NL Chemists And Chemistry Gurus. Help! Question About Moles. - Education - Nairaland
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| NL Chemists And Chemistry Gurus. Help! Question About Moles. by cazchukwu(op): 1:10pm On Aug 13, 2016 |
A student conducting this experiment weighs out 3.10g of CoCl2.6H2O. For the part you will be calculating the amount Of sodium carbonate required for the complete precipitation of cobalt2 carbonate. Calculate the moles of CoCl2.6H2O used in this reaction. Thanks guys. |
| Re: NL Chemists And Chemistry Gurus. Help! Question About Moles. by raayah(f): 1:14pm On Aug 13, 2016*. Modified: 1:29pm On Aug 13, 2016 |
Are you asking how to calculate just the moles?? If yes, the use the formula Moles = Mass/Molar mass of CoCl2.6H2O Let MM = Molar Mass MM of CoCl2.6H2O = MM of Co + (2*MM of Cl) + ( 6*2 MM of H) + (6*MM Of O) From the periodic tables, MM of Co = 58.93 g/mol MM of Cl = 35.45 g/mol MM of H = 1.00 g/mol MM of O = 16.00g/mol MM of CoCl2.6H2O = 58.93 + (2*35.45)+(12*1)+(6*16) MM of CoCl2.6H2O = 237.83 g/mol Moles of CoCl2.6H2O = 3.10g/237.83g/mol Moles of CoCl2.6H2O = 0.013 moles |
| Re: NL Chemists And Chemistry Gurus. Help! Question About Moles. by cazchukwu(op): 1:27pm On Aug 13, 2016 |
raayah:I love you bro. No homo. God bless you. |
| Re: NL Chemists And Chemistry Gurus. Help! Question About Moles. by raayah(f): 1:30pm On Aug 13, 2016 |
cazchukwu:Ok,I have updated the full calculation,if this is what you're looking for |
| Re: NL Chemists And Chemistry Gurus. Help! Question About Moles. by cazchukwu(op): 2:12pm On Aug 13, 2016 |
raayah:Just noticed that you're a female. Thanks tho. The answer was right. Passed my Online quiz cos of it. |
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