₦airaland Forum

Funjosh:
Sent

sir, please I really need help. Presently I don't have anything to eat or to even celebrate new year, I am teaching in a private school and we are not paid December salary. The little I saved from previous salary, I have used it to feed....pls help me with any amount sir, don't let me die of hunger pls.

7039233809
palm pay

Funjosh:
Sent

seen...., Thanks so much, God will enrich you. I really appreciate.

Funjosh:
Remaining 4 people.

Thanks

07039233809 MTN

Funjosh:
Good evening all, compliment of the season to everyone.
Just want to show some appreciation and gift 10 people 1gig Data here.

Just Ten numbers please, though it's small but I know it's a lot to some.

Thanks

07039233809 MTN.

Hersserbi3:
Which browser did you use please?

I used chrome

number2016:
Pls if there is anyone that has applied pls let us know if there is any application number attached to it, my own went through but I don't know if there is any registration number attach to it because I was just clicking and clicking because of the network.

there is a reference number you are to take note and beside you are to print acknowledgement slip that confirm your registration....., Just completed mine now!!.

temitope28:
Same thing with me; l have not been paid as well..l will try and collect another set of papers from them next year but will not return the paper until my money is paid. Useless examination body

same here...., Neco na trash. I marked WAEC and I was paid a week before results was released.

laceblaze:
I don't know what is happening,I have not seen mine.it was usually paid immediately the results are released.thisbcountry don spoil.walahi😂

same here, I haven't seen mine as well.

Kinsol007:
Some examiners claimed they were not paid last year

why ?

asiwaju1981:
NECO payment is always in batches. I am sure you will get yours before end of month.
.

okay, thank you.

asiwaju1981:
I received my NECO payment on the 8th of October at exactly 5:00PM...

pls I have not receive mine......what could be the problem ?

asiwaju1981:
NECO don pay today. Exactly one month after the coordination exercise

pls when did you see the alert, I have not received mine. What could be the problem ?

chinchum:
you are guilty of what you are accusing others of. You need to convert the linear expansivity to volume expansivity.

And the correct relationship is multiplying the linear expansivity by 3.

Question is asking about change in volume not length.

Before you start arguing again, remember a 21st century illiterate is someone who refuses to unlearn and relearn.

I think he haven't consulted his Text before commenting. I only pity his students .

Alusiizizi:
No point arguing with a stone wall! Bye!

okay bye !

Alusiizizi:
It clearly stated "Linear expansivity" in the question.

bro, the question is volume expansivity not linear expansivity. You should try and understand the question na.

Charmopompie:
Mr NDSMELODY...You are the one that don't know what you are doing. Changing it to kelvin still gives you the same answer. Learn from your oga on top

my brother this is education/academics...., Your oga at the top gave wrong explanation about the question

Charmopompie:
Mr NDSMELODY...You are the one that don't know what you are doing. Changing it to kelvin still gives you the same answer. Learn from your oga on top

1. How does converting from one unit to another now change the answer, if you truly understand the basic as you claimed , then you don't need to argue on this .

2. I know you don't still understand the question, for backing up wrong comment up there about the relationship between linear and volume expansivity. The question was not based on linear expansivity so you can't use linear expansion formula.

3. Go and study your physics text very well before you comment.

Alusiizizi:
Volume "expansionity"(whatever the hell that means) is not 3 multiplied by linear "expansionity" so your solution is incorrect ab-initio. Linear coefficient of expansion is just that, the the fraction of the linear dimension of an object that must be added to the original linear dimension of aforementioned object to obtain the new linear dimension after the object is heated. To get the new volume, use the information to calculate the increase in the cubes side length, getting (L_0 + DL) where L_0 is the original side length and DL is the increase in length due to heating, then compute the volume with (L_0 + DL) ^3, cube the new length to get the new volume.

Your second mistake is that you failed to note that the heat coefficients were given in Kelvin while the problem asked for increase in volume after the cubic object is increased from 10 Celsius to 60 Celsius. Before you write even the first line of equation you must convert these temperatures to Kelvin. You can do this by adding 273K to the given temperatures, because 0C=273K

This is why many students fail exams, when you do not understand questions, how will you provide correct solution to such question. The question was not based on linear expansivity, therefore how would you use linear expansion formula......just smiling, you need to do your research very well next time before commenting and in case you are a physics teacher/tutor, kindly consult your text before you teach your students non- sense !!

Alusiizizi:
Volume "expansionity"(whatever the hell that means) is not 3 multiplied by linear "expansionity" so your solution is incorrect ab-initio. Linear coefficient of expansion is just that, the the fraction of the linear dimension of an object that must be added to the original linear dimension of aforementioned object to obtain the new linear dimension after the object is heated. To get the new volume, use the information to calculate the increase in the cubes side length, getting (L_0 + DL) where L_0 is the original side length and DL is the increase in length due to heating, then compute the volume with (L_0 + DL) ^3, cube the new length to get the new volume.

Your second mistake is that you failed to note that the heat coefficients were given in Kelvin while the problem asked for increase in volume after the cubic object is increased from 10 Celsius to 60 Celsius. Before you write even the first line of equation you must convert these temperatures to Kelvin. You can do this by adding 273K to the given temperatures, because 0C=273K

from the first line of your comment, I believe you have not studied expansivity very well before you made your comment if otherwise you shouldn't have commented at all...............I just have one question for you,.......is there any relationship between linear expansivity and volume expansivity, is there any relationship between linear expansivity and area expansivity??
Therefore, show mathematically the relationship between the quantities stated above ?

Alusiizizi:
Volume "expansionity"(whatever the hell that means) is not 3 multiplied by linear "expansionity" so your solution is incorrect ab-initio. Linear coefficient of expansion is just that, the the fraction of the linear dimension of an object that must be added to the original linear dimension of aforementioned object to obtain the new linear dimension after the object is heated. To get the new volume, use the information to calculate the increase in the cubes side length, getting (L_0 + DL) where L_0 is the original side length and DL is the increase in length due to heating, then compute the volume with (L_0 + DL) ^3, cube the new length to get the new volume.

Your second mistake is that you failed to note that the heat coefficients were given in Kelvin while the problem asked for increase in volume after the cubic object is increased from 10 Celsius to 60 Celsius. Before you write even the first line of equation you must convert these temperatures to Kelvin. You can do this by adding 273K to the given temperatures, because 0C=273K

I would like you to provide your solution and show your workings clearly.

Here is the solution to the question. Check the picture below 👇👇👇

Pls I am at home with no hope to eat today, I am working in a school but we have not been paid our salary...., Pls I need your help with any amount to feed myself today, even yesterday I went without food.

0632908849 (gt bank)....thank you.

Pls note; this is not because I solved the question, but I am just asking if you could help me.

Thatgudoddguy:
I'm creating the group today and I believe we'd have a great time ...
Take an action today
It might be all you need to do in the rest of the year
See you at the top

add my number, 07039233809

Babamide:
You said sum of angles at a point is 360. That works for X+D.

What he is asking is what theorem you used to assume all the angles in the shape amount to 360.

okay, I used the proof of angle at the center is twice the remaining circumference.

Babamide:
That is not what he is asking

didn't you see the line of the solution he quoted ?

Babamide:
That is not what he is asking

what is he asking ?

AnotherSeun:
What theorem did you use for 70+30+20+D=360?

angle at a point sir, sum of angles at a point is 360°....Note that angle D is at a point .

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EreluRoz:
This is a simple stuff and hope you are not feeling fly about it

it is simple for those that know it, remember you know what you understand .