefficient for the expansion. Since it's power four in (2a+3b)⁴
Hence: (2a +3b)⁴ = 1*(2a)⁴ + 4*(2a)³(3b) + 6*(2a)²(3b)² + 4*(2a)(3b)³ + 1*(3b)⁴
=16a⁴ + 96a³b + 432a²b² + 216ab³ + 81b⁴

The coefficients of (A + B)**5 are 1 5 10 10 5 1
The coefficients of (A+ B)**6 are 1 6 15 20 15 6 1


Oyya bless my azza WEMA Bank:7811737820

seanwilliam:



Hmmm. Omo you suppose Dey work with better private university

qwertyboss:

.........1
.......1 1
......1 2 1
.....1 3 3 1
....1 4 6 4 1
..1 5 10 10 5 1
.1 6 15 20 15 6 1
Above is the Pascal's triangle.
So we are going to use the row 1 4 6 4 1 as our coefficient for the expansion. Since it's power four in (2a+3b)⁴
Hence: (2a +3b)⁴ = 1*(2a)⁴ + 4*(2a)³(3b) + 6*(2a)²(3b)² + 4*(2a)(3b)³ + 1*(3b)⁴
=16a⁴ + 96a³b + 432a²b² + 216ab³ + 81b⁴

The coefficients of (A + B)**5 are 1 5 10 10 5 1
The coefficients of (A+ B)**6 are 1 6 15 20 15 6 1


Oyya bless my azza WEMA Bank:7811737820

MyVILLAGEpeople:


Which one be Pascal triangle again.

Mayemavins:

Seen
But Abeg make my lecturer Mark am first if e correct I go credit u inshallah on Monday

Mayemavins:
1.Expand (2a+3b) *4 using pascal triangle
2: find the coefficient of (A+B) *5 and (A+B) *6

qwertyboss:

The coefficients of the terms of an algebraic expression:
Like X has 1 as it's coefficient
X+Y has 1 and 1 as coefficients of it terms
(X+y)²= x²+2xy+y² has 1, 2 and 1 as coefficients of it terms
(X+y)³=x³+3x²y+3xy²+y³ has 1, 3, 3 and 1as it's coefficient.

So Blaise Pascal a renown scientists discover tha the coefficients forms a triangle starting from a single to a triple term...
.......1 single term expression
......1 1 double term expression
.....1 2 1 triple term expression

So Pascal's observed that the coefficients for quadruple term can be obtained by adding the first two terms of the previous coefficients in sequence after putting down 1 as the first and last coefficients of the current expression.
Like 1 (1+2) (2+1) 1 which gives 1 3 3 1
Which corresponds to the coefficients of the expansion of (X+y)³
The next row of coefficients can also be obtained using 1 3 3 1
As 1 (1+3) (3+3) (3+1) 1 which gives 1 4 6 4 1
An expansion for (X+y)⁴
That's how he construct the traingle which can be applied to expansion of higher polynomials with ease like (X+y)¹² and so on before the discovery of permutation and combination which further makes the process very easier by eliminating the need for the triangle

FatherCHRISTMAS:
You tried qwertyboss
I got -1Ax + -22y as my final answer

qwertyboss:

That's mathematics for you
You know they said understanding the question is half of the answer...
The post is properly written as (2a + 3b)⁴...
I believe many people skipped it because they didn't comprehend (2a + 3b)*4 because one * means multiplication, is double ** that means raised to the power of...
After all this is just a silly maths compare to advance power series like the Tailor's, Fourier's or McLaren's series

qwertyboss:

That's mathematics for you
You know they said understanding the question is half of the answer...
The post is properly written as (2a + 3b)⁴...
I believe many people skipped it because they didn't comprehend (2a + 3b)*4 because one * means multiplication, is double ** that means raised to the power of...
After all this is just a silly maths compare to advance power series like the Tailor's, Fourier's or McLaren's series

qwertyboss:

That's mathematics for you
You know they said understanding the question is half of the answer...
The post is properly written as (2a + 3b)⁴...
I believe many people skipped it because they didn't comprehend (2a + 3b)*4 because one * means multiplication, is double ** that means raised to the power of...
After all this is just a silly maths compare to advance power series like the Tailor's, Fourier's or McLaren's series

qwertyboss:

.........1
.......1 1
......1 2 1
.....1 3 3 1
....1 4 6 4 1
..1 5 10 10 5 1
.1 6 15 20 15 6 1
Above is the Pascal's triangle.
So we are going to use the row 1 4 6 4 1 as our coefficient for the expansion. Since it's power four in (2a+3b)⁴
Hence: (2a +3b)⁴ = 1*(2a)⁴ + 4*(2a)³(3b) + 6*(2a)²(3b)² + 4*(2a)(3b)³ + 1*(3b)⁴
=16a⁴ + 96a³b + 432a²b² + 216ab³ + 81b⁴

The coefficients of (A + B)**5 are 1 5 10 10 5 1
The coefficients of (A+ B)**6 are 1 6 15 20 15 6 1


Oyya bless my azza WEMA Bank:7811737820

qwertyboss:

.........1
.......1 1
......1 2 1
.....1 3 3 1
....1 4 6 4 1
..1 5 10 10 5 1
.1 6 15 20 15 6 1
Above is the Pascal's triangle.
So we are going to use the row 1 4 6 4 1 as our coefficient for the expansion. Since it's power four in (2a+3b)⁴
Hence: (2a +3b)⁴ = 1*(2a)⁴ + 4*(2a)³(3b) + 6*(2a)²(3b)² + 4*(2a)(3b)³ + 1*(3b)⁴
=16a⁴ + 96a³b + 432a²b² + 216ab³ + 81b⁴

The coefficients of (A + B)**5 are 1 5 10 10 5 1
The coefficients of (A+ B)**6 are 1 6 15 20 15 6 1


Oyya bless my azza WEMA Bank:7811737820

Mayemavins:

Seen
But Abeg make my lecturer Mark am first if e correct I go credit u inshallah on Monday

Ihatebuhariwith:
did na fss 201 for eksu

Mayemavins:

Seen
But Abeg make my lecturer Mark am first if e correct I go credit u inshallah on Monday

lordbeans:


Unfortunately there was a mistake in your calculation. I am surprised no one caught it. 432 should be 216. The concept is correct but computation wrong.