₦airaland Forum

mention a vertebrate that lays egg...den we wil continue when?

datz a'level nw

1st and 2nd laws of thermodynamics,i tink

bt u didnt tell me,sir...anyways i want anoda,sir

ask anoda questn pls@horpe...i'l be reserved at dose ?s

arrrgh...i ws so close l2-30=54 so t'ws 30-54...my mistake

no wonder,i sensed manipulation...i dnt see cross sectional area in d questn nw

i knw bt PLS solve it...stil got 84

itz linear expansivity,hw did it become superficial,sir..i dnt undastand

THE 2ND ONE

hw did i do in dat expansivity questn

hw did i do in dat expansivity questn?

finally,i got u...that questn dnt nid any calculation since u're lukin for d acceleration before cumin to rest...wen a body undergoes uniform velocity or constant speed the acceleration is always zero...the ans is 0

yea bt can u smash dis?
A body of mass 50kg moving with a uniform speed of 5m/s comes to rest in 5 sec.calculate its acceleration before coming to rest.

a=l2-l1/l1*¤ 0.000011=5-4.997/5¤ ¤=0.003/0.000055 ¤=54 bt ¤2-30=54 ¤2=54+30 =84'

b=2a 0.00006=A2-A1/A1¤ AREA=1/2*12*6 =36CM CUBE ¤=70-15 =55CM 0.00006*36*55=A2-36 A2=36+0.1188 a2=36.1188cm sq

A BODY SLIDES DOWN AN INCLINED PLANE WHICH MAKES ANGLE OF 30 WITH THE HORIZONTAL,NEGLECTING FRICTION.CALCULATE:
a.the velocity of the body after sliding 10m from rest
b.the time taken to slide the 10m distance


MORNING TO Y'ALL AND HAPPY SUNDAY

got 69.67 bt nt sure

yea,i nid more of ur physics questn@ope

hmmm...try again

a girl of mass 65kg falls from a bridge that is 50m above the water.calculate her kinetic energy after falling for 5 sec...
QUESTION 4 ALL

alryt...

the no. 2 gave me tough time bt got 69.6 though m nt sure

1.p1v1=p2v2
(10+40)2.5=10(V)
125=10V
V=12.5cm cube

4.hpg(mercury)=hpg(water)
103360 =2000000
p1v1=p2v2
103360(0.5)=2000000v
v=0.03CM CUBE

4rm d simplest
3.When held in a vertical position,the total pressure is (h+15) and the volume is 20.
When held in a horizontal position,the presure is h and the volume is 24
using boyle's law
P1V1=P2V2
(H+15)20=24H
20H+300=24H
H=75cmhg

you tried but the length for the vertically erected tube is 30 nt 20...therefore v1=30A...i respect una...i'll try to make ammendments...tenkz sir

yea@thaotech...a test tube is placed vertically with a mercury tread of 15cm of height 30cm.if the test tube is inverted with d same mercury thread nd height 45.calculate the atmospheric pressure common to both illustration

when a body of mass 500g is placed on a spiral spring,it extends by 0.2 m.find itz extension if a mass of 700g is placed on it(g=10m/s'2)...pls,solve

1.D 2.A 3.A 4.D 5.D 6.D 7.B 8B 10.D 11.lung bt c shud be close 12.D 9.I'M nt rily gud wit scientific names bt i knw itz found in insects...c:horpeyemi66

AMEN OO

waw,i respect u ooo