₦airaland Forum

sweet7oyin:
if I go for medicine and dnt meet the cutoff I would be given another course

Yes,if you get connection..... No if you don't have connection.... Still God grace prevail

starlingslimnet:
Yes,if you get connection..... No if you don't have connection.... Still God grace prevail

also their change of course hw does it work.... I mean is there a specific course that would be change to another or.....

sweet7oyin:
also their change of course hw does it work.... I mean is there a specific course that would be change to another or.....

Yea....microbiology nd biochemistry can cross to Medicine and surgery... It's advisable to obtain JAMB coc and change to any of the above mentioned nd later move MBBS

starlingslimnet:
Yea....microbiology nd biochemistry can cross to Medicine and surgery... It's advisable to obtain JAMB coc and change to any of the above mentioned nd later move MBBS

itz nt as easy as u think

DrSage:
itz nt as easy as u think

Somebody initially going for medicine have the facility to make it happen

starlingslimnet:
Somebody initially going for medicine have the facility to make it happen

true talk.

Buh sometimes in d dept of microbiology,d HOD might release 5 out of 250+

even those with good & high GP's have a 50:50 chance of crossing

DrSage:
true talk.

Buh sometimes in d dept of microbiology,d HOD might release 5 out of 250+

even those with good & high GP's have a 50:50 chance of crossing

And that is why Bro we need God favour

starlingslimnet:
And that is why Bro we need God favour

na so
check ur mail boss

DrSage:
na so
check ur mail boss

that mail not working .....reach me on starlingleanets@gmail.com

starlingslimnet:
that mail not working .....reach me on starlingleanets@gmail.com

aiit sire

DrSage:
aiit sire

yea

starlingslimnet:
yea

done
u can check naw

DrSage:
done
u can check naw

can't find it Bro..

starlingslimnet:
can't find it Bro..

or try checking ur spam folder

DrSage:
or try checking ur spam folder

seen...thanks have replied

starlingslimnet:
seen...thanks have replied

ok man

But is it possible for the cutoff mark to reach 300

sweet7oyin:
But is it possible for the cutoff mark to reach 300

it's possible but i don't see it happening. Though the cut off mark is decided based on the general performance... But nonetheless, it's never been as high as that

Pls who can differentiate y= logaU...... a is the base

Hi fellas, watz d cut off mark for chemical engineering pls?

coolestboy:
Hi fellas, watz d cut off mark for chemical engineering pls?

250 on merit.
The cutoff aint constant

DrSage:
250 on merit.
The cutoff aint constant

Tanx, but dt shd be d addition of ume and post ume divided by two, ryt?
I need sum clarifications here.

coolestboy:
Tanx, but dt shd be d addition of ume and post ume divided by two, ryt?
I need sum clarifications here.

exactly

DrSage:
exactly

Is d post ume form now available 4 sale?

coolestboy:
Is d post ume form now available 4 sale?

not yet available sir

coolestboy:
Is d post ume form now available 4 sale?

ma boss has answered alredi

sweet7oyin:
Pls who can differentiate y= logaU...... a is the base

if y = logaU
we can change to base "e" to obtain
y = lnU/lna note: ln = loge
(1/lna) is a constant, factor it out
y = (1/lna) lnU
dy/dx = (1/lna) d(lnU)/dx
dy/dx = (1/lna) (1/U) = 1/Ulna
as final ansa.

Or if u like express in log base a
since (1/lna) is same as loga(e)

we av
dy/dx = loga(e)/U

donriddo:
if y = logaU
we can change to base "e" to obtain
y = lnU/lna note: ln = loge
(1/lna) is a constant, factor it out
y = (1/lna) lnU
dy/dx = (1/lna) d(lnU)/dx
dy/dx = (1/lna) (1/U) = 1/Ulna
as final ansa.

Or if u like express in log base a
since (1/lna) is same as loga(e)

we av
dy/dx = loga(e)/U

I'm sorry, I don't agree with you, especially since your differentiating with respect to x, d(lnU)/dx =! 1/U (I mean not equal) unless you're differentiatin with respect to u as in dy/du

mathefaro:
I'm sorry, I don't agree with you, especially since your differentiating with respect to x, d(lnU)/dx =! 1/U (I mean not equal) unless you're differentiatin with respect to u as in dy/du

he is correct

donriddo:
if y = logaU
we can change to base "e" to obtain
y = lnU/lna note: ln = loge
(1/lna) is a constant, factor it out
y = (1/lna) lnU
dy/dx = (1/lna) d(lnU)/dx
dy/dx = (1/lna) (1/U) = 1/Ulna
as final ansa.

Or if u like express in log base a
since (1/lna) is same as loga(e)

we av
dy/dx = loga(e)/U

what of if its loya4U.... a is the base