Pls help me with the solution of this question.

A fisherman caught 15 kg of fish on Monday and 23 kg on Tuesday. On Tuesday there were twice as many fish on Monday, but their average mass was 1/8 kg less. How many fish did the fisherman catch on Monday.

28.

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Solahted:
Pls help me with the solution of this question.

A fisherman caught 15 kg of fish on Monday and 23 kg on Tuesday. On Tuesday there were twice as many fish on Monday, but their average mass was 1/8 kg less. How many fish did the fisherman catch on Monday.

Solahted:
Pls help me with the solution of this question.

A fisherman caught 15 kg of fish on Monday and 23 kg on Tuesday. On Tuesday there were twice as many fish on Monday, but their average mass was 1/8 kg less. How many fish did the fisherman catch on Monday.

Answer === 28 fish was caught on Monday
Working :
Let the number of fish caught on Monday be x
Therefore, number of fish caught on Tuesday will be 2x
Total mass of all fish caught on Monday = 15kg, Average mass of fish caught on Monday = Total/count = 15/x
Average mass of fish caught on Tuesday = Total/count = 23/2x
It is said that the average mass of Tuesday's catch is 1/8kg less than that of Monday's catch, Therefore,
15/x - 23/2x = 1/8
Find the LCM and collecting like terms gives:
(30-23)/2x = 1/8 which gives: 7/2x = 1/8
==> 2x = 56, Therefore x = 28.
Recall that x represents the number of fish caught on Monday.
Finally, The number of fish caught on Monday = 28 (Q.E.D)

Thank you for providing solution to this question.