benbuks: guys ..i made mistake in that abelian question

seems d.done was right!!
i make corrections later .....

benbuks: fastest fingers first


compute

lim as n--> infinity

of [5 ⁽ⁿ⁺¹⁾ + 7⁽ⁿ⁺¹⁾ / (5ⁿ - 7ⁿ ]



correct answer only ....

benbuks: ok

i give you 10mins ....if no1 gets it

then i post another question.



a winner must emerge ....

benbuks: Q1..

given x^y=y^x

prove that

y' =(y/x)[(xlny-y) /(ylnx-x) ]

benbuks: integrate xe^2x dx



asap..

(xe^2x)/2 - (e^2x)/4

benbuks:

it invites the use of partial fractions not. . trig.

benbuks: DRNIYI4U.--------------2PTS

KENDYZMA-------------2PTS

benbuks: Q4 $dx/(x^2 -1)

benbuks: Q4 f the rate at which EVD spreads in west Africa is given by the function f(t)=-e^kt . compute f " (100) .

benbuks: Q5 . integral of tanx.sec²x dx is.....?

benbuks: Q6 if f(x,y)= y³ +2yx² -3x -3

F_xy =………?

benbuks: Q.7 .$[-3tan(3p)sec(3p)]dp

benbuks: Q8. Y=arc.sinh(8x)

y ' = ?
.

benbuks: Oya guys...fix a time you all will be available ተoday

asap ...

benbuks: $dx/(1+x² ) for -infinity <x< infinity

=?.

benbuks: Q d/dx arc.cosh(e^2x) = …?

benbuks: Q what is d derivative of y=arc tan (x^2 - 1)

benbuks: Q $ e^√x dx

benbuks: Q.y= cos²x

y ' ' =…?

benbuks: Q. y= e^arctanx

y ' =…?

benbuks: Q14. integral of tan²x dx =…?

S. secx+ c

e. cotx + c

u. tanx -x+c

n . -tanx-x+c

benbuks: Q15

2x² /y =1/x .y '

solve

E. -y=x² - c

B. y=x² + c

O. -x² +c = y

L. -x+c=y

A.God forbid ...

benbuks: Q13
solve

4x⁴/x = dy/dx


M. x⁴ + c=y

A.dxx⁴ + c =y

T.x³ -c =y



H .. hmm ..na wa ooo

benbuks: Q12.
solve

0=sinx + y '


B. cosx+c

u.sinx + c

k. -sinx + c

s. -cosx + c

benbuks: OK GUYS G GUYS..

RELAX........

benbuks: Q10 SOLUTION

using i.b.p

put u=lnx =>dx=du/x

& dv=dx =>v= x

hence we have

xlnx+x + c

= x(lnx+1) + c

benbuks: Q2 . $lnxdx =.?

benbuks: Q1 if y =-4e^-4x

it fourth derivative is ...?

B -1024e^-4x

E. 1024e^4x

N. - next question please.

benbuks: TIME UP...!!