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I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 5:50am On Jan 20, 2018 |
You will recieve 2k worth of airtime if you get these questions within 5hrs 1. integral[1/((e^t)-1)]dt 2. integral(lnx) 3. show that |n|n-1=π/sinnπ (| rep a sign in gamma and beta function) 4. show that beta(m,n)=(|p|q)/|(p+q) |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by dingbang(m): 5:53am On Jan 20, 2018 |
U dey find person wey go solve your assignment for you abi.. No worry... Things will be made easy soon for you 3 Likes |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by doughziay: 5:56am On Jan 20, 2018 |
sopstan: I'll pay you double that amount if you'll solve it. 4 Likes |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 5:59am On Jan 20, 2018 |
ok after 5hrs... |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by presh2dk(m): 6:16am On Jan 20, 2018 |
Abeg keep your card |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 6:20am On Jan 20, 2018 |
presh2dk:you've tried your best right?... e pain am 1 Like |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 6:21am On Jan 20, 2018 |
you've tried your best right?... ; e pain am 1 Like |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by LordSkinnie(m): 6:27am On Jan 20, 2018 |
Simple. Answer - South Africa. where my card? sopstan: 1 Like |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by dejt4u(m): 6:35am On Jan 20, 2018 |
sopstan:this resembles Mathematical Physics.. Beta and Gamma functions (Euler's function) |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 6:38am On Jan 20, 2018 |
dejt4u:something like that |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by falcon01: 7:16am On Jan 20, 2018 |
MAKE I SOLVE |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 8:01am On Jan 20, 2018 |
sopstan:2. sol integral(Inx)= integral(lnx.x°) (where x°=1) this becomes integral(udv) u=Inx and dv=x° du=1/x and v=x then using integratn by parts you have uv-integral(vdu) which will be Inx.x-integral(x.1/x)dx = xInx-x = x(Inx-1)ans... |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by Mrkumareze(m): 8:13am On Jan 20, 2018 |
It's like you don't know where to post such question. Nairaland is characterized by lazy men and women 2 Likes |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 8:32am On Jan 20, 2018 |
sopstan: 1. sol integral[1/((e^t)-1)]dt u=e^t, du=e^tdt, dt=du/e^t=du/u the whole guy now becomes integral[du/u(u-1)] then you resolve into partial fraction it now becomes integral[1/(u+1)-1/u]du you then integrate= In(u+1)-Inu=In[(u+1)/u] (since u=e^t) the whole guy now becomes In[((e^t)+1)/e^t] or In[1+1/e^t]ans... now do the rest |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 8:34am On Jan 20, 2018 |
Mrkumareze:like seriously? |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by BunbleBee: 9:18am On Jan 20, 2018 |
3). Another common integral representation of the beta function is B( x , y ) = ∫ ∞ 0 t x −1 (1 + t ) x + y dt . So Γ( n)Γ(n-1) = B( n, n − 1) = ∫ ∞ 0 t n −1 1 + t dt . That integral can be evaluated by considering f( z ) = z n −1 1 + z and integrating around a keyhole contour with the branch cut for z n-1 along the positive real axis. Then ∫ ∞ 0 t n−1 1 + t dt + ∫ 0 ∞ ( te 2 πi ) n −1 1 + t dt = 2 πi Res[ f ( z ), = 2 πi ( e πi ) n − = − 2 πie πin which implies ∫ ∞ 0 t n −1 1 + t dt = −2 πie πin 1 − e 2 πin = π 2 i e πin − e − πin = π sinπn |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by sopstan(m): 9:36am On Jan 20, 2018 |
BunbleBee:the integral limit should be 0-1 since it's a beta function B(m,n) you try weldone |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by BunbleBee: 9:42am On Jan 20, 2018 |
. |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by MYSELF2018: 9:43am On Jan 20, 2018 |
sopstan:I can solve it for you. I am not with my android phone here, but I'l send it in the evening when I get back home. Please kindly send your whatsap number to praisejummy42@gmail.com |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by spartandude: 7:07am On Jan 21, 2018 |
which you championed Mrkumareze: |
Re: I'll Send A Card Worth #2000 If Anyone Can Solve These Problems by spartandude: 7:10am On Jan 21, 2018 |
Anus ofcourse sopstan: |
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