₦airaland Forum

 //give te script time to execute
    ini_set("max_execution_time", 200);
    
    $portRange = range(0, 1023);
    $host = "127.0.0.1";
    
    print "<p>The scan results for $host is:</p>";
    //execute the scan
    foreach ($portRange as $port) {
      if ($result = @fsockopen($host, $port, $errNo, $errString, 1)) {
        $service = getservbyport($port, 'tcp');
        print "Socket open at port $port, with <em><strong>$service</strong></em> service <br />";
      }
    } //end loop

The code above works just fine because wrote '@' beside the fsockopen() function. Removing the '@' produces error as seen in the screen shots. Why is the @ compulsory? what it actually does?

Thanks in anticipation of your replies.

paranorman:

 //give te script time to execute
    ini_set("max_execution_time", 200);
    
    $portRange = range(0, 1023);
    $host = "127.0.0.1";
    
    print "<p>The scan results for $host is:</p>";
    //execute the scan
    foreach ($portRange as $port) {
      if ($result = @fsockopen($host, $port, $errNo, $errString, 1)) {
        $service = getservbyport($port, 'tcp');
        print "Socket open at port $port, with <em><strong>$service</strong></em> service <br />";
      }
    } //end loop

The code above works just fine because wrote '@' beside the fsockopen() function. Removing the '@' produces error as seen in the screen shots. Why is the @ compulsory? what it actually does?

Thanks in anticipation of your replies.

Basically using the @sign will cause all php warnings not to be shown for that particular function.

http://php.net/manual/en/language.operators.errorcontrol.php

Like Echatbook said, the @silences errors for a function(read the php manual above)

If you don't mind me asking what exactly whee you trying to achieve with your function. It would be best to write a bug free code.

I appreciate your contributions. Thanks