Write a function named collatz() that has one parameter named number. If number is even, then collatz() should print number // 2 and return this value. If number is odd, then collatz() should print and return 3 * number + 1. Then write a program that lets the user type in an integer and that keeps calling collatz() on that number until the function returns the value 1. (Amazingly enough, this sequence actually works for any integer—sooner or later, using this sequence, you’ll arrive at 1! Even mathematicians aren’t sure why. Your program is exploring what’s called the Collatz sequence, sometimes called “the simplest impossible math problem.”) Remember to convert the return value from input() to an integer with the int() function; otherwise, it will be a string value. Hint: An integer number is even if number % 2 == 0, and it’s odd if number % 2 == 1.

@SPLENDID25
What have you coded so far?. Are you experiencing some issues or what?

It hasn't been proved that it works for all positive integers.

What's the problem though? The problem looks straightforward.

stanliwise:
@SPLENDID25
What have you coded so far?. Are you experiencing some issues or what?

I am actually a beginner. its actually a practice problem. I was able to write the function, but unable to write the part that should call the function and ask for an input provided the returned value isn't 1. I need hints from seniors.

Najdorf:
It hasn't been proved that it works for all positive integers.

What's the problem though? The problem looks straightforward.

I need hints on how to go about the problem. I have been thinking, for the past three days now.

SPLENDID25:
I am actually a beginner. its actually a practice problem. I was able to write the function, but unable to write the part that should call the function and ask for an input provided the returned value isn't 1. I need hints from seniors.

what language are you using??

SPLENDID25:
Write a function named collatz() that has one parameter named number. If number is even, then collatz() should print number // 2 and return this value. If number is odd, then collatz() should print and return 3 * number + 1. Then write a program that lets the user type in an integer and that keeps calling collatz() on that number until the function returns the value 1. (Amazingly enough, this sequence actually works for any integer—sooner or later, using this sequence, you’ll arrive at 1! Even mathematicians aren’t sure why. Your program is exploring what’s called the Collatz sequence, sometimes called “the simplest impossible math problem.”) Remember to convert the return value from input() to an integer with the int() function; otherwise, it will be a string value. Hint: An integer number is even if number % 2 == 0, and it’s odd if number % 2 == 1.

I remember this from automate the boring stuff with Python, I couldn't solve it then let me try it now.

SPLENDID25:
I need hints on how to go about the problem. I have been thinking, for the past three days now.

I will give you a hint, the best to use for this practice is recursive function. It calls itself. Please read more on it.

def collatz ():
if number % 2 == 0:
return number // 2
elif number % 2 == 1:
return 3 * number + 1

number = int(input())

while number != 1:
number = collatz ()
print(number)

sorry for d indentation
I have answer dis question b4,

before u ask question use the search bar to see if such question has not been asked before

join www.africonn.com
I hope this helps

stanliwise:
what language are you using??

Python

Taofeekdboy:

I will give you a hint, the best to use for this practice is recursive function. It calls itself. Please read more on it.

okay I will. thanks

codeigniter:
def collatz ():
if number % 2 == 0:
return number // 2
elif number % 2 == 1:
return 3 * number + 1

number = int(input())

while number != 1:
number = collatz ()
print(number)

sorry for d indentation
I have answer dis question b4,

before u ask question use the search bar to see if such question has not been asked before

join www.africonn.com
I hope this helps

Sir, every input returned 1 and the program ends.

SPLENDID25:
Python

use the input() functionality.
To get integer you can use:
int(input(“input a number”))

Just store it a variable and you can attach it to a while loop to keep calling it.

stanliwise:

use the input() functionality.
To get integer you can use:
int(input(“input a number”))

Just store it a variable and you can attach it to a while loop to keep calling it.

def collatz (number):
 	if number % 2 == 0:
 		return number // 2
 	else:
 		return 3 * number + 1
 number = int(input())

I used the while loop, followed by invoking the function. all it did was to continue printing the returned value.

SPLENDID25:

def collatz (number):
 	if number % 2 == 0:
 		return number // 2
 	else:
 		return 3 * number + 1
 number = int(input())

I used the while loop, followed by invoking the function. all it did was to continue printing the returned value.

When is your while loop suppose to terminate?

SPLENDID25:
Sir, every input returned 1 and the program ends.

is that not the problem u want to solve

stanliwise:

When is your while loop suppose to terminate?

when the returned value equals 1.

SPLENDID25:
when the returned value equals 1.

if it fails to return 1 then it means your loop is infinite.
Try to input value that could make your function return 1

codeigniter:


is that not the problem u want to solve

I mean, using your code. Every input returned 1 and the program terminates. its not supposed to be that way.

stanliwise:
if it fails to return 1 then it means your loop is infinite.
Try to input value that could make your function return 1

def collatz (number):
	if number % 2 == 0:
		return number // 2
	else:
		return 3 * number + 1
number = int(input())
collatz (number)
print (collatz (number))
while collatz (number) != 1:
	print (collatz (number))

the program above did with 2 as input, but if the returned value isn't 1, it prints the returned value infinitely.

stanliwise:
if it fails to return 1 then it means your loop is infinite.
Try to input value that could make your function return 1

Going farther than this coding exercise, this is a popular unsolved math problem. There is no known way to check if a number will reach 1. But there is also no known counterexample of a number that does not eventually reach 1.

codeigniter:
def collatz ():
if number % 2 == 0:
return number // 2
elif number % 2 == 1:
return 3 * number + 1

number = int(input())

while number != 1:
number = collatz ()
print(number)

sorry for d indentation
I have answer dis question b4,

before u ask question use the search bar to see if such question has not been asked before

join www.africonn.com
I hope this helps

Taofeekdboy:

I will give you a hint, the best to use for this practice is recursive function. It calls itself. Please read more on it.

saheedniyi22:


I remember this from automate the boring stuff with Python, I couldn't solve it then let me try it now.

Najdorf:
It hasn't been proved that it works for all positive integers.

What's the problem though? The problem looks straightforward.

stanliwise:
@SPLENDID25
What have you coded so far?. Are you experiencing some issues or what?

I successfully written the program. Thanks to everyone for his or her contributions.