₦airaland Forum

QUIZPAYZ
Three ladies met at a jewelry store. ‘Look here,’ said Susan to Amina, ‘I’ll give you six of my black stones for one of your white stone, and then you’ll have twice as many stones here as I’ve got.’
‘If that’s your way of doing business,’ said jumoke to Susan, ‘I’ll give you fourteen of my red stones for a white stone, and then you’ll have three times as many stones as I.’
‘Well, I’ll go better than that,’ said Amina to Jumoke; ‘I’ll give you four green stones for a white stone, and then you’ll have six times as many animals as I’ve got here.’
No doubt this was a very primitive way of bartering stones, but it is an interesting little puzzle to discover just how many stones Susan, Amina and Jumoke must have taken to the jewelry store.

PLEASE DROP ANSWERS ON THE THREAD AS THE FIRST IS TO GET THE CASH PRIZE OF #5000

kimbat:
QUIZPAYZ
Three ladies met at a jewelry store. ‘Look here,’ said Susan to Amina, ‘I’ll give you six of my black stones for one of your white stone, and then you’ll have twice as many stones here as I’ve got.’
‘If that’s your way of doing business,’ said jumoke to Susan, ‘I’ll give you fourteen of my red stones for a white stone, and then you’ll have three times as many stones as I.’
‘Well, I’ll go better than that,’ said Amina to Jumoke; ‘I’ll give you four green stones for a white stone, and then you’ll have six times as many animals as I’ve got here.’
No doubt this was a very primitive way of bartering stones, but it is an interesting little puzzle to discover just how many stones Susan, Amina and Jumoke must have taken to the jewelry store.

PLEASE DROP ANSWERS ON THE THREAD AS THE FIRST IS TO GET THE CASH PRIZE OF #5000

Getting equations from the expressions:
Let Susan's numbers of stones rep. S,
Amina's number of stones rep. A, and
Jumoke's number of stones J

Eqn 1: 2(S - 6 + 1) = A + 6 - 1

Eqn 2: 3(J - 14 + 1) = S + 14 - 1

Eqn 3: 6(A - 4 + 1) = J + 4 - 1

Solving these individually, the eqns become;
Eqn 1: 2S - A = 15,
Eqn 2: 3J - S = 52, and
Eqn 3: 6A - J = 21


Now solving together; we have;
A = 7, S = 11 and J = 21.

Therefore, Amina must have taken 7 stones to jewelry store, Susan must have taken 11, and Jumoke must have taken 21. There were thus 39 stones altogether.

kimbat:
QUIZPAYZ
Three ladies met at a jewelry store. ‘Look here,’ said Susan to Amina, ‘I’ll give you six of my black stones for one of your white stone, and then you’ll have twice as many stones here as I’ve got.’
‘If that’s your way of doing business,’ said jumoke to Susan, ‘I’ll give you fourteen of my red stones for a white stone, and then you’ll have three times as many stones as I.’
‘Well, I’ll go better than that,’ said Amina to Jumoke; ‘I’ll give you four green stones for a white stone, and then you’ll have six times as many animals as I’ve got here.’
No doubt this was a very primitive way of bartering stones, but it is an interesting little puzzle to discover just how many stones Susan, Amina and Jumoke must have taken to the jewelry store.

PLEASE DROP ANSWERS ON THE THREAD AS THE FIRST IS TO GET THE CASH PRIZE OF #5000

This is my detailed and explanatory calculation boss