₦airaland Forum

E. E will die

No bodies first
The chopped part of the block will leave [/b]D alive
The weight of the complete block will suspend the Chopped block leaving [b][/b]C [b] alive

Non

Morbeta11:
Who dies first if "E" pushes the stone?




Ccccccccccc

NO ONE DIES BECAUSE MR D CAN EASILY SEE THE STONE COMING AND BEND UNDER HIS HOLE AS THE STONE ROLLED OVER.
AS FOR MR C, NOTHING WILL HAPPENED TO HIM BECAUSE THE MASS OF THE ROLLING STONE IS LESS THAN THE MASS OF THE SITTING STONE AT THE OTHER END OF THE LEVER (BECAUSE OF THE HOLLOWED HOLE ON THE STONE), SO THE ROLLING STONE CAN NOT PULL THE LEVER DOWN WITH IT LESS MASS TO HURT MR C

E dies first because the moment the stone from his end lands on the plank, it lifts the stone to the sender

C dies first.




If you need explanation contact me.

It has to be D

Morbeta11:
Who dies first if "E" pushes the stone?




Ccccccccccc

B.

Reason: If E pushes the stone, it rolls down the slope and hits the big spherical boulder. That impact sends the boulder rolling left, straight into the corridor where B is walking — B gets crushed.

Source chat gpt

C

This is a reflection of the type of political system we're operating in Nigeria.

ROTTWEILER007:
I believe C will die first. If E pushes the stone down the slope, there’s a very high chance (about 99.9%) that the gap in the stone will align with D’s head as it rolls, causing it to land on the crowbar (acting as the effort). The sharp edges under the crowbar would then fatally injure C. However, if the gap doesn’t align, the stone would roll over D’s head, pushing D back into the hole.

No matter wat C will not die. Remember the law of equilibrium? The spherical boulder being pushed by E has a lesser weight compared to the stationary spherical boulder on the pulley, thus, the spherical boulder being pushed by E is incapable of exerting enough force on the side of C because some part of it has been chopped off.

None of them will kpai

geunik:
Very incomplete puzzle. You need to tell us the radius of the ball and the length of the slope including the force amd even the weight of both balls. Then mathematicians can calculate. Right now, all we have to work with is guess everything

You must be a Physics inclined guy 💯.

The mechanics of the system was intentionally designed with ambiguity... hence the missing values.

They are busy arguing scenarios instead of taking it like a physics problem with missing values.

That's exactly what whoever created this wants

MMempire:
C!
This is where nairaland bot is useless as an answer as simple as an alphabet or digit can not be welcomed anymore without the bot asking for 40 more characters.

No body may die sef. It all depends on so many variables.

WRONG! The rolling ball is not a free-falling object that gains force due to mass and gravitational acceleration. In this case, as the ball which has less mass rolls along the incline with a frictional force that might slow the ball. Hence, it lands on the LEVER with a tangential and weakened force, insufficient EFFORT to lift the LOAD of the bigger ball resting on the other side. So, Person C will be saved. Meanwhile, after the rolling ball lands on the lever, the wedge on the lever with serve as an incline that with turn the ball to a PROJECTILE, causing the ball to fly into the air towards Person B or Person A. But, given that the force on the flying ball will be ATTENUATED, the ball will land where Person B is located. Given that the pit where Person B is standing is wider than the DIAMETER of the flying ball, Person B will be crushed.

A305:
The answer is C due to momentum from acceleration otherwise known as gravitational force from the rolling ball. And this will only happen if the mass of that rolling ball is greater than the mass of that stationary ball on the other side of the swing.

The energy in the speed of the rolling ball has to go somewhere, hence, centrifugal force will make it bounce back and the stationary ball might change direction to join it to press down the swing to kill that unfortunate fellow.

PERSON B!

EXPLANATION.
Person D will live by lowering his/her height and the rolling ball will roll over the small gap.

Person C will live because the rolling ball is not a free-falling (vertical fall) object that gains gravitational momentum enough to force the LEVER downwards. Rather, the ball rolls along the INCLINE PLANE with a frictional force that might slow the ball’s momentum and lowers its weight. Hence, it lands on the LEVER with a tangential and weakened force, with insufficient EFFORT to lift the LOAD of the bigger ball resting on the other side. So, Person C will be saved.

Person B will die because after the rolling ball lands on the lever, the wedge on the lever with serve as an incline that will send the ball into a PROJECTILE motion, causing the ball to fly into the air towards Person B or Person A. But, given that the force on the flying ball will be ATTENUATED by gravity, the ball will land where Person B is located. Also, given that the pit where Person B is standing is wider than the DIAMETER of the flying ball, Person B will be crushed.

Person A will live because the rolling ball won’t get to where he/she is standing. Moreover, Person A has ample space to move and avoid the rolling ball.

Morbeta11:
Who dies first if "E" pushes the stone?




Ccccccccccc

Nobody dies , everyone survives the impact on the stone with the C opening , saves everyone

D is the answer.

The markings on the slope and the ball are there for a reason. Calculating each quadrant of the ball with each square on the slope, it shows that by the time the ball gets to D it won't be the cut side that would be on the plane.
By the time the ball gets to D if will be the side with no cut. So D would die first.

MMempire:
C!
This is where nairaland bot is useless as an answer as simple as an alphabet or digit can not be welcomed anymore without the bot asking for 40 more characters.

c wouldn't because the stone is not the same weight as the one placed on the fulcrum. the hollow point will fit acuratley with the head of D, so no one will die.

ROTTWEILER007:
I believe C will die first. If E pushes the stone down the slope, there’s a very high chance (about 99.9%) that the gap in the stone will align with D’s head as it rolls, causing it to land on the crowbar (acting as the effort). The sharp edges under the crowbar would then fatally injure C. However, if the gap doesn’t align, the stone would roll over D’s head, pushing D back into the hole.

You're assuming the stone is heavier than the stationary one

Morbeta11:
Who dies first if "E" pushes the stone?




Ccccccccccc

C. The stone will press down the spiked lever and c will be stabbed to death

sprints1:
No one dies. If the effort of that E ball lands on the see saw the fulcrum of the see saw will not be equal or balance the see-saw from the image we were not given the weight of the objects. The load and resistance of that other ball looks very high. So no one dies

Don't forget there's a curve on the see saw that could give the stone in motion a flip which could end up killing A or B

[quote author=olamkas post=136589548][/quote]Could be A too..

But you know the stone flipping over depends on the force in which E exerts to push ..

If the push is with mild force, the stone rolls over , on getting to the curve , it would flip but would not go as far as getting to B, maybe just take a little lift and land just a little away from the curve thereby not killing anyone or killing C if the see saw is not strong enough withstand the weight it exerts with gravity..

D

Morbeta11:
Who dies first if "E" pushes the stone?




Ccccccccccc

CoronaVirusPro:
No one dies.

I don’t have 500 characters to type and will update when I have.

You are right, no body will die as the weight of the incoming stone will stay put with the other one after the pivot point with the help of the stopper.

harmargedon:
c wouldn't because the stone is not the same weight as the one placed on the fulcrum. the hollow point will fit acuratley with the head of D, so no one will die.

Yes, you are right.

Silentgroper:
Could be A too..

But you know the stone flipping over depends on the force in which E exerts to push ..

If the push is with mild force, the stone rolls over , on getting to the curve , it would flip but would not go as far as getting to B, maybe just take a little lift and land just a little away from the curve thereby not killing anyone or killing C if the see saw is not strong enough withstand the weight it exerts with gravity..

xup bro

EmiDon11:
xup bro

Xup??

That's so 2go ..
.no one says that again ..


.where yo been?

MMempire:
C!
This is where nairaland bot is useless as an answer as simple as an alphabet or digit can not be welcomed anymore without the bot asking for 40 more characters.

you no see person head wey the stone go first hit before it proceeds?

Caseless:
you no see person head wey the stone go first hit before it proceeds?

It will only press his head down, but he will not die🤣🤣🤣

A

Silentgroper:
Xup??

That's so 2go ..
.no one says that again ..


.where yo been?

on the low my bro

EmiDon11:
on the low my bro

What's up with you