₦airaland Forum

NDSMELODY:
bro! The internal resistor of the meter is in parallel with the 5ohm resistor,so u calculate the total resistor first and then use voltage divider rule to measure output voltage across 5ohm resistor since the meter was placed across it.....note you can labell 20ohm resistor as R1 and R total as R2....i stop here!

okay now I understand the question.

kolad59:
I am late sha, any other cct question...you can tag me

u can try this

Another one for you guys.........remember first person to comment will be awarded.

..Note; show ur workings clearly with phone number (MTN).

NDSMELODY:
Another one for you guys.........remember first person to comment will be awarded.

..Note; show ur workings clearly with phone number (MTN).

1/R = 1/R_b + 1/R_m
1/R = 1/5 + 1/2
1/R = (2+5)/10
R = 10/7 = 1.43 kΩ


V_o = {5/(25+1.43)} × 30
V_o = 5.68 V

Phone no: 09062114822 - MTN

NDSMELODY:
Here is my solution

you are wrong

Kareayo:
1/R = 1/R_b + 1/R_m 1/R = 1/5 + 1/2 1/R = (2+5)/10 R = 10/7 = 1.43 kΩ

V_o = {5/(25+1.43)} × 30 V_o = 5.68 V
Phone no: 09062114822 - MTN

wrong

Unknownartiste:
you are wrong

kindly post ur solution here sir