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Help With Tricky Math by creazor(m): 12:03am On Jan 11, 2014 |
I encountered a seemingly simple question a few months ago from a math lecturer. But when I attempted it, it was kind of tricky. The equation goes thus: 2^x = 4x. Solve for x. Pls d math gurus in d house, kindly help with workings to derive d solution. |
Re: Help With Tricky Math by tbmas(m): 12:25am On Jan 11, 2014 |
Wats d final ansa for x? Seems am arriving at smtin |
Re: Help With Tricky Math by Nobody: 12:27am On Jan 11, 2014 |
creazor: I encountered a seemingly simple question a few months ago from a math lecturer. But when I attempted it, it was kind of tricky. x = 4. Go to Nairaland Mathematics Clinic for more help |
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