₦airaland Forum

CondomSir:
I thought the trend is as x increases from 10cm to 60cm, current and voltage also increase..

cc Natureboy91

it should be increasing,,,I think I know where our own connection is wrong

ComradeTY:
Please do explain better....

Are you a teacher or a student? Let me know so as to know how best to put my explanation

ibroh22:
it should be increasing,,,I think I know where our own connection is wrong

Do try and rectify it then. Let's try and perfect it before tomorrow. Have you found your way around question 1?

CondomSir:
Do try and rectify it then. Let's try and perfect it before tomorrow. Have you found your way around question 1?

the setup is in school and am at home,,,for question 1,the motion of the metre rule will be coming to and fro like simple pendulum Bob more like jingle over?

CondomSir:
Do try and rectify it then. Let's try and perfect it before tomorrow. Have you found your way around question 1?

there should be a 2 wire connecting to the Jockey,one directly from the voltmeter and the other from the one going to the bulb, I guess,check the diagram,i only connect one wire from voltmeter to the Jockey and I didn't connect anyone from the bulb to the Jockey,is this where am wrong?

CondomSir:
Are you a teacher or a student? Let me know so as to know how best to put my explanation

he is a teacher,i can attest to that cos we are do talk on phone and also chat

CondomSir:
Do try and rectify it then. Let's try and perfect it before tomorrow. Have you found your way around question 1?

please did you have the series past question with you,u can snap the answer page of the 2011 question 3 or anybody that have it can pls snap and send it here

CondomSir:
Are you a teacher or a student? Let me know so as to know how best to put my explanation

Teacher

How do we come about 6 ohms resistance for the bulb? Is the answer in the WAEC PQ correct?

Lawless101:
thats true. Our data processing theory was like that. Please why?

That's Upgrade.

ibroh22:
the setup is in school and am at home,,,for question 1,the motion of the metre rule will be coming to and fro like simple pendulum Bob more like jingle over?

I uploaded a video earlier on for the Q1, if you watched it and checked the diagram for the question, you will get the movement. It is not a jingle over

Q1: L(cm)> 80, 70, 60, 50, 40.
t(s)> 14, 13, 12, 11, 09.
Q2: M(g)> 10, 20, 30, 40, 50.
bi> 109, 118, 127, 136, 145.
ibroh22 type me the values from ur theory answer to Q3 snapped here so i can compare the values & make corrections before u take it to ur students. Sorry, am using java phone, dats why i cant see the pic clearly.

ibroh22:
there should be a 2 wire connecting to the Jockey,one directly from the voltmeter and the other from the one going to the bulb, I guess,check the diagram,i only connect one wire from voltmeter to the Jockey and I didn't connect anyone from the bulb to the Jockey,is this where am wrong?

I said earlier on that both my ammeter and voltmeter didn't even move at all. Right now, i'm at the mercy of the formula i uploaded except if the apparatus in the centre where my students will be using tomorrow are working properly. But if i'm to go by the theory, i will be using E=2.5v

ibroh22:
please did you have the series past question with you,u can snap the answer page of the 2011 question 3 or anybody that have it can pls snap and send it here

The readings in the past question i saw with my students are wrong

CondomSir:
I said earlier on that both my ammeter and voltmeter didn't even move at all. Right now, i'm at the mercy of the formula i uploaded except if the apparatus in the centre where my students will be using tomorrow are working properly. But if i'm to go by the theory, i will be using E=2.5v

Then, what will be ur values for current and voltage?

ComradeTY:
Teacher

How do we come about 6 ohms resistance for the bulb? Is the answer in the WAEC PQ correct?

It depends on the resistance of the bulb you used. If you are using a new bulb, check the body of its carton, the resistance is writen there

CondomSir:
The readings in the past question i saw with my students are wrong

I've seen two different readings in different past question. I feel that q3 is faulty, the answers were just manipulated. I did everything perfectly right but the bulb didn't come up, and both meter didn't read simultaneously with the bulb in the circuit

NatureBoy91:
Then, what will be ur values for current and voltage?

Using

V=L2E/2L2-L1

and

I=V/R

where L1=x, L2=100-x, my own R=6ohms and E=2.5V

Use this to make a table for all values of x

CondomSir:
I uploaded a video earlier on for the Q1, if you watched it and checked the diagram for the question, you will get the movement. It is not a jingle over

the number you dropped here,is it ur WhatsApp number,,I want to add u and send 2 videos to u,,I demonstrate two movements dere,tel me which one we are going to use for the Q1

NatureBoy91:
Q1: L(cm)> 80, 70, 60, 50, 40.
t(s)> 14, 13, 12, 11, 09.
Q2: M(g)> 10, 20, 30, 40, 50.
bi> 109, 118, 127, 136, 145.
ibroh22 type me the values from ur theory answer to Q3 snapped here so i can compare the values & make corrections before u take it to ur students. Sorry, am using java phone, dats why i cant see the pic clearly.

x=10,20,30,40,50
V=0.6,0.55,0.5,0.45,0.40,0.35
I=0.30,0.3,0.25,0.25,0.2,0.15

Connect the (-) of ba3 to the end of potentiometer, Q, then (+) of ba3 to plug key down to the end of potentiometer, P, down to (-) of ammeter to (+) of voltmeter. Then, connect (+) of ammeter to the bulb down to (-)of voltmeter to the jockey. Hope, this helps: ibroh22, condomsir, readers.

ibroh22:
x=10,20,30,40,50
V=0.6,0.55,0.5,0.45,0.40,0.35
I=0.30,0.3,0.25,0.25,0.2,0.15

It should be increasing & not decreasing. Current is directly proportional to Voltage. Use the values I gave u instead. It should go in 1s & not 0s. If nt why did they require of 0-5 A/Vmeter instead of 0-3 A/Vmeter.

good evening my people.I av something I want to contribute to d physics practical which will b useful

ibroh22:
the number you dropped here,is it ur WhatsApp number,,I want to add u and send 2 videos to u,,I demonstrate two movements dere,tel me which one we are going to use for the Q1

Unfortunately, i'm using a small java phone right now. i used someone's phone to upload in the afternoon.

let me try to explain..

set up the apparatus as show in the diagram. Hold the two ends of the metre rule, now use your left hand to pull one end towards you and use the right hand to push the other end away from you. Now release the metre rule and allow it perform a to-and-fro movement about its vertical axis through its centre.

I hope this helps

NatureBoy91:
It should be increasing & not decreasing. Current is directly proportional to Voltage. Use the values I gave u instead. It should go in 1s & not 0s. If nt why did they require of 0-5 A/Vmeter instead of 0-3 A/Vmeter.

yes,,, that's why I said my values are wrong,,the connection is not right,,I have two positive wire connected to the bulb,which shld not be so

NatureBoy91:
Connect the (-) of ba3 to the end of potentiometer, Q, then (+) of ba3 to plug key down to the end of potentiometer, P, down to (-) of ammeter to (+) of voltmeter. Then, connect (+) of ammeter to the bulb down to (-)of voltmeter to the jockey. Hope, this helps: ibroh22, condomsir, readers.

Thanks man i will check it out tomorrow morning

CondomSir:
Unfortunately, i'm using a small java phone right now. i used someone's phone to upload in the afternoon.

let me try to explain..

set up the apparatus as show in the diagram. Hold the two ends of the metre rule, now use your left hand to pull one end towards you and use the right hand to push the other end away from you. Now release the metre rule and allow it perform a to-and-fro movement about its vertical axis through its centre.

I hope this helps

this is horizontal movement,,the metre rule is moving on same plane

NatureBoy91:
Connect the (-) of ba3 to the end of potentiometer, Q, then (+) of ba3 to plug key down to the end of potentiometer, P, down to (-) of ammeter to (+) of voltmeter. Then, connect (+) of ammeter to the bulb down to (-)of voltmeter to the jockey. Hope, this helps: ibroh22, condomsir, readers.

thanks,,this is not how I connect it,,,,I will check that up

d readings for Q3 is logical.one needs to be careful.this is how it goes:
current is directly proportional to potential difference. bear it in mind that d value of V is always greater than I

ibroh22:
x=10,20,30,40,50 V=0.6,0.55,0.5,0.45,0.40,0.35 I=0.30,0.3,0.25,0.25,0.2,0.15

Your V and I are suppose to be increasing oo

ibroh22:
this is horizontal movement,,the metre rule is moving on same plane

It's vertical.

hassantaofeeq90:
d readings for Q3 is logical.one needs to be careful.this is how it goes:
current is directly proportional to potential difference. bear it in mind that d value of V is always greater than I

U got it right. Also, two points above can give u the vertical intercept. Thanks.