Since 1cm'cube of water weighs 1gcm'cube we have dat;
mass of cold water in d calorimetre m1=50g
mass of hot water m2=45g
mass of calorimetre and stirrer Mo=73g

initial temperature of water teta nll=32degree c
temperature of hot water teta1=60c

temperature of mixure teta2=36c

assume that the SHC Of water=4200 jkg^-1k^-1 and dat of copper =380 jkg^-1k1-

(1)Calculate heat gained by the cold water and heat gained by d calorimeter stirrer
(2)calculate d total heat gained
(3)calculate heat lost by hot water
(4)by how much does the result from (2) for the total heat gained differ from (3).....................Thank in ad. And GOD BLESS.