₦airaland Forum

CondomSir:
Your V and I are suppose to be increasing oo

Yh I know

ibroh22:
this is horizontal movement,,the metre rule is moving on same plane

It will be making a horizontal movement about its vertical axis..
are you confused?

For vertical oscillatn, hold both ends of metre rule. With it, pull one end forward & the other end backward, allow(remove ur hands) to oscillate.

CondomSir:
It will be making a horizontal movement about its vertical axis..

are you confused?

Check this movement,,if pendulum Bob is moving like dat manner in the picx,thats vertical movement,because the movement is moving to the vertical axis

Cc natureboy91

the value of V starts from 1.6 while that of I starts from 0.6.the highest value of I is not up to 1.my results tell me that.it was confirmed from waec website that my readings are correct

x=10,20,30,40,50
V=1.3, 1.4,1.6,1.9,2.5,5.0
I=0.2,0.2,0.3,0.3,0.4,0.8

For E=2.5V
R=6 ohms

hassantaofeeq90:
the value of V starts from 1.6 while that of I starts from 0.6.the highest value of I is not up to 1.my results tell me that.it was confirmed from waec website that my readings are correct

Upload ur result here baba

hassantaofeeq90:
the value of V starts from 1.6 while that of I starts from 0.6.the highest value of I is not up to 1.my results tell me that.it was confirmed from waec website that my readings are correct

Then, list three values of urs below, let me confirm.

in 2011,students were asked to evaluate log V and Log I .from the table,all d values of log I are negative because log 0.5 will give negative valuyand so on. disregard what u c in series
goto this waec website to check if my readings are right or wrong
http://waeconline.org.ng/e-learning/Physics/Phys120mq3.html

ibroh22:
Check this movement,,if pendulum Bob is moving like dat manner in the picx,thats vertical movement,because the movement is moving to the vertical axis

Cc natureboy91

That's horizontal.

hassantaofeeq90:
in 2011,students were asked to evaluate log V and Log I .from the table,all d values of log I are negative because log 0.5 will give negative valuyand so on. disregard what u c in series
goto this waec website to check if my readings are right or wrong
http://waeconline.org.ng/e-learning/Physics/Phys120mq3.html

What are ur readings? List them.

NatureBoy91:
That's horizontal.

so simple pendulum movement is horizontal?

CondomSir:
It will be making a horizontal movement about its vertical axis..
are you confused?

yes o

ComradeTY:
x=10,20,30,40,50 V=1.3, 1.4,1.6,1.9,2.5,5.0 I=0.2,0.2,0.3,0.3,0.4,0.8
For E=2.5V R=6 ohms

natureboy91,,,check this result

here are my readings

@ibroh22

The instruction states that

"....then release so that it oscillates about a vertical axis through its centre.."

What is meant by vertical axis is the point from where the rope is tied to the retort stand and used to suspend the metre rule. This is straight forward

NatureBoy91:
Q1: L(cm)> 80, 70, 60, 50, 40.
t(s)> 14, 13, 12, 11, 09.
Q2: M(g)> 10, 20, 30, 40, 50.
bi> 109, 118, 127, 136, 145.
ibroh22 type me the values from ur theory answer to Q3 snapped here so i can compare the values & make corrections before u take it to ur students. Sorry, am using java phone, dats why i cant see the pic clearly.

How sure are this values sir ?

This values looks more like it following what's on the Waec site.

ComradeTY:
How sure are this values sir ?

Test and see for urself.

ibroh22:
natureboy91,,,check this result

This is what should be obtained acording to the theory. But again, you might want to modify the values of I

hassantaofeeq90:
here are my readings

Pls, android users, write out the values on the pic.

I also av d readings for Q1,I carried out d experiment myself.also I av taught my students.Q1 is d simplest

xenoo:
This values looks more like it following what's on the Waec site.

Which of the values?

hassantaofeeq90:
I also av d readings for Q1

Upload please

CondomSir:
@ibroh22

The instruction states that

"....then release so that it oscillates about a vertical axis through its centre.."

What is meant by vertical axis is the point from where the rope is tied to the retort stand and used to suspend the metre rule. This is straight forward

I think I got it now,,its same with the first YouTube video u sent yst

i also av d readings for Q1,I carried out d experiment myself.also I av taught my students.Q1 is d simplest

ibroh22:
natureboy91,,,check this result

V will be greater than I. But, i disagree for values of V: 2.5- 5.0. And that of I: 0.2, 0.2. Remember, those are theoritical values, no running down ba3 as in the case of practical.

NatureBoy91:
Pls, android users, write out the values on the pic.

x=10,20,30,40,50,60
V=1.60,1.80,2.10,2.30,2.60,2.90
I=0.27,0.31,0.35,0.39,0.44,0.48

hassantaofeeq90:
i also av d readings for Q1,I carried out d experiment myself.also I av taught my students.Q1 is d simplest

Q1 is the hardest, I would advise one go for Q2 & 3. Q2 is the simplest. Q1 & 3 are logical.

EMF can never be 2.5v because we we were told to use two batteries. a battery has 1.5v therefore two batteries have 3.0v

NatureBoy91:
V will be greater than I. But, i disagree for values of V: 2.5- 5.0. And that of I: 0.2, 0.2. Remember, those are theoritical values, no running down ba3 as in the case of practical.

that's wat am saying, u can't compare theoretical values with practical

ibroh22:
I think I got it now,,its same with the first YouTube video u sent yst

You may go ahead and carry it out then.

for L=80cm, my t=14.25s, as L decreases, the time taken to complete 10 oscillations also decreases