₦airaland Forum

Chiamaka01:
Last year, resumption dates were fixed between the 11th and 13th of November.

wow tnx..wats ur combo?

mathefaro:
First and foremost, convert the average velocity to m/s by multiplying by 5/18
==> v = 54 * 5/18 = 15m/s;
Then recall that distance = average velocity * time taken i.e. S = vt
S = ?; v = 15m/s; t = 10s
Therefore, S = 15 * 10 = 150m


Since the car started from rest, initial velocity, u = 0, v = 30m/s; t = 6a; a = v/t = 30/6 = 5m/s²; S = ?
So with the available parameters, S, u, a and t, the appropriate equation to use is S = ut + (1/2)*at²;
Therefore, S = 0(6) + 0.5*5*36
S = 0+ 90
S = 90m


V - U = 5m/s; t = 30s; U = 20m/s;
a = (V - U)/t = 5/30 = 1/6m/s²
S =ut + ½at²
S = 20(30) + ½*1/6*30*30
==> S =600 + 75
==> S = 675m

u = 50m/s; v = 0; t = ?, g = 10m/s²
=> V = u - gt (minus because the body is going up against gravity)
=> 0 = 50 - 10t
=> 10t = 50
=> t = 5s

Good morning lovely people

although I understand all ur soln but for d no 1 I want to knw y u divided by 5/18 inorder to convert to m/s. For no 2 I want to knw y we can't just solve straight by usin d=vt cos if I use dz formular I wil get 180 rada dan 90. Nd 4 no 4 whr did u arrive at d formula v=u-gt..thanx

chimhigher:
No 2...d magnitude wuld b Mgsin@ = 30*10*sin30=300sin30= 150N

ok seriously I don't get this solution..why didn't u use 50N in the soln nd we were not told it was sin 30 so hw did u knw its sin 30..lastly, this @ wat dos dat min in phySics cos I have never seen dat b4..lest i forget, is d 10 there cos of d g(acc due to gravity)?

Umartins1:
I remain on my two tentacles to support my claims.

Has is singular, had is plural. Have is the past tense of both.

Seun Osewa had verified his account.

Seun Osewa have clarified his account.


Which is correct if I'm referring to the past?

none

Ok..pls does an1 have a clue wen pd studs usually resume? Lyk month to b precise