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A painter charges $40 per day for himself, and he also charges $10 per day for his assistant. if he paints some cars for some couple of days and received $2000. And the painter worked 10 days more than his assistant. How much will the assistant and the painter receive ?

Kodejuice:
Think you're smart?, try this
A painter charges $40 per day for himself, and he also charges $10 per day for his assistant. if he paints some cars for some couple of days and received $2000. And the painter worked 10 days more than his assistant. How much will the assistant and the painter receive ?

Let me try

The painter will receive $1700
While his assistant will receive $300.
Since they both earn $50 per day, they will both have to work for 40days to earn $2000.
But the assistant didn't work for 10 days which means they only worked together for 30days
So $50 x 30days =$1500 so the painter worked alone for 12.5days to make up the total $2000.
If they were to divide the money, then, the painter will get $1200 for the 30days they worked together + the extra 12.5days which he worked alone ($40x12.5days)=$500. so he receives a total of $1700 While his assistant who worked for 30days and earns $10 per day will receive $300 for the 30days he worked.

Kodejuice:
Think you're smart?, try this


A painter charges $40 per day for himself, and he also charges $10 per day for his assistant. if he paints some cars for some couple of days and received $2000. And the painter worked 10 days more than his assistant. How much will the assistant and the painter receive ?

Basic algebra.
Let days assistance worked = D

D * 10 = Amount Assistance got paid
D+10 * 40 = Amount painter got paid
((D+10) * 40) + (D * 10) = 2000
40D + 400 + 10D = 2000
50D + 400 = 2000
50D + 400-400 = 2000-400
50D = 1600
50D/50 = 1600/50
D = 32

Therefore assistance received 32 * 10 = 320
painter received 40D + 400 = 1280 + 400 = 1680