YoungDaNaval:
Wow

yeah

Solved

itstinaofficial:

x^(1/√x)=2

x=2^√x

let y=√x

x=2^y

x-2^y=0

x=y²

y²=2^y

hence y=2

x=2²

x=4

I think there are some issues here.

itstinaofficial:

yeah

Hey, let's be friends

Najdorf:

I think there are some issues here.

Point them out

Alao046:
Solve for X anyone. I have already given the answer, but solve to get it.
Lets see how good you are

x^(1/√x)=2
applying natural log
In(x^(1/√x)=In2
(1/√x)Inx=In2
(x^-1/2)Inx=In2
since e^In=1
(e^In(x^-1/2)Inx=In2
(e^-1/2Inx)Inx=In2
multiplying both sides by -1/2
(e^-1/2Inx)(Inx*-1/2)=(-1/2)(In2)
(e^-1/2Inx)(-1/2Inx)=-1/(2In2)
since. W(xe^x)=x
adding W to both sides
-1/2Inx=W(-1/(2In2))
multiplying by -2
Inx=-2W(-1/(2In2)
e^Inx=e^-2W(-1/(2In2)
x=e^-2W((-1/2In2))
x will have 4 solutions including 2 complex solutions
don't have the Wolfram alpha but I'm sure x=4

Spartancosta:

x^(1/√x)=2
applying natural log
In(x^(1/√x)=In2
(1/√x)Inx=In2
(x^-1/2)Inx=In2
since e^Inx=x
(e^In(x^-1/2)Inx=In2
(e^-1/2Inx)Inx=In2
multiplying both sides by -1/2
(e^-1/2Inx)(Inx*-1/2)=(-1/2)(In2)
(e^-1/2Inx)(-1/2Inx)=-1/(2In2)
since. W(xe^x)=x
adding W to both sides
-1/2Inx=W(-1/(2In2))
multiplying by -2
Inx=-2W(-1/(2In2)
e^Inx=e^-2W(-1/(2In2)
x=e^-2W((-1/2In2))
x will have 4 solutions including 2 complex solutions
don't have the Wolfram alpha but I'm sure x=4

Fixed
e^x and lnx are the inverses of each other

YoungDaNaval:
Point them out

The only/ main issue is the conclusion

"hence y = 2" as a solution to the equation y² = 2^y.

It is tantamount to the following
x^(1/√x)=2
Hence x = 4

mathefaro:
Fixed e^x and lnx are the inverses of each other

I don't get you?

mathefaro:
Fixed e^x and lnx are the inverses of each other

yeah In(e^x)=e^(Inx)

Spartancosta:

I don't get you?

what I meant was that. It is not really correct to say
e^ln = 1
There has to be an argument to the log function.

mathefaro:
what I meant was that. It is not really correct to say
e^ln = 1
There has to be an argument to the log function.

you are right

Derive the rules of pascal triangle and solve this using pascal triangle and correct to 2d.p
(1.01)4

ayubasodeeq:
Derive the rules of pascal triangle and solve this using pascal triangle and correct to 2d.p
(1.01)4

(a+b)⁴=a⁴+4a³b+6a²b²+4ab³+b⁴
(1.01)=(1+0.01)
1=a
0.01=b
(1.01)⁴=1⁴+4(1³)(0.01)+6(1²)(0.01)²+4(1)(0.01)³+(0.01)⁴
will modify this later, I'm typing on the road
1⁴+4(0.01)+6(0.0001)+4(0.000001)+0.00000001
1+0.04+0.0006+0.000004+0.00000001
=1.04060401
=1.041(app.)

Wow,I had no idea there was a thread like this,I need someone to solve these questions

simiife:
Wow,I had no idea there was a thread like this,I need someone to solve these questions

1.nth term =3^(n-1)
1st term =3^(1-1)=3°=1
2nd=3^(1-2)=3^-¹=1/3
3rd=3^(1-3)=3^-²=1/9
sum =1/3+1/9=(4/9)+1=13/9
2.
81^(3/4) -27^(1/3)/(3*2³)
(⁴√81)³-(³√27)/(3*2³)
(3)³-(3)/3*2³
=27-3/(3*2³)
24/(3*2³)
24/24=1
4.
sum of interior angles =(180n-360)
1800=180n-360
1800+360=180n
2160=180n
n=2160/180=12
number of sides =12
each angle=1800/12=150°
sum of interior angles and exterior angle of a regular polygon =180
150+e=180
e=180-150
e=30°
3.
y=x³-x
differentiating
y=3x²-1
solving the quadratic equation
a=3,b=0,c=-1
=(√-(4*3*-1))/2*3
=(√12)/6
=2√3/6
=√3/3

Spartancosta:
(a+b)⁴=a⁴+4a³b+6a²b²+4ab³+b⁴ (1.01)=(1+0.01) 1=a 0.01=b (1.01)⁴=1⁴+4(1³)(0.01)+6(1²)(0.01)²+4(1)(0.01)³+(0.01)⁴ will modify this later, I'm typing on the road 1⁴+4(0.01)+6(0.0001)+4(0.000001)+0.00000001 1+0.04+0.0006+0.000004+0.00000001 =1.04060401 =1.041(app.)

Are you a teacher

ayubasodeeq:
Are you a teacher

no sir

Najdorf:
I think there are some issues here.

where exactly?

itstinaofficial:

where exactly?

I've stated the issue in a post up there

Help me solve this please

Anyone please

Entrepreneurrr:
Help me solve this please

Have you attempted solving it? If you have, where exactly did you get stuck? Let me know so I can take it up from there.

simiife:
Anyone please

Have you attempted solving them? If you have, where exactly did you get stuck? Let me know so I can take it up from there.

Entrepreneurrr:
Help me solve this please

The answer to the second question is x=5/4

simiife:
Anyone please

the second question Is not clear..is is 2√x-1/x ??

Obinoscopy:
Have you attempted solving it? If you have, where exactly did you get stuck? Let me know so I can take it up from there.

Exactly. It feels like he hasn't even looked at the questions at all.

Obinoscopy:
Have you attempted solving it? If you have, where exactly did you get stuck? Let me know so I can take it up from there.

For the first question I didn’t try it because I don’t know how to evaluate different bases.


The second one, i tried but i don’t think i got it right (see the workings)

Najdorf:

Exactly. It feels like he hasn't even looked at the questions at all.

Its not like that I haven’t learn mathematics for the fast 6 years, so my brain is not that active their.

I am trying to brush up my brain

yusman14:
the second question Is not clear..is is 2√x-1/x ??

No be 1?

Dy/dx = 2rtX/X - 1

= 2*1/1 -1

= 1

Then again maybe it 1/x the problem is not clear

Entrepreneurrr:
Help me solve this please

X=5/4

Entrepreneurrr:


For the first question I didn’t try it because I don’t know how to evaluate different bases.


The second one, i tried but i don’t think i got it right (see the workings)

This is what you need.