Bryan and Kathleen live 150miles apart. They each drive towards the other's house along a straight road connecting the two. Bryan drives @ a constant rate of 30M/hr and kath drives @ 50 M/hr. If Bryan and kath leave dia houses @ d same time, how many miles are they from bryans house when they meet?

150 miles

ALVA001:
Bryan and Kathleen live 150miles apart. They each drive towards the other's house along a straight road connecting the two. Bryan drives @ a constant rate of 30M/hr and kath drives @ 50 M/hr. If Bryan and kath leave dia houses @ d same time, how many miles are they from bryans house when they meet?

i know this is more of physics than maths. velocity. speed. distance and time must come into play

for how long do they drive?? ur question is incomplete, pls review it

boujaye:


i know this is more of physics than maths. velocity. speed. distance and time must come into play

Actually is a mathematics question ,simple algebra
(and Logic)
Distance = Speed X Time


When they meet they would both have been travelling for the same time T and the distance covered by both of them would be 150

So

150 = 30T + 50T
= 80T
they will meet after 150/80T
=1.875 hours

Brian would have travelled
1.875 X 30 km =56.25 km
while Kath would have travelled
1.875 x 50 m
= 93.75 km

93.75 + 56.25 = 150

So they will be 56.25 from Brian's and 93.75 from Kath's

This is a JSS question

Why is this question in the politics section

ALVA001:
Bryan and Kathleen live 150miles apart. They each drive towards the other's house along a straight road connecting the two. Bryan drives @ a constant rate of 30M/hr and kath drives @ 50 M/hr. If Bryan and kath leave dia houses @ d same time, how many miles are they from bryans house when they meet?

60 mins = 1hr
therefore
kath drives @ 50 miles in 60 mins
while Bryan drive @ 30 mins in 60 mins
kath and Bryan will drive for 1hr 52 mins and 30 secs and the distance from BRYAN'S HOUSE will be 56.25 miles when they both meet.
Kath will cover 93.75 miles and Bryan will cover 56.25 miles.
Don't asked me working

omonnakoda:

Actually is a mathematics question ,simple algebra
(and Logic)
Distance = Speed X Time


When they meet they would both have been travelling for the same time T and the distance covered by both of them would be 150

So

150 = 30T + 50T
= 80T
they will meet after 150/80T
=1.875 hours

Brian would have travelled
1.875 X 30 km =56.25 km
while Kath would have travelled
1.875 x 50 m
= 93.75 km

93.75 + 56.25 = 150

So they will be 56.25 from Brian's and 93.75 from Kath's

This is a JSS question

Why is this question in the politics section

you see how people they fail.
what the s.I unit in miles or kilometres!
so marking scheme
content=1 out of 5
Objective=3 out of 5
expression=3 out of 5
accuracy=0 out of 5



total marks scored=7 out of 20!(35%)

baralatie:

you see how people they fail.
what the s.I unit in miles or kilometres!
so marking scheme
content=1 out of 5
Objective=3 out of 5
expression=3 out of 5
accuracy=0 out of 5



total marks scored=7 out of 20!(35%)

Nearly funny

eminikansoso:

60 mins = 1hr
therefore
kath drives @ 50 miles in 60 mins
while Bryan drive @ 30 mins in 60 mins
kath and Bryan will drive for 1hr 52 mins and 30 secs and the distance from BRYAN'S HOUSE will be 56.25 miles when they both meet.
Kath will cover 93.75 miles and Bryan will cover 56.25 miles.
Don't asked me working

I am using university of Ife marking scheme

content=1.5 out of 5
objective=1.5 out of 5
expression=1 out of 5
accuracy=0 out of 5


total marks =4 out of 20(20%)

omonnakoda:

Nearly funny

if you know how boys in the engineering faculty are bursting the brains in msths .it is not funny ra ra!
I don't understand how they pass in that faculty

And you knew I can't answer it yet you went ahead to ask it now what will you call that

omonnakoda:

Actually is a mathematics question ,simple algebra
(and Logic)
Distance = Speed X Time


When they meet they would both have been travelling for the same time T and the distance covered by both of them would be 150

So

150 = 30T + 50T
= 80T
they will meet after 150/80T
=1.875 hours

Brian would have travelled
1.875 X 30 km =56.25 km
while Kath would have travelled
1.875 x 50 m
= 93.75 km

93.75 + 56.25 = 150

So they will be 56.25 from Brian's and 93.75 from Kath's

This is a JSS question

Why is this question in the politics section

THANK YOU.

I HAD APPROXIMATED IT TO BRYAN 56MILES AND KATHLEEN 94 MILES.

THEN I SCROLLED DOWN TO FIND YOUR METICULOUS WORK.

BRAVO. THOUGH A SIMPLE ONE FOR AVERAGE SCIENCE STUDENT.

YOUR UNIT ALSO CHANGED FROM MILES TO KILOMETRES

all calculations av been done assuming time they drove to b 1hr whereas d question didnt state it

,

princy80:
all calculations av been done assuming time they drove to b 1hr whereas d question didnt state it

What are you talking about?

Please keep quiet and stop typing rubbish

Must you talk?

56.25miles

Oops! this got me remembering my jamb days

omonnakoda:

Actually is a mathematics question ,simple algebra
(and Logic)
Distance = Speed X Time


When they meet they would both have been travelling for the same time T and the distance covered by both of them would be 150

So

150 = 30T + 50T
= 80T
they will meet after 150/80T
=1.875 hours

Brian would have travelled
1.875 X 30 km =56.25 km
while Kath would have travelled
1.875 x 50 m
= 93.75 km

93.75 + 56.25 = 150

So they will be 56.25 from Brian's and 93.75 from Kath's

This is a JSS question

Why is this question in the politics section

Beautiful work but you will lose marks for your miraculous change in units (miles to Km)

omonnakoda:

What are you talking about?

Please keep quiet and stop typing rubbish

Must you talk?

You dont have to be harsh in your response... no be everybody must sabi book

omonnakoda:

Actually is a mathematics question ,simple algebra
(and Logic)
Distance = Speed X Time


When they meet they would both have been travelling for the same time T and the distance covered by both of them would be 150

So

150 = 30T + 50T
= 80T
they will meet after 150/80T
=1.875 hours

Brian would have travelled
1.875 X 30 km =56.25 km
while Kath would have travelled
1.875 x 50 m
= 93.75 km

93.75 + 56.25 = 150

So they will be 56.25 from Brian's and 93.75 from Kath's

This is a JSS question

Why is this question in the politics section

You are implying they are moving at the same time T in your first equation.

PappyMason:



You are implying they are moving at the same time T in your first equation.

What is your point?

PappyMason:



You are implying they are moving at the same time T in your first equation.

Even though the distance travelled by each would vary, but the two must meet at the same time elapsed. After all, both left home at the same time.

The distance has been stated in d question
....150miles QED since the question is incomplete and not stating where the distance shld be measured. Is it from point C (final distance) or from the initial distance.
We just ve to assume dat the distance still remain at same place at time 0s moving at the same constand velocity

Volksfuhrer:


Even though the distance travelled by each would vary, but the two must meet at the same time elapsed. After all, both left home at the same time.

Alright

ALVA001:
Bryan and Kathleen live 150miles apart. They each drive towards the other's house along a straight road connecting the two. Bryan drives @ a constant rate of 30M/hr and kath drives @ 50 M/hr. If Bryan and kath leave dia houses @ d same time, how many miles are they from bryans house when they meet?

go and do your homework.