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Nairaland Forum / Entertainment / Forum Games / Any Mathematician In The House...try Solving This Trick Question. (2815 Views)
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Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 9:48am On Jan 29, 2015 
If 4a=3b=a+b+c find a, b, c. Pls show ur workings clearly. 
Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 10:02am On Jan 29, 2015 
Legacy44: You teach mathematics in the school? 
Re: Any Mathematician In The House...try Solving This Trick Question. by derrick333(m): 10:03am On Jan 29, 2015 
Shud I use almighty formula ? 1 Like 
Re: Any Mathematician In The House...try Solving This Trick Question. by mideeniafe(f): 10:10am On Jan 29, 2015 
Hmmm..lemme try 4a=3b=a+b+c 3b=a+b+c4a x=a+b+c4a3b Using Almighty Formula x= b +/ square root (b2  4ac)/2a x= 1+/ ......... Wo....I don't know jor 
Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 10:13am On Jan 29, 2015 
Mathematical your attention is needed here. Do the needful. 
Re: Any Mathematician In The House...try Solving This Trick Question. by olusolaj(m): 10:26am On Jan 29, 2015 
a=1 b=4/3 c=5/3 I'm too busy to type the workings for now. I shall show it when I'm less busy 1 Like 
Re: Any Mathematician In The House...try Solving This Trick Question. by AdeniyiA(m): 10:30am On Jan 29, 2015 
check d workings in d pix posted ... a=3, b= 4, c=5 3 Likes

Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 10:33am On Jan 29, 2015 
U'all didnt get it right. Hint: a,b,c are all integers... Yes i teach maths...nysc stuff 
Re: Any Mathematician In The House...try Solving This Trick Question. by Mathematical(f): 10:35am On Jan 29, 2015 
Like I understand your illogical mathe 
Re: Any Mathematician In The House...try Solving This Trick Question. by AdeniyiA(m): 10:39am On Jan 29, 2015 
Legacy44:enable image on your phone and see d workings I posted 
Re: Any Mathematician In The House...try Solving This Trick Question. by Mathematical(f): 10:40am On Jan 29, 2015 
If abc re the integers. Then 4a = 3b b = 4a/3 2b = 5c b = 5c/2 
Re: Any Mathematician In The House...try Solving This Trick Question. by ArchEnemy(m): 11:48am On Jan 29, 2015 
mideeniafe:lol I join you in giving this up 
Re: Any Mathematician In The House...try Solving This Trick Question. by ArchEnemy(m): 11:52am On Jan 29, 2015 
AdeniyiA:all hail the Prof! 
Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 12:17pm On Jan 29, 2015 
AdeniyiA: sorry but ur workings is not clear...it doesn't explain ur answer 
Re: Any Mathematician In The House...try Solving This Trick Question. by Creamish(f): 1:17pm On Jan 29, 2015 
Legacy44: But his answers are right... 3 Likes 
Re: Any Mathematician In The House...try Solving This Trick Question. by AdeniyiA(m): 1:23pm On Jan 29, 2015 
Legacy44:you mean my approach is not clear to you, it's a right approach and the answers are correct. You can request for further explanation if u wish. 1 Like 
Re: Any Mathematician In The House...try Solving This Trick Question. by AdeniyiA(m): 1:25pm On Jan 29, 2015 
ArchEnemy:I wan thief am...? 
Re: Any Mathematician In The House...try Solving This Trick Question. by ArchEnemy(m): 1:33pm On Jan 29, 2015 
AdeniyiA:ohkay Sir 
Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 2:06pm On Jan 29, 2015 
Legacy44:AdeniyiA solved it already. 
Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 2:12pm On Jan 29, 2015 
AdeniyiA: 
Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 5:37pm On Jan 29, 2015 
AdeniyiA: yeah...i need further explanation. I understand the following deductions: a/c=3/5, c/b=5/4, a/b=3/4. But how did the above translate to a=3, b=4, c=5 
Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 5:42pm On Jan 29, 2015 
olusolaj: Pls show ur working 
Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 5:45pm On Jan 29, 2015 
AdeniyiA: yeah...i need further explanation. I understand the following deductions: a/c=3/5, c/b=5/4, a/b=3/4. But how did the above translate to a=3, b=4, c=5 because it seems like u jus guessed what should have been there...olusolaj also apparently got it 'right' cos it fitted perfectly to the question. His answer was a=1, b=4/3, C=5/3. Pls clear workings will justify ur answer not assumptions 
Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 5:57pm On Jan 29, 2015 
AdeniyiA: yeah...i need further explanation. I understand the following deductions: a/c=3/5, c/b=5/4, a/b=3/4. But how did the above translate to a=3, b=4, c=5 because it seems like u jus guessed what should have been there...olusolaj also apparently got it 'right' cos it fitted perfectly to the question. His answer was a=1, b=4/3, C=5/3. I can also say a=3/2, b=2, c=5/2 AND THE ANSWER WILL BE JUSTIFIABLE....it still doesn't make it right. Pls clear workings will justify ur answer not assumptions 
Re: Any Mathematician In The House...try Solving This Trick Question. by AdeniyiA(m): 6:25pm On Jan 29, 2015 
Legacy44: I neither deduce nor assume. my answers were simply arrived at through simple ratio relation. If u break down olusolaj 's answers, they all come down to 3,4 & 5 ,by mere multiplying through by 3. 1 Like 
Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 6:51pm On Jan 29, 2015 
AdeniyiA: U didnt answer my question...i said explain the last part i highlighted frm ur calculations 
Re: Any Mathematician In The House...try Solving This Trick Question. by PuntGenius: 8:38pm On Jan 29, 2015 
I got a=0,b=0 and c=0 
Re: Any Mathematician In The House...try Solving This Trick Question. by AdeniyiA(m): 8:55pm On Jan 29, 2015 
Legacy44:a/c=3/5, c/b=5/4, a/b=3/4. simple ratio my dear. Three variables nd three numbers with at least a variable appearing in two places d same . You can even check /work it backwards. 
Re: Any Mathematician In The House...try Solving This Trick Question. by tundeayo2020: 11:29pm On Jan 29, 2015 
hmm solving Modified... A=0, b=0, c=0. Or a=6, b=8, c=10. Op is it correct? 
Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 12:02am On Jan 30, 2015 
tundeayo2020: yh 
Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 7:46am On Jan 30, 2015 
tundeayo2020: Legacy44: Show the working lets see. 
Re: Any Mathematician In The House...try Solving This Trick Question. by PuntGenius: 8:35am On Jan 30, 2015 
I got a=0, b=0 and c=0 from my workings, but 3, 4 and 5 or 6, 4 and 8vare also correct but I can't seem to work that out 
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