₦airaland Forum

if we have an empty measuring cylinder. of mass M, radius r and height H placed on a table, and a fluid/liquid of density P is poured into it,
at what height will the fluid be at when the cylinder is most stable?

in other words,

how high does the fluid have to go in the cylinder for the center of gravity of the whole apparatus to be at it's lowest?


just another problem to think about.

Mg+pie r^2H+p=0 Mg+22/7r^2H+p=0 7mg+22r^2H+7p=0 22r^2H=-7p-7mg H=-7(p+g)/22r^2.

*yawn*

Teempakguy:
if we have an empty measuring cylinder. of mass M, radius r and height H placed on a table, and a fluid/liquid of density P is poured into it,
at what height will the fluid be at when the cylinder is most stable?

in other words,

how high does the fluid have to go in the cylinder for the center of gravity of the whole apparatus to be at it's lowest?


just another problem to think about.

How does this put garri on the table? Lets work on problems of national importance and relevance, please.

holocron:
How does this put garri on the table? Lets work on problems of national importance and relevance, please.

Hmmn,

Deboxoxo:
Mg+pie r^2H+p=0
Mg+22/7r^2H+p=0
7mg+22r^2H+7p=0
22r^2H=-7p-7mg
H=-7(p+g)/22r^2.

the result is negative . . . how can one have a negative height?

Teempakguy:
if we have an empty measuring cylinder. of mass M, radius r and height H placed on a table, and a fluid/liquid of density P is poured into it,
at what height will the fluid be at when the cylinder is most stable?
in other words,
how high does the fluid have to go in the cylinder for the center of gravity of the whole apparatus to be at it's lowest?
just another problem to think about.

The smallest volume of liquid possible to have the smallest depth possible