₦airaland Forum

I need a genius to help solve this physics problem

When you put Ice in water 3 process will occur: 1. The ice which is solid will melt that is convert to liquid 2. The melted ice which is now water at o degree celsius will gain temperature and 3. The water in which you put the ice will lose temp. From these analysis am very sure my final temp for the mixture will be less than 50.
Solution
heat gain by ice= heat loss by water . Give laten heat of fussion of ice = 3.34*10^5 and heat capacity of water is 4200.
Ml+mc(x-0)=mc(50-x)
note convert all gram to kilogram.
0.15*3.34*10^5+0.15*4200*(x-0)=0.3*4200*(50-x)
when you solve for x you will get 6.83 degree celsius.