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rossovu:
8 raised to power b x 2 raised to power 2b over 2 raised to power m

The question is:
8^b x 2^2b / 2^m

2^3b x 2^2b / 2^m

2^5b / 2^m

2^{5b - m}

From law of indices
let 2^5b

Continue from there, it is very simple

Kylekent59:
The question is:
8^b x 2^2b / 2^m

2^3b x 2^2b / 2^m

2^5b / 2^m

2^{5b - m}

From law of indices
let 2^5b

Continue from there, it is very simple

Thanks I really appreciate