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A 0.62g sample of NaOH ,Na2CO3,and inert material was dissolved and required 30cm³ of HCl to reach the phenolphthalein in end point.Methyl orange was added and 6.50cm³ more HCl was required yo reach the methyl orange end point .If HCl was 0.24M.calculate the percentage of NaOH ,Na2CO3 in the sample

the




result is same as d amount

ozoono:
the




result is same as d amount

How sir?

using CaVa\CbVb= Na/Nb u got it

Won't you need the atomic number and atomic mass before the Cava/Nb I'm sorry I've forgotten this masterpiece

Buhari should come and answer this question, I dont like stress!

dingbang:
Buhari should come and answer this question, I dont like stress!

how you go know, its not firstbank related

dingbang:
Buhari should come and answer this question, I dont like stress!

Buhari na science student ?

You need to convert 0.62g to m

Hnn i remember those days.. If only we actually apply these things in real life

the only chemistry i love is the one between a man and wonan!

Herbephe1:
A 0.62g sample of NaOH ,Na2CO3,and
inert material was dissolved and required 30cm³ of HCl
to reach the phenolphthalein in end point.Methyl orange
was added and 6.50cm³ more HCl was required yo reach
the methyl orange end point .If HCl was 0.24M.calculate
the percentage of NaOH ,Na2CO3 in the sample

I hope it is not kind of late, I just passed by sha

picture

ayobama:
picture

picture

Sorry for coming late I found it so difficult to upload since...I just got through.

Final

Seen it

ayobama:
Final

I am now following you. Will need your expertise very soon.

Can I find you on hangout?

Can someone make the answer clearer on this page