₦airaland Forum

WinningEleven:
thanks for the advice sir. Is having one of the textbooks included for each subjects good enough. Cause I only have modern bio and its new

WinningEleven:
I scored 324 in jamb and I'm shooting for medicine.
I solved some UI practice questions and I realized that I'd need better textbooks that the ones I had.
Which textbooks do you recommend for me??
Just say anyone. Help a learner

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Quick hot Revision Questions in PHYSICS.

Ten questions to be answered in 20 minutes!

The CORRECT ANSWERS with their EXPLANATIONS will be released in 24 hours!


1 : A bead travelling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01Kg and the coefficient of friction between the bead and the wire is 0.1, determine the work done by friction.
A ) 0.0002 Joules.
B ) 0.002 Joules.
C ) 20 Joules.
D ) 200 Joules.
[g ≈ 10m/s²]

The answer is B because in calculating the work done by friction, using the formula; Work done(W) = Frictional Force(F) x displacement (S).But coefficient of friction (U) = Frictional force/Reaction force(mg). [.: F = Umg] . Substituting [F = Umg] in the initial equation, we have that : Work done = U x mg x S = 0.1 x 0.01 x 10 x 0.2 = 0.002 Joules.


2 : On top of a spiral spring of force constant 500N/m is placed a mass of 0.005Kg. If the spring is compressed downwards by a length of 0.02m and then released, calculate the height to which the mass is projected.
A ) 8m
B ) 4m
C ) 2m
D ) 1m
[g ≈ 10m/s²]

The correct answer is C because, from the principle of energy conservation, the elastic potential energy that was stored in the compressed spring (½ke²) was transformed into gravitational potential energy (mgh) when the spring stretches. [.: ½ke² = mgh] .We make h the subject of the formula to find the height, .: h = (k x e²)/(2 x m x g) = (500 x 0.02 x 0.02)/(2 x 0.005 x 10) = 2meters.

3 : A test tube of radius 1.0cm is loaded to 8.8g. If it is placed upright in water, find the depth to which it would sink.
A ) 2.8 cm
B ) 5.2 cm
C ) 25.5 cm
D ) 28.0 cm
[g ≈ 10m/s², density of water = 1000Kg/m²]

The answer is A because from Archimedes principle, upthrust in water is equal to weight of water displaced. i.e. Density x Volume x acceleration due to gravity(g) = mass x g. But Volume(V) = Area x height(depth). Substitute for V in the initial equation and cancel out g on both sides, we have : Density(D) x Area(A) x height(h) = mass(M). [A = πr² = Π x 0.01² ≈ 0.0003142]. Also, M = 8.8g = 0.0088kg.We are looking for height (depth). Therefore, h = M/(D x A) = 0.0088/(1000 x 0.0003142) ≈ 0.028meters = 2.8cm.


4 : If an object just begins to slide on a surface inclined at 30° to the horizontal, the coefficient of friction is _____?
A ) Surd 3
B ) Surd 3/2
C ) 1/surd 2
D ) 1/surd3
The correct answer is D because the coefficient of friction(U) = F/R = (sin theta)/(cos theta) = tan theta. Here, theta = 30°. Therefore, U = tan 30° = 1 over surd 3.

5 : A force of 100N is used to kick a football of mass 0.8Kg. Find the velocity with which the ball moves if it takes 0.8 seconds to be kicked.
A ) 32m/s
B ) 50m/s
C ) 64m/s
D ) 100m/s

The correct answer is D because from the formula for Force(F),which is; F = ma, but a = V/t. Therefore, F = mv/t. To find Velocity, V = Ft/m = (100 x 0.8 )/0.8 = 100m/s.


6 : A piece of stone attached to one end of a string is whirled round in a horizontal circle and the string suddenly cuts. The stone will fly off in a direction ______
A ) perpendicular to the circular path.
B ) parallel to the circular path.
C ) tangential to the circular path.
D ) towards the center of the circle.

The correct answer is C because when the string suddenly cuts or breaks, the stone no longer rotates around its center of rotation but will move directly away from it and continue to follow its path of inertia. That is, it will continue to move in the direction in which it was moving at the moment the string broke because there is no more centripetal force to keep it in the circular path.

7 ) By what factor will the size of an object placed 10cm from a convex lens be increased if the image is seen on a screen placed 25cm from the lens?
A ) 15.0
B ) 2.5
C ) 1.5
D ) 0.4

The answer is B because magnification = image distance/object distance = 25cm/10cm = 2.5


8 : An open pipe closed at one end produces its first fundamental note. If the velocity of sound in air is V and L is the length of the pipe, the frequency of the note is ____?
A ) 2V/L
B ) V/5L
C ) V/4L
D ) V/2L

The correct answer is C because the Fundamental Frequency of a closed pipe is given by V/4L.


9 : If an object is placed between two parallel plane mirrors with their reflecting surfaces facing each other, how many images of the object will be formed?
A ) Infinite .
B ) Eight.
C ) Four.
D ) Two.

The correct answer is A because when two mirrors are placed parallel to each other and an object is placed between them, the number of images formed is infinite.


10 : The operation of an optical fibre is based on the principle of ______?
A ) dispersion of light.
B ) interference of light.
C ) refraction of light.
D ) polarization of light.

The correct answer is C because optical fibre is used to transmit very strong optical signal over a long distance and it works by the principle of refraction or total internal reflection.

300+ RECORD BREAKERS in JAMB Series.

Quick hot Revision Questions in PHYSICS.

Ten questions to be answered in 20 minutes!

The CORRECT ANSWERS with their EXPLANATIONS will be released in 24 hours!


1 : A bead travelling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01Kg and the coefficient of friction between the bead and the wire is 0.1, determine the work done by friction.
A ) 0.0002 Joules.
B ) 0.002 Joules.
C ) 20 Joules.
D ) 200 Joules.
[g ≈ 10m/s²]

The answer is B because in calculating the work done by friction, using the formula; Work done(W) = Frictional Force(F) x displacement (S).But coefficient of friction (U) = Frictional force/Reaction force(mg). [.: F = Umg] . Substituting [F = Umg] in the initial equation, we have that : Work done = U x mg x S = 0.1 x 0.01 x 10 x 0.2 = 0.002 Joules.


2 : On top of a spiral spring of force constant 500N/m is placed a mass of 0.005Kg. If the spring is compressed downwards by a length of 0.02m and then released, calculate the height to which the mass is projected.
A ) 8m
B ) 4m
C ) 2m
D ) 1m
[g ≈ 10m/s²]

The correct answer is C because, from the principle of energy conservation, the elastic potential energy that was stored in the compressed spring (½ke²) was transformed into gravitational potential energy (mgh) when the spring stretches. [.: ½ke² = mgh] .We make h the subject of the formula to find the height, .: h = (k x e²)/(2 x m x g) = (500 x 0.02 x 0.02)/(2 x 0.005 x 10) = 2meters.

3 : A test tube of radius 1.0cm is loaded to 8.8g. If it is placed upright in water, find the depth to which it would sink.
A ) 2.8 cm
B ) 5.2 cm
C ) 25.5 cm
D ) 28.0 cm
[g ≈ 10m/s², density of water = 1000Kg/m²]

The answer is A because from Archimedes principle, upthrust in water is equal to weight of water displaced. i.e. Density x Volume x acceleration due to gravity(g) = mass x g. But Volume(V) = Area x height(depth). Substitute for V in the initial equation and cancel out g on both sides, we have : Density(D) x Area(A) x height(h) = mass(M). [A = πr² = Π x 0.01² ≈ 0.0003142]. Also, M = 8.8g = 0.0088kg.We are looking for height (depth). Therefore, h = M/(D x A) = 0.0088/(1000 x 0.0003142) ≈ 0.028meters = 2.8cm.


4 : If an object just begins to slide on a surface inclined at 30° to the horizontal, the coefficient of friction is _____?
A ) Surd 3
B ) Surd 3/2
C ) 1/surd 2
D ) 1/surd3
The correct answer is D because the coefficient of friction(U) = F/R = (sin theta)/(cos theta) = tan theta. Here, theta = 30°. Therefore, U = tan 30° = 1 over surd 3.

5 : A force of 100N is used to kick a football of mass 0.8Kg. Find the velocity with which the ball moves if it takes 0.8 seconds to be kicked.
A ) 32m/s
B ) 50m/s
C ) 64m/s
D ) 100m/s

The correct answer is D because from the formula for Force(F),which is; F = ma, but a = V/t. Therefore, F = mv/t. To find Velocity, V = Ft/m = (100 x 0.8 )/0.8 = 100m/s.


6 : A piece of stone attached to one end of a string is whirled round in a horizontal circle and the string suddenly cuts. The stone will fly off in a direction ______
A ) perpendicular to the circular path.
B ) parallel to the circular path.
C ) tangential to the circular path.
D ) towards the center of the circle.

The correct answer is C because when the string suddenly cuts or breaks, the stone no longer rotates around its center of rotation but will move directly away from it and continue to follow its path of inertia. That is, it will continue to move in the direction in which it was moving at the moment the string broke because there is no more centripetal force to keep it in the circular path.

7 ) By what factor will the size of an object placed 10cm from a convex lens be increased if the image is seen on a screen placed 25cm from the lens?
A ) 15.0
B ) 2.5
C ) 1.5
D ) 0.4

The answer is B because magnification = image distance/object distance = 25cm/10cm = 2.5


8 : An open pipe closed at one end produces its first fundamental note. If the velocity of sound in air is V and L is the length of the pipe, the frequency of the note is ____?
A ) 2V/L
B ) V/5L
C ) V/4L
D ) V/2L

The correct answer is C because the Fundamental Frequency of a closed pipe is given by V/4L.


9 : If an object is placed between two parallel plane mirrors with their reflecting surfaces facing each other, how many images of the object will be formed?
A ) Infinite .
B ) Eight.
C ) Four.
D ) Two.

The correct answer is A because when two mirrors are placed parallel to each other and an object is placed between them, the number of images formed is infinite.


10 : The operation of an optical fibre is based on the principle of ______?
A ) dispersion of light.
B ) interference of light.
C ) refraction of light.
D ) polarization of light.

The correct answer is C because optical fibre is used to transmit very strong optical signal over a long distance and it works by the principle of refraction or total internal reflection.

DrOptimistic:
Thanks very much. God bless you. Thanks for always helping we the aspirants

300+ RECORD BREAKERS in JAMB Series.

Quick hot Revision Questions in BIOLOGY.

Ten questions to be answered in 15 minutes!

The CORRECT ANSWERS with their EXPLANATIONS will be released in 24 hours!


1 : The smallest living organisms which share the characteristics of both living and non living matter are ________?
A ) Bacteria.
B ) Fungi.
C ) Virus.
D ) Protozoa.

The answer is C because virus reproduces inside the cells of other living organisms, but exists as a crystal outside a living cell.


2 : The cell of an onion bulb can be differentiated from a cheek cell by the presence of _______?
A ) Plasmalemma.
B ) Chloroplast.
C ) Cell wall.
D ) Nucleus.

The answer is C because the cell of an onion bulb being a plant cell possesses cellulose while a cheek cell which is an animal cell does not.


3 : In a cell, the genes are carried by _______?
A ) Nuclear membrane.
B ) Lysosomes.
C ) Chromatin threads.
D ) Mitochondria.

The answer is C because chromosomes are thread-like materials located in the nucleus of a cell which carries the genes. It was discovered in 1912 by the American geneticist whose name is Thomas Morgan.


4 : The membrane surrounding the vacuole in a plant cell is called the _____?
A ) Plasmalemma.
B ) Tonoplast.
C ) Nuclear membrane.
D ) Endoplasmic reticulum.

The answer is B because a vacuole is surrounded by a membrane called tonoplast which is filled with water, mineral salts, sugars and pigments called cell sap.


5 : A group of similar cells performing the same function is _______?
A ) an organ.
B ) a tissue.
C ) a system .
D ) an organelle.
E ) an enzyme.

The answer is B because a tissue is a group of cells which are similar in structure and function.


6 : An amoeba and an unlaid chicken egg are _______?
A ) Animal tissues.
B ) Organelles.
C ) Single cells.
D ) Organisms.

The answer is C because both amoeba and an unlaid chicken egg are unicellular.


7 : The rods in the retina of the eye are examples of _______?
A ) Organs.
B ) Cells.
C ) Tissues.
D ) Systems.

The answer is B because rods and cones are cells present in the retina which is a tissue in the eye which is in turn an organ in the body.


8 : What is the level of organisation of an onion bulb _______?
A ) Tissue.
B ) Organ.
C ) Systemic.
D ) Organism.

The answer is B because onion bulb is a plant organ composed of aggregates of epithelial tissues. NOTE that, tissues which cover and protect the surface of plants are known as epithelial tissues.


9 : Which of the following does a virus have in common with animal cells____?
A ) Nucleus.
B ) DNA.
C ) Glycogen.
D ) Cytoplasm.

The answer is B because a virus possesses a strand of nucleic acid which may be DNA or RNA which is present in all other animal cells.


10 : The pioneer organisms in an ecological succession are usually the ______?
A ) Lichens.
B ) Algae.
C ) Ferns.
D ) Mosses.

The answer is A because the pioneer organism in a plant succession on bare rock surfaces are some species of crustose lichen, followed by foliose lichen and then mosses.

300+ RECORD BREAKERS in JAMB Series.

Quick hot Revision Questions in BIOLOGY.

Ten questions to be answered in 15 minutes!

The CORRECT ANSWERS with their EXPLANATIONS will be released in 24 hours!


1 : The smallest living organisms which share the characteristics of both living and non living matter are ________?
A ) Bacteria.
B ) Fungi.
C ) Virus.
D ) Protozoa.

The answer is C because virus reproduces inside the cells of other living organisms, but exists as a crystal outside a living cell.


2 : The cell of an onion bulb can be differentiated from a cheek cell by the presence of _______?
A ) Plasmalemma.
B ) Chloroplast.
C ) Cell wall.
D ) Nucleus.

The answer is C because the cell of an onion bulb being a plant cell possesses cellulose while a cheek cell which is an animal cell does not.


3 : In a cell, the genes are carried by _______?
A ) Nuclear membrane.
B ) Lysosomes.
C ) Chromatin threads.
D ) Mitochondria.

The answer is C because chromosomes are thread-like materials located in the nucleus of a cell which carries the genes. It was discovered in 1912 by the American geneticist whose name is Thomas Morgan.


4 : The membrane surrounding the vacuole in a plant cell is called the _____?
A ) Plasmalemma.
B ) Tonoplast.
C ) Nuclear membrane.
D ) Endoplasmic reticulum.

The answer is B because a vacuole is surrounded by a membrane called tonoplast which is filled with water, mineral salts, sugars and pigments called cell sap.


5 : A group of similar cells performing the same function is _______?
A ) an organ.
B ) a tissue.
C ) a system .
D ) an organelle.
E ) an enzyme.

The answer is B because a tissue is a group of cells which are similar in structure and function.


6 : An amoeba and an unlaid chicken egg are _______?
A ) Animal tissues.
B ) Organelles.
C ) Single cells.
D ) Organisms.

The answer is C because both amoeba and an unlaid chicken egg are unicellular.


7 : The rods in the retina of the eye are examples of _______?
A ) Organs.
B ) Cells.
C ) Tissues.
D ) Systems.

The answer is B because rods and cones are cells present in the retina which is a tissue in the eye which is in turn an organ in the body.


8 : What is the level of organisation of an onion bulb _______?
A ) Tissue.
B ) Organ.
C ) Systemic.
D ) Organism.

The answer is B because onion bulb is a plant organ composed of aggregates of epithelial tissues. NOTE that, tissues which cover and protect the surface of plants are known as epithelial tissues.


9 : Which of the following does a virus have in common with animal cells____?
A ) Nucleus.
B ) DNA.
C ) Glycogen.
D ) Cytoplasm.

The answer is B because a virus possesses a strand of nucleic acid which may be DNA or RNA which is present in all other animal cells.


10 : The pioneer organisms in an ecological succession are usually the ______?
A ) Lichens.
B ) Algae.
C ) Ferns.
D ) Mosses.

The answer is A because the pioneer organism in a plant succession on bare rock surfaces are some species of crustose lichen, followed by foliose lichen and then mosses.