jayphe:

Exercise 5
Write a Python program that accepts a string and a character from the user. The program checks the number of times(frequency) the character appeared in the string. E.g. If the user enters "Michael Faraday" as the string and enters 'a' as the character, the program should display:

There are 4 a in Michael Faraday!

Collinsanele Taofeekdboy kensmoney Daddyshome Zabiboy

kensmoney:
ken="kensmoney is good boy"
def count_char(a,b): char = b.lower() stri = a.lower() counter=0 for a in stri: if a == char: counter += 1
print(counter)


count_char(ken, "o" ) #4

jayphe:

Collinsanele Taofeekdboy kensmoney Daddyshome Zabiboy

hmm....who else ooo? Let's get to business. Pls, let's try to read the question in details first. If the question asks for the users' input, then we should include an input statement. Zabiboy we need to talk ooo. This one wey I no see you....

Exercise 4
We are doing some 'loop and looping stuffs' today.

Write a Python program that accepts the name of a student, matric number, course code and the score he/she got in the course. E.g
Name: John Alfred
Matric. No.: MUC/CS/014/0882
Course Code: CMP 212
Score: 100

The program then print the result as:
John Alfred, MUC/CS/014/0882, CMP 212, Grade A

Using this grading table.
100-95 A
94-85 B
84-70 C
69-60 D
59-50 E
49-0 F

Corrections, advices, suggestions and opinions are highly welcome!

jayphe:

Exercise 6
Write a Python program that accepts an integer number and checks if it is an even number or an odd number. Pls don't use the % (modulus) operator. Let's see some genuius.

def check_type(val):
    _type = 'even' if val & 1 == 0 else 'odd'
    return _type

jayphe:

Exercise 6
Write a Python program that accepts an integer number and checks if it is an even number or an odd number. Pls don't use the % (modulus) operator. Let's see some genuius.

nwele2017:


numbers=list(range(1,10000000))
even_number=int(input("Input a number:\n" ))
for i in numbers:
if (even_number/2)==i:
print(str(even_number)+" is even an number" )

Collinsanele:


def count_char(string, char):
return "There are "+ str(string.lower().count(char)) + " "+ str(char) + " in " + string



print(count_char(string="Michael Faraday", char='a'))

def check_num(nums):
	num = nums/2
	check = num.is_integer()
	if check == True:
		print("even" )
	else:
		print("odd" )
check_num(5)

SKYQUEST:
Great job guys!

Write a python program where python LOOKS FOR Total Assets and Total liabilities in the attached table and returns the value of the ratio of the two given variables as per their values in the table.

scarplanet:


Is this a job at your workplace or an assignment given to you? Oya confess

jayphe:
I welcome every Python Lords to this thread. Hmm....I don't seem to know you guys by name buh you can tell me to mention you in my next post.
Alright guys let's get this straight. This is not a tutorial thread...buh it can be of help sha. This is a place where we can ask ourselves 'Python' questions and share ideas.
Please welcome me home!

SKYQUEST:
Great job guys!

Write a python program where python LOOKS FOR Total Assets and Total liabilities in the attached table and returns the value of the ratio of the two given variables as per their values in the table.

Daddyshome:

Note: I am a beginner, so don't expect clean code. Also, I suck at naming variables . It can definitely be improved upon. I can protect the code with trys here and there, to prevent certain errors. I don't know if the list is necessary, but I don't know any way to sort dictionaries by time or maybe I should have stored the contacts using another data type. Criticism is welcome


contacts = dict()
contacts_date = list()


def save_contact(name, number):
contacts[name] = number
contacts_date.append([name, number])
print('contact saved')

def display_contact_alphabetical():
print('Name\tNumbers')
for i, j in sorted(contacts.items()):
print( '{}\t{}'.format(i, j))


def delete(name):
contacts_date.remove([name, contacts[name]])
del contacts[name]
print('contact deleted')

def display_contact_date():
for a, b in contacts_date:
print('{}\t{}'.format(a, b))


def edit_contact_name(old_name, new_name):
tmp = contacts[new_name]
delete(old_name)
save_contact(new_name, tmp)
print('Contact information updated')


def edit_contact_num(name, new_num):
delete(name)
save_contact(name, new_num)
print('Contact information updated')


while True:
print('Press \n1. To save a contact\n2. To display contats\n3. To delete a contact\n4. To edit a contact\n5. To quit')
user_input = int(input())
if user_input == 1:
response_to_one = input('Enter name and number')
cont_name, cont_num = response_to_one.split()
save_contact(cont_name, cont_num)
elif user_input == 2:
print('Press \n1. To display alphabetically\n2. To display by time')
reply = int(input())
if reply == 1:
display_contact_alphabetical()
elif reply == 2:
display_contact_date()
elif user_input == 3:
response_to_three = input('Enter name')
delete(response_to_three)
elif user_input == 4:
print('Press \n1. To edit contact name\n2. To edit contact number')
reply_two = int(input())
if reply_two == 1:
reply_two_one = input('Enter old name and new name')
old_name, new_name = reply_two_one.split()
edit_contact_name(old_name, new_name)
elif reply_two == 2:
reply_two_two = input('Enter name and number')
cont_name, cont_num = reply_two_two.split()
edit_contact_num(cont_name, cont_num)
elif user_input == 5:
print('Exiting')
break

kensmoney:
def Grade():
name = str(input("name:" ))
matric = str(input("matric:" ))
code =str(input("course code:" ))
score=int(input("score:" ))
if score <= 100 and score >=95:
print(name,matric,code, "Grade: A" )
elif score <= 94 and score >=85:
print(name, matric, code, "Grade: B" )
elif score <= 69 and score >=60:
print( name, matric, code,"Grade: D" )
elif score <= 59 and score >=50:
print(name, matric, code, "Grade: E" )
else:
print(name, matric, code, "Grade: F" )




Grade()

Collinsanele:


Write a function that takes a list of numbers and returns the first unique number in the list.
(You may submit your solutions via pastebin)

Example:
[1,4,6,1,8,4,9] -> returns 6

print('hello word')

Collinsanele:


contact _date list is misleading as there aren't any date in it (Lol).

To use dates in Python, you can make use of the datetime module, it's straight forward, however, nice program.

Daddyshome:

Note: I am a beginner, so don't expect clean code. Also, I suck at naming variables . It can definitely be improved upon. I can protect the code with trys here and there, to prevent certain errors. I don't know if the list is necessary, but I don't know any way to sort dictionaries by time or maybe I should have stored the contacts using another data type. Criticism is welcome

contacts = dict()
contacts_date = list()


def save_contact(name, number):
    contacts[name] = number
    contacts_date.append([name, number])
    print('contact saved')

def display_contact_alphabetical():
    print('Name\tNumbers')
    for i, j in sorted(contacts.items()):
        print( '{}\t{}'.format(i, j))


def delete(name):
    contacts_date.remove([name, contacts[name]])
    del contacts[name]
    print('contact deleted')

def display_contact_date():
    for a, b in contacts_date:
        print('{}\t{}'.format(a, b))


def edit_contact_name(old_name, new_name):
    tmp = contacts[new_name]
    delete(old_name)
    save_contact(new_name, tmp)
    print('Contact information updated')


def edit_contact_num(name, new_num):
    delete(name)
    save_contact(name, new_num)
    print('Contact information updated')


while True:
    print('Press \n1. To save a contact\n2. To display contats\n3. To delete a contact\n4. To edit a contact\n5. To quit')
    user_input = int(input())
    if user_input == 1:
        response_to_one = input('Enter name and number')
        cont_name, cont_num = response_to_one.split()
        save_contact(cont_name, cont_num)
    elif user_input == 2:
        print('Press \n1. To display alphabetically\n2. To display by time')
        reply = int(input())
        if reply == 1:
            display_contact_alphabetical()
        elif reply == 2:
            display_contact_date()
    elif user_input == 3:
        response_to_three = input('Enter name')
        delete(response_to_three)
    elif user_input == 4:
        print('Press \n1. To edit contact name\n2. To edit contact number')
        reply_two = int(input())
        if reply_two == 1:
            reply_two_one = input('Enter old name and new name')
            old_name, new_name = reply_two_one.split()
            edit_contact_name(old_name, new_name)
        elif reply_two == 2:
            reply_two_two = input('Enter  name and number')
            cont_name, cont_num = reply_two_two.split()
            edit_contact_num(cont_name, cont_num)
    elif user_input == 5:
        print('Exiting')
        break

gbolly1151:


Nice one...by the time you learn class...you will really appreciate what you have done here,this is good for a start

jayphe:

Exercise 6
Write a Python program that accepts an integer number and checks if it is an even number or an odd number. Pls don't use the % (modulus) operator. Let's see some genuius.

Collinsanele:


Write a function that takes a list of numbers and returns the first unique number in the list.
(You may submit your solutions via pastebin)

Example:
[1,4,6,1,8,4,9] -> returns 6

jayphe:

Exercise 6
Write a Python program that accepts an integer number and checks if it is an even number or an odd number. Pls don't use the % (modulus) operator. Let's see some genuius.

num=int(input('your num '))
status='even' if (bin(num)).endswith('0') else 'odd'
print(status)

Collinsanele:


Can be easily done with pandas

kensmoney:
ken="kensmoney is good boy"

def count_char(a,b):
char = b.lower()
stri = a.lower()
counter=0
for a in stri:
if a == char:
counter += 1

print(counter)



count_char(ken, "o" )
#4

ken="kensmoney is good boy"

def count_char(a,b):
    char = b.lower()
    stri = a.lower()
    counter=0
    for a in stri:
        if a == char:
    counter += 1

print(counter)



count_char(ken, "o" )
#4

gbolly1151:
Guy when you are posting code,you can use this format

[Code]
#Your code here

[/Code]

Change the C to c

Example of output is

print('hello word')

kensmoney:

ken="kensmoney is good boy"

def count_char(a,b):
    char = b.lower()
    stri = a.lower()
    counter=0
    for a in stri:
        if a == char:
    counter += 1

print(counter)



count_char(ken, "o" )
#4

SKYQUEST:


lets have your solution sir

Daddyshome:

lis = [1, 4, 6, 1, 8, 4, 9]
unique = [x for x in lis if lis.count(x) == 1]
print(unique[0])